Damped Simple Harmonic Motion
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PHXI14:OSCILLATIONS

364283 A simple pendulum performs simple harmonic motion about \(x=0\) with an amplitude \(a\) and time period \(T\). The speed of the pendulum at \(x=a / 2\) will be

1 \(\dfrac{\pi a \sqrt{3}}{2 T}\)
2 \(\dfrac{\pi a}{T}\)
3 \(\dfrac{3 \pi^{2} a}{T}\)
4 \(\dfrac{\pi a \sqrt{3}}{T}\)
PHXI14:OSCILLATIONS

364284 A particle performs linear SHM at a particular instant, velocity of the particle is ' \(u\) ' and acceleration is ' \(\alpha\) ' while at another instant velocity is ' \(v\) ' and acceleration is \(\beta(0 < \alpha < \beta)\). The distance between the two positions is

1 \(\dfrac{u^{2}-v^{2}}{\alpha+\beta}\)
2 \(\dfrac{u^{2}+v^{2}}{\alpha+\beta}\)
3 \(\dfrac{u^{2}-v^{2}}{\alpha-\beta}\)
4 \(\dfrac{u^{2}+v^{2}}{\alpha-\beta}\)
MHTCET - 2017
PHXI14:OSCILLATIONS

364285 Assertion :
In extreme position of a particle executing S.H.M., both velocity and acceleration are zero.
Reason :
In S.H.M., acceleration always acts towards mean position.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI14:OSCILLATIONS

364286 A particle executes linear simple harmonic motion with an amplitude of \(2\;cm\). When the particle is at \(1\;cm\) from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

1 \(2 \pi \sqrt{3}\)
2 \(\dfrac{1}{2 \pi \sqrt{3}}\)
3 \(\dfrac{\sqrt{3}}{2 \pi}\)
4 \(\dfrac{2 \pi}{\sqrt{3}}\)
PHXI14:OSCILLATIONS

364287 An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is \(15\;cm{\rm{/}}\sec \) and the period is \(628\;ms\). The amplitude of the motion in centimeters is

1 3.0
2 2.0
3 1.5
4 1.0
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PHXI14:OSCILLATIONS

364283 A simple pendulum performs simple harmonic motion about \(x=0\) with an amplitude \(a\) and time period \(T\). The speed of the pendulum at \(x=a / 2\) will be

1 \(\dfrac{\pi a \sqrt{3}}{2 T}\)
2 \(\dfrac{\pi a}{T}\)
3 \(\dfrac{3 \pi^{2} a}{T}\)
4 \(\dfrac{\pi a \sqrt{3}}{T}\)
PHXI14:OSCILLATIONS

364284 A particle performs linear SHM at a particular instant, velocity of the particle is ' \(u\) ' and acceleration is ' \(\alpha\) ' while at another instant velocity is ' \(v\) ' and acceleration is \(\beta(0 < \alpha < \beta)\). The distance between the two positions is

1 \(\dfrac{u^{2}-v^{2}}{\alpha+\beta}\)
2 \(\dfrac{u^{2}+v^{2}}{\alpha+\beta}\)
3 \(\dfrac{u^{2}-v^{2}}{\alpha-\beta}\)
4 \(\dfrac{u^{2}+v^{2}}{\alpha-\beta}\)
MHTCET - 2017
PHXI14:OSCILLATIONS

364285 Assertion :
In extreme position of a particle executing S.H.M., both velocity and acceleration are zero.
Reason :
In S.H.M., acceleration always acts towards mean position.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI14:OSCILLATIONS

364286 A particle executes linear simple harmonic motion with an amplitude of \(2\;cm\). When the particle is at \(1\;cm\) from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

1 \(2 \pi \sqrt{3}\)
2 \(\dfrac{1}{2 \pi \sqrt{3}}\)
3 \(\dfrac{\sqrt{3}}{2 \pi}\)
4 \(\dfrac{2 \pi}{\sqrt{3}}\)
PHXI14:OSCILLATIONS

364287 An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is \(15\;cm{\rm{/}}\sec \) and the period is \(628\;ms\). The amplitude of the motion in centimeters is

1 3.0
2 2.0
3 1.5
4 1.0
For More Updates join with Us
PHXI14:OSCILLATIONS

364283 A simple pendulum performs simple harmonic motion about \(x=0\) with an amplitude \(a\) and time period \(T\). The speed of the pendulum at \(x=a / 2\) will be

1 \(\dfrac{\pi a \sqrt{3}}{2 T}\)
2 \(\dfrac{\pi a}{T}\)
3 \(\dfrac{3 \pi^{2} a}{T}\)
4 \(\dfrac{\pi a \sqrt{3}}{T}\)
PHXI14:OSCILLATIONS

364284 A particle performs linear SHM at a particular instant, velocity of the particle is ' \(u\) ' and acceleration is ' \(\alpha\) ' while at another instant velocity is ' \(v\) ' and acceleration is \(\beta(0 < \alpha < \beta)\). The distance between the two positions is

