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PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364678 A clock hung on a wall has marks instead of numerals on its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time $7 : 10$ . Then, the time on the clock is

1

7 : 10

2

4 : 50

3

5 : 40

4

10 : 7

Explanation:

In a plane mirror, the image undergoes depth inversion, hence the time on the image is as much ahead of $12 h$ and $0 min$ as the time on actual clock is behind $12 h$ and $0 min$
Time on the image clock $= 7 h$ and $10 min$
Time on the actual clock
$= (12 h a n d 0 min) - (7 h a n d 10 min)$
$= 4 h$ and $50 min$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364679 Statement A :
A ray of light incident along the normal to the plane mirror retraces its path after reflection from the mirror.
Statement B :
A ray of light along the normal has angle of incidence as $\frac{π}{2}$ and hence, it retraces its own path after reflection from mirror.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both Statements are correct.

4 Both Statements are incorrect.

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364680 An unnumbered wall clock shows time $04 : 25$ : 37 , where $1^{st}$ term represents hours, $2^{nd}$ represents minutes and the last term represents seconds. What time will its image in a plane mirror show.

1

08 : 35 : 23

2

07 : 35 : 23

3

07 : 34 : 23

4 None of these

Explanation:

Let time in object clock be $T_{1} &$ time in image clock be $T_{2}$ then,
$\begin{aligned} T_{1} + T_{2} = 12 : 00 : 00 \\ 4 : 25 : 37 + T_{2} = 12 : 00 : 00 \\ T_{2} = 07 : 34 : 23 . \end{aligned}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364681 When a convergent beam of light is incident on a plane mirror, the image formed is

1 Upright and virtual

2 Upright and real

3 Inverted and real

4 Inverted and virtual

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364682 The power of a plane mirror is

1 0

2

4 D

3

2 D

4

\infty

Explanation:

$f = \frac{R}{2} = \infty \Rightarrow P = \frac{1}{f} = 0$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364678 A clock hung on a wall has marks instead of numerals on its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time $7 : 10$ . Then, the time on the clock is

1

7 : 10

2

4 : 50

3

5 : 40

4

10 : 7

Explanation:

In a plane mirror, the image undergoes depth inversion, hence the time on the image is as much ahead of $12 h$ and $0 min$ as the time on actual clock is behind $12 h$ and $0 min$
Time on the image clock $= 7 h$ and $10 min$
Time on the actual clock
$= (12 h a n d 0 min) - (7 h a n d 10 min)$
$= 4 h$ and $50 min$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364679 Statement A :
A ray of light incident along the normal to the plane mirror retraces its path after reflection from the mirror.
Statement B :
A ray of light along the normal has angle of incidence as $\frac{π}{2}$ and hence, it retraces its own path after reflection from mirror.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both Statements are correct.

4 Both Statements are incorrect.

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364680 An unnumbered wall clock shows time $04 : 25$ : 37 , where $1^{st}$ term represents hours, $2^{nd}$ represents minutes and the last term represents seconds. What time will its image in a plane mirror show.

1

08 : 35 : 23

2

07 : 35 : 23

3

07 : 34 : 23

4 None of these

Explanation:

Let time in object clock be $T_{1} &$ time in image clock be $T_{2}$ then,
$\begin{aligned} T_{1} + T_{2} = 12 : 00 : 00 \\ 4 : 25 : 37 + T_{2} = 12 : 00 : 00 \\ T_{2} = 07 : 34 : 23 . \end{aligned}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364681 When a convergent beam of light is incident on a plane mirror, the image formed is

1 Upright and virtual

2 Upright and real

3 Inverted and real

4 Inverted and virtual

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364682 The power of a plane mirror is

1 0

2

4 D

3

2 D

4

\infty

Explanation:

$f = \frac{R}{2} = \infty \Rightarrow P = \frac{1}{f} = 0$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364678 A clock hung on a wall has marks instead of numerals on its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time $7 : 10$ . Then, the time on the clock is

1

7 : 10

2

4 : 50

3

5 : 40

4

10 : 7

Explanation:

In a plane mirror, the image undergoes depth inversion, hence the time on the image is as much ahead of $12 h$ and $0 min$ as the time on actual clock is behind $12 h$ and $0 min$
Time on the image clock $= 7 h$ and $10 min$
Time on the actual clock
$= (12 h a n d 0 min) - (7 h a n d 10 min)$
$= 4 h$ and $50 min$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364679 Statement A :
A ray of light incident along the normal to the plane mirror retraces its path after reflection from the mirror.
Statement B :
A ray of light along the normal has angle of incidence as $\frac{π}{2}$ and hence, it retraces its own path after reflection from mirror.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both Statements are correct.

