364670
Which of the following is not the case with image formed by a plane mirror?
1 It is erect
2 It is virtual
3 It is diminished
4 It is at the same distance as the object
Explanation:
\(m = 1\) for a plane mirror. So image formed is not diminished.
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364671
A person's eye is at a height of \(1.5\,m\) . He stands infront of a \(0.3\,m\) long plane mirror which is \(0.8\,m\) above the ground. The length of the image he sees of himself is
1 \(1.5\,m\)
2 \(1.0\,m\)
3 \(0.8\,m\)
4 \(0.6\,m\)
Explanation:
Only that portion of body will be visible in mirror from which light strikes the mirror and enters into the eyes, and that portion is \(ED\) So, \({E D=A D-A E=1.4-.8=0.6 m}\)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364672
A clock hung on a wall has marks instead of numeralsn its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time 7.10. Then, the time on the clock is:
1 \({\rm{4:50}}\)
2 \({\rm{7:10}}\)
3 \({\rm{10:7}}\)
4 \({\rm{5:40}}\)
Explanation:
Time on the actual clock = \(7\;h\) and \(10\;\min \).
Time in the image is = (12 h and 0 min) - (7 h and 10 min) = 4 h and 50 min.
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364673
A plane mirror reflects pencil of light to form a real image then the pencil of light incident on the mirror is
1 parallel
2 convergent
3 divergent
4 None of these
Explanation:
When convergent beam incident on a plane mirror, then mirror forms real image, for a virtual object.
364670
Which of the following is not the case with image formed by a plane mirror?
1 It is erect
2 It is virtual
3 It is diminished
4 It is at the same distance as the object
Explanation:
\(m = 1\) for a plane mirror. So image formed is not diminished.
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364671
A person's eye is at a height of \(1.5\,m\) . He stands infront of a \(0.3\,m\) long plane mirror which is \(0.8\,m\) above the ground. The length of the image he sees of himself is
1 \(1.5\,m\)
2 \(1.0\,m\)
3 \(0.8\,m\)
4 \(0.6\,m\)
Explanation:
Only that portion of body will be visible in mirror from which light strikes the mirror and enters into the eyes, and that portion is \(ED\) So, \({E D=A D-A E=1.4-.8=0.6 m}\)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364672
A clock hung on a wall has marks instead of numeralsn its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time 7.10. Then, the time on the clock is:
1 \({\rm{4:50}}\)
2 \({\rm{7:10}}\)
3 \({\rm{10:7}}\)
4 \({\rm{5:40}}\)
Explanation:
Time on the actual clock = \(7\;h\) and \(10\;\min \).
Time in the image is = (12 h and 0 min) - (7 h and 10 min) = 4 h and 50 min.
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364673
A plane mirror reflects pencil of light to form a real image then the pencil of light incident on the mirror is
1 parallel
2 convergent
3 divergent
4 None of these
Explanation:
When convergent beam incident on a plane mirror, then mirror forms real image, for a virtual object.
364670
Which of the following is not the case with image formed by a plane mirror?
1 It is erect
2 It is virtual
3 It is diminished
4 It is at the same distance as the object
Explanation:
\(m = 1\) for a plane mirror. So image formed is not diminished.
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364671
A person's eye is at a height of \(1.5\,m\) . He stands infront of a \(0.3\,m\) long plane mirror which is \(0.8\,m\) above the ground. The length of the image he sees of himself is
1 \(1.5\,m\)
2 \(1.0\,m\)
3 \(0.8\,m\)
4 \(0.6\,m\)
Explanation:
Only that portion of body will be visible in mirror from which light strikes the mirror and enters into the eyes, and that portion is \(ED\) So, \({E D=A D-A E=1.4-.8=0.6 m}\)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364672
A clock hung on a wall has marks instead of numeralsn its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time 7.10. Then, the time on the clock is:
1 \({\rm{4:50}}\)
2 \({\rm{7:10}}\)
3 \({\rm{10:7}}\)
4 \({\rm{5:40}}\)
Explanation:
Time on the actual clock = \(7\;h\) and \(10\;\min \).
Time in the image is = (12 h and 0 min) - (7 h and 10 min) = 4 h and 50 min.
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364673
A plane mirror reflects pencil of light to form a real image then the pencil of light incident on the mirror is
1 parallel
2 convergent
3 divergent
4 None of these
Explanation:
When convergent beam incident on a plane mirror, then mirror forms real image, for a virtual object.
364670
Which of the following is not the case with image formed by a plane mirror?
1 It is erect
2 It is virtual
3 It is diminished
4 It is at the same distance as the object
Explanation:
\(m = 1\) for a plane mirror. So image formed is not diminished.
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364671
A person's eye is at a height of \(1.5\,m\) . He stands infront of a \(0.3\,m\) long plane mirror which is \(0.8\,m\) above the ground. The length of the image he sees of himself is
1 \(1.5\,m\)
2 \(1.0\,m\)
3 \(0.8\,m\)
4 \(0.6\,m\)
Explanation:
Only that portion of body will be visible in mirror from which light strikes the mirror and enters into the eyes, and that portion is \(ED\) So, \({E D=A D-A E=1.4-.8=0.6 m}\)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364672
A clock hung on a wall has marks instead of numeralsn its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time 7.10. Then, the time on the clock is:
1 \({\rm{4:50}}\)
2 \({\rm{7:10}}\)
3 \({\rm{10:7}}\)
4 \({\rm{5:40}}\)
Explanation:
Time on the actual clock = \(7\;h\) and \(10\;\min \).
Time in the image is = (12 h and 0 min) - (7 h and 10 min) = 4 h and 50 min.
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364673
A plane mirror reflects pencil of light to form a real image then the pencil of light incident on the mirror is
1 parallel
2 convergent
3 divergent
4 None of these
Explanation:
When convergent beam incident on a plane mirror, then mirror forms real image, for a virtual object.