1 \(\dfrac{u^{2}-v^{2}}{\alpha+\beta}\)
2 \(\dfrac{u^{2}+v^{2}}{\alpha+\beta}\)
3 \(\dfrac{u^{2}-v^{2}}{\alpha-\beta}\)
4 \(\dfrac{u^{2}+v^{2}}{\alpha-\beta}\)
MHTCET - 2017
PHXI14:OSCILLATIONS

364285 Assertion :
In extreme position of a particle executing S.H.M., both velocity and acceleration are zero.
Reason :
In S.H.M., acceleration always acts towards mean position.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI14:OSCILLATIONS

364286 A particle executes linear simple harmonic motion with an amplitude of \(2\;cm\). When the particle is at \(1\;cm\) from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

1 \(2 \pi \sqrt{3}\)
2 \(\dfrac{1}{2 \pi \sqrt{3}}\)
3 \(\dfrac{\sqrt{3}}{2 \pi}\)
4 \(\dfrac{2 \pi}{\sqrt{3}}\)
PHXI14:OSCILLATIONS

364287 An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is \(15\;cm{\rm{/}}\sec \) and the period is \(628\;ms\). The amplitude of the motion in centimeters is

1 3.0
2 2.0
3 1.5
4 1.0
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PHXI14:OSCILLATIONS

364283 A simple pendulum performs simple harmonic motion about \(x=0\) with an amplitude \(a\) and time period \(T\). The speed of the pendulum at \(x=a / 2\) will be

1 \(\dfrac{\pi a \sqrt{3}}{2 T}\)
2 \(\dfrac{\pi a}{T}\)
3 \(\dfrac{3 \pi^{2} a}{T}\)
4 \(\dfrac{\pi a \sqrt{3}}{T}\)
PHXI14:OSCILLATIONS

364284 A particle performs linear SHM at a particular instant, velocity of the particle is ' \(u\) ' and acceleration is ' \(\alpha\) ' while at another instant velocity is ' \(v\) ' and acceleration is \(\beta(0 < \alpha < \beta)\). The distance between the two positions is

1 \(\dfrac{u^{2}-v^{2}}{\alpha+\beta}\)
2 \(\dfrac{u^{2}+v^{2}}{\alpha+\beta}\)
3 \(\dfrac{u^{2}-v^{2}}{\alpha-\beta}\)
4 \(\dfrac{u^{2}+v^{2}}{\alpha-\beta}\)
MHTCET - 2017
PHXI14:OSCILLATIONS

364285 Assertion :
In extreme position of a particle executing S.H.M., both velocity and acceleration are zero.
Reason :
In S.H.M., acceleration always acts towards mean position.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI14:OSCILLATIONS

364286 A particle executes linear simple harmonic motion with an amplitude of \(2\;cm\). When the particle is at \(1\;cm\) from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

1 \(2 \pi \sqrt{3}\)
2 \(\dfrac{1}{2 \pi \sqrt{3}}\)
3 \(\dfrac{\sqrt{3}}{2 \pi}\)
4 \(\dfrac{2 \pi}{\sqrt{3}}\)
PHXI14:OSCILLATIONS

364287 An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is \(15\;cm{\rm{/}}\sec \) and the period is \(628\;ms\). The amplitude of the motion in centimeters is

1 3.0
2 2.0
3 1.5
4 1.0
Join With Us for More Updates
PHXI14:OSCILLATIONS

364283 A simple pendulum performs simple harmonic motion about \(x=0\) with an amplitude \(a\) and time period \(T\). The speed of the pendulum at \(x=a / 2\) will be

1 \(\dfrac{\pi a \sqrt{3}}{2 T}\)
2 \(\dfrac{\pi a}{T}\)
3 \(\dfrac{3 \pi^{2} a}{T}\)
4 \(\dfrac{\pi a \sqrt{3}}{T}\)
PHXI14:OSCILLATIONS

364284 A particle performs linear SHM at a particular instant, velocity of the particle is ' \(u\) ' and acceleration is ' \(\alpha\) ' while at another instant velocity is ' \(v\) ' and acceleration is \(\beta(0 < \alpha < \beta)\). The distance between the two positions is

1 \(\dfrac{u^{2}-v^{2}}{\alpha+\beta}\)
2 \(\dfrac{u^{2}+v^{2}}{\alpha+\beta}\)
3 \(\dfrac{u^{2}-v^{2}}{\alpha-\beta}\)
4 \(\dfrac{u^{2}+v^{2}}{\alpha-\beta}\)
MHTCET - 2017
PHXI14:OSCILLATIONS

364285 Assertion :
In extreme position of a particle executing S.H.M., both velocity and acceleration are zero.
Reason :
In S.H.M., acceleration always acts towards mean position.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXI14:OSCILLATIONS

364286 A particle executes linear simple harmonic motion with an amplitude of \(2\;cm\). When the particle is at \(1\;cm\) from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

1 \(2 \pi \sqrt{3}\)
2 \(\dfrac{1}{2 \pi \sqrt{3}}\)
3 \(\dfrac{\sqrt{3}}{2 \pi}\)
4 \(\dfrac{2 \pi}{\sqrt{3}}\)
PHXI14:OSCILLATIONS

364287 An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is \(15\;cm{\rm{/}}\sec \) and the period is \(628\;ms\). The amplitude of the motion in centimeters is

1 3.0
2 2.0
3 1.5
4 1.0