4 Both Statements are incorrect.

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364680 An unnumbered wall clock shows time $04 : 25$ : 37 , where $1^{st}$ term represents hours, $2^{nd}$ represents minutes and the last term represents seconds. What time will its image in a plane mirror show.

1

08 : 35 : 23

2

07 : 35 : 23

3

07 : 34 : 23

4 None of these

Explanation:

Let time in object clock be $T_{1} &$ time in image clock be $T_{2}$ then,
$\begin{aligned} T_{1} + T_{2} = 12 : 00 : 00 \\ 4 : 25 : 37 + T_{2} = 12 : 00 : 00 \\ T_{2} = 07 : 34 : 23 . \end{aligned}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364681 When a convergent beam of light is incident on a plane mirror, the image formed is

1 Upright and virtual

2 Upright and real

3 Inverted and real

4 Inverted and virtual

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364682 The power of a plane mirror is

1 0

2

4 D

3

2 D

4

\infty

Explanation:

$f = \frac{R}{2} = \infty \Rightarrow P = \frac{1}{f} = 0$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364678 A clock hung on a wall has marks instead of numerals on its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time $7 : 10$ . Then, the time on the clock is

1

7 : 10

2

4 : 50

3

5 : 40

4

10 : 7

Explanation:

In a plane mirror, the image undergoes depth inversion, hence the time on the image is as much ahead of $12 h$ and $0 min$ as the time on actual clock is behind $12 h$ and $0 min$
Time on the image clock $= 7 h$ and $10 min$
Time on the actual clock
$= (12 h a n d 0 min) - (7 h a n d 10 min)$
$= 4 h$ and $50 min$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364679 Statement A :
A ray of light incident along the normal to the plane mirror retraces its path after reflection from the mirror.
Statement B :
A ray of light along the normal has angle of incidence as $\frac{π}{2}$ and hence, it retraces its own path after reflection from mirror.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both Statements are correct.

4 Both Statements are incorrect.

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364680 An unnumbered wall clock shows time $04 : 25$ : 37 , where $1^{st}$ term represents hours, $2^{nd}$ represents minutes and the last term represents seconds. What time will its image in a plane mirror show.

1

08 : 35 : 23

2

07 : 35 : 23

3

07 : 34 : 23

4 None of these

Explanation:

Let time in object clock be $T_{1} &$ time in image clock be $T_{2}$ then,
$\begin{aligned} T_{1} + T_{2} = 12 : 00 : 00 \\ 4 : 25 : 37 + T_{2} = 12 : 00 : 00 \\ T_{2} = 07 : 34 : 23 . \end{aligned}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364681 When a convergent beam of light is incident on a plane mirror, the image formed is

1 Upright and virtual

2 Upright and real

3 Inverted and real

4 Inverted and virtual

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364682 The power of a plane mirror is

1 0

2

4 D

3

2 D

4

\infty

Explanation:

$f = \frac{R}{2} = \infty \Rightarrow P = \frac{1}{f} = 0$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364678 A clock hung on a wall has marks instead of numerals on its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time $7 : 10$ . Then, the time on the clock is

1

7 : 10

2

4 : 50

3

5 : 40

4

10 : 7

Explanation:

In a plane mirror, the image undergoes depth inversion, hence the time on the image is as much ahead of $12 h$ and $0 min$ as the time on actual clock is behind $12 h$ and $0 min$
Time on the image clock $= 7 h$ and $10 min$
Time on the actual clock
$= (12 h a n d 0 min) - (7 h a n d 10 min)$
$= 4 h$ and $50 min$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364679 Statement A :
A ray of light incident along the normal to the plane mirror retraces its path after reflection from the mirror.
Statement B :
A ray of light along the normal has angle of incidence as $\frac{π}{2}$ and hence, it retraces its own path after reflection from mirror.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both Statements are correct.

4 Both Statements are incorrect.

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364680 An unnumbered wall clock shows time $04 : 25$ : 37 , where $1^{st}$ term represents hours, $2^{nd}$ represents minutes and the last term represents seconds. What time will its image in a plane mirror show.

1

08 : 35 : 23

2

07 : 35 : 23

3

07 : 34 : 23

4 None of these

Explanation:

Let time in object clock be $T_{1} &$ time in image clock be $T_{2}$ then,
$\begin{aligned} T_{1} + T_{2} = 12 : 00 : 00 \\ 4 : 25 : 37 + T_{2} = 12 : 00 : 00 \\ T_{2} = 07 : 34 : 23 . \end{aligned}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364681 When a convergent beam of light is incident on a plane mirror, the image formed is

1 Upright and virtual

2 Upright and real

3 Inverted and real

4 Inverted and virtual

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

364682 The power of a plane mirror is

1 0

2

4 D

3

2 D

4

\infty

Explanation:

$f = \frac{R}{2} = \infty \Rightarrow P = \frac{1}{f} = 0$

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