QBManager

PHXII06:ELECTROMAGNETIC INDUCTION

358675 In the following figure,the magnet is moved towards the coil with a speed $v$ and induced emf is $ε$ . If magnet and coil recede away from one another each moving with speed $v$ , the induced emf in the coil will be
supporting img

1

ε

2

2 ε

3

ε / 2

4

4 ε

Explanation:

${(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = ε$
${(\frac{d ϕ}{d t})}_{I n 2^{n d} c a s e} = 2 {(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = 2 ε$
supporting img

PHXII06:ELECTROMAGNETIC INDUCTION

358676 The Lenz's law gives:

1 direction of induced current

2 magnitude of induced emf

3 magnitude of induced current

4 magnitude and direction of induced current

PHXII06:ELECTROMAGNETIC INDUCTION

358677 A bar magnet is allowed to fall vertically through a copper coil placed in a horizontal plane. The magnet falls with a net acceleration
supporting img

1

= g

2 zero

3

< g

4

> g

KCET - 2017

PHXII06:ELECTROMAGNETIC INDUCTION

358678 If a resistance less rod is moving with constant velocity $v$ in a constant magnetic field. Then direction of current $I_{1}$ and $I_{2}$ in resistance $R_{1}$ and $R_{2}$ respectively is :
supporting img

1

I_{1} \to

clockwise,

I_{2} \to

Anticlockwise

2

I_{1} \to

Anticlockwise,

I_{2} \to

Clockwise

3

I_{1}

and

I_{2}

both clockwise

4

I_{1}

and

I_{2}

both Anticlockwise

Explanation:

The magnetic flux is decreasing in the loop on the left and increasing in the loop on the right.
$∴$ Using Lenz's law, the direction of current $I_{1}$ in $R_{1}$ is clockwise and the direction of current $I_{2}$ in $R_{2}$ is anticlockwise.
supporting img

JEE - 2021

PHXII06:ELECTROMAGNETIC INDUCTION

358679 There are two coils $A$ and $B$ as shown in the fig. A current starts following in B as shown when $A$ is moved towards $B$ and current will be zero in $B$ when $A$ stops moving we can infer that
supporting img

1 There is no current in

A

2 There is a constant current in the clockwise direction in

A

3 There is a varying current in

A

4 There is a constant current in the counterclockwise direction in

A

Explanation:

Coil $A$ must be carrying a constant current in counter clockwise direction. That is why when $A$ moves towards $B$ , current induced in $B$ is in counter clockwise direction, as per Lenz's law. The current in $B$ would stop when $A$ stops moving.

PHXII06:ELECTROMAGNETIC INDUCTION

358675 In the following figure,the magnet is moved towards the coil with a speed $v$ and induced emf is $ε$ . If magnet and coil recede away from one another each moving with speed $v$ , the induced emf in the coil will be
supporting img

1

ε

2

2 ε

3

ε / 2

4

4 ε

Explanation:

${(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = ε$
${(\frac{d ϕ}{d t})}_{I n 2^{n d} c a s e} = 2 {(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = 2 ε$
supporting img

PHXII06:ELECTROMAGNETIC INDUCTION

358676 The Lenz's law gives:

1 direction of induced current

2 magnitude of induced emf

3 magnitude of induced current

4 magnitude and direction of induced current

PHXII06:ELECTROMAGNETIC INDUCTION

358677 A bar magnet is allowed to fall vertically through a copper coil placed in a horizontal plane. The magnet falls with a net acceleration
supporting img

1

= g

2 zero

3

< g

4

> g

KCET - 2017

PHXII06:ELECTROMAGNETIC INDUCTION

358678 If a resistance less rod is moving with constant velocity $v$ in a constant magnetic field. Then direction of current $I_{1}$ and $I_{2}$ in resistance $R_{1}$ and $R_{2}$ respectively is :
supporting img

1

I_{1} \to

clockwise,

I_{2} \to

Anticlockwise

2

I_{1} \to

Anticlockwise,

I_{2} \to

Clockwise

3

I_{1}

and

I_{2}

both clockwise

4

I_{1}

and

I_{2}

both Anticlockwise

Explanation:

The magnetic flux is decreasing in the loop on the left and increasing in the loop on the right.
$∴$ Using Lenz's law, the direction of current $I_{1}$ in $R_{1}$ is clockwise and the direction of current $I_{2}$ in $R_{2}$ is anticlockwise.
supporting img

JEE - 2021

PHXII06:ELECTROMAGNETIC INDUCTION

358679 There are two coils $A$ and $B$ as shown in the fig. A current starts following in B as shown when $A$ is moved towards $B$ and current will be zero in $B$ when $A$ stops moving we can infer that
supporting img

1 There is no current in

A

2 There is a constant current in the clockwise direction in

A

3 There is a varying current in

A

4 There is a constant current in the counterclockwise direction in

A

Explanation:

Coil $A$ must be carrying a constant current in counter clockwise direction. That is why when $A$ moves towards $B$ , current induced in $B$ is in counter clockwise direction, as per Lenz's law. The current in $B$ would stop when $A$ stops moving.

PHXII06:ELECTROMAGNETIC INDUCTION

358675 In the following figure,the magnet is moved towards the coil with a speed $v$ and induced emf is $ε$ . If magnet and coil recede away from one another each moving with speed $v$ , the induced emf in the coil will be
supporting img

1

ε

2

2 ε

3

ε / 2

4

4 ε

Explanation:

${(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = ε$
${(\frac{d ϕ}{d t})}_{I n 2^{n d} c a s e} = 2 {(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = 2 ε$
supporting img

PHXII06:ELECTROMAGNETIC INDUCTION

358676 The Lenz's law gives:

1 direction of induced current

2 magnitude of induced emf

3 magnitude of induced current

4 magnitude and direction of induced current

PHXII06:ELECTROMAGNETIC INDUCTION

358677 A bar magnet is allowed to fall vertically through a copper coil placed in a horizontal plane. The magnet falls with a net acceleration
supporting img

1

= g

2 zero

3

< g

4

> g

KCET - 2017

PHXII06:ELECTROMAGNETIC INDUCTION

358678 If a resistance less rod is moving with constant velocity $v$ in a constant magnetic field. Then direction of current $I_{1}$ and $I_{2}$ in resistance $R_{1}$ and $R_{2}$ respectively is :
supporting img

1

I_{1} \to

clockwise,

I_{2} \to

Anticlockwise

2

I_{1} \to

Anticlockwise,

I_{2} \to

Clockwise

3

I_{1}

and

I_{2}

both clockwise

4

I_{1}

and

I_{2}

both Anticlockwise

Explanation:

The magnetic flux is decreasing in the loop on the left and increasing in the loop on the right.
$∴$ Using Lenz's law, the direction of current $I_{1}$ in $R_{1}$ is clockwise and the direction of current $I_{2}$ in $R_{2}$ is anticlockwise.
supporting img

JEE - 2021

PHXII06:ELECTROMAGNETIC INDUCTION

358679 There are two coils $A$ and $B$ as shown in the fig. A current starts following in B as shown when $A$ is moved towards $B$ and current will be zero in $B$ when $A$ stops moving we can infer that
supporting img

1 There is no current in

A

2 There is a constant current in the clockwise direction in

A

3 There is a varying current in

A

4 There is a constant current in the counterclockwise direction in

A

Explanation:

Coil $A$ must be carrying a constant current in counter clockwise direction. That is why when $A$ moves towards $B$ , current induced in $B$ is in counter clockwise direction, as per Lenz's law. The current in $B$ would stop when $A$ stops moving.

PHXII06:ELECTROMAGNETIC INDUCTION

358675 In the following figure,the magnet is moved towards the coil with a speed $v$ and induced emf is $ε$ . If magnet and coil recede away from one another each moving with speed $v$ , the induced emf in the coil will be
supporting img

1

ε

2

2 ε

3

ε / 2

4

4 ε

Explanation:

${(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = ε$
${(\frac{d ϕ}{d t})}_{I n 2^{n d} c a s e} = 2 {(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = 2 ε$
supporting img

PHXII06:ELECTROMAGNETIC INDUCTION

358676 The Lenz's law gives:

1 direction of induced current

2 magnitude of induced emf

3 magnitude of induced current

4 magnitude and direction of induced current

PHXII06:ELECTROMAGNETIC INDUCTION

358677 A bar magnet is allowed to fall vertically through a copper coil placed in a horizontal plane. The magnet falls with a net acceleration
supporting img

1

= g

2 zero

3

< g

4

> g

KCET - 2017

PHXII06:ELECTROMAGNETIC INDUCTION

358678 If a resistance less rod is moving with constant velocity $v$ in a constant magnetic field. Then direction of current $I_{1}$ and $I_{2}$ in resistance $R_{1}$ and $R_{2}$ respectively is :
supporting img

1

I_{1} \to

clockwise,

I_{2} \to

Anticlockwise

2

I_{1} \to

Anticlockwise,

I_{2} \to

Clockwise

3

I_{1}

and

I_{2}

both clockwise

4

I_{1}

and

I_{2}

both Anticlockwise

Explanation:

The magnetic flux is decreasing in the loop on the left and increasing in the loop on the right.
$∴$ Using Lenz's law, the direction of current $I_{1}$ in $R_{1}$ is clockwise and the direction of current $I_{2}$ in $R_{2}$ is anticlockwise.
supporting img

JEE - 2021

PHXII06:ELECTROMAGNETIC INDUCTION

358679 There are two coils $A$ and $B$ as shown in the fig. A current starts following in B as shown when $A$ is moved towards $B$ and current will be zero in $B$ when $A$ stops moving we can infer that
supporting img

1 There is no current in

A

2 There is a constant current in the clockwise direction in

A

3 There is a varying current in

A

4 There is a constant current in the counterclockwise direction in

A

Explanation:

Coil $A$ must be carrying a constant current in counter clockwise direction. That is why when $A$ moves towards $B$ , current induced in $B$ is in counter clockwise direction, as per Lenz's law. The current in $B$ would stop when $A$ stops moving.

PHXII06:ELECTROMAGNETIC INDUCTION

358675 In the following figure,the magnet is moved towards the coil with a speed $v$ and induced emf is $ε$ . If magnet and coil recede away from one another each moving with speed $v$ , the induced emf in the coil will be
supporting img

1

ε

2

2 ε

3

ε / 2

4

4 ε

Explanation:

${(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = ε$
${(\frac{d ϕ}{d t})}_{I n 2^{n d} c a s e} = 2 {(\frac{d ϕ}{d t})}_{I n 1^{1 t} c a s e} = 2 ε$
supporting img

PHXII06:ELECTROMAGNETIC INDUCTION

358676 The Lenz's law gives:

1 direction of induced current

2 magnitude of induced emf

3 magnitude of induced current

4 magnitude and direction of induced current

PHXII06:ELECTROMAGNETIC INDUCTION

358677 A bar magnet is allowed to fall vertically through a copper coil placed in a horizontal plane. The magnet falls with a net acceleration
supporting img

1

= g

2 zero

3

< g

4

> g

KCET - 2017

PHXII06:ELECTROMAGNETIC INDUCTION

358678 If a resistance less rod is moving with constant velocity $v$ in a constant magnetic field. Then direction of current $I_{1}$ and $I_{2}$ in resistance $R_{1}$ and $R_{2}$ respectively is :
supporting img

1

I_{1} \to

clockwise,

I_{2} \to

Anticlockwise

2

I_{1} \to

Anticlockwise,

I_{2} \to

Clockwise

3

I_{1}

and

I_{2}

both clockwise

4

I_{1}

and

I_{2}

both Anticlockwise

Explanation:

The magnetic flux is decreasing in the loop on the left and increasing in the loop on the right.
$∴$ Using Lenz's law, the direction of current $I_{1}$ in $R_{1}$ is clockwise and the direction of current $I_{2}$ in $R_{2}$ is anticlockwise.
supporting img

JEE - 2021

PHXII06:ELECTROMAGNETIC INDUCTION

358679 There are two coils $A$ and $B$ as shown in the fig. A current starts following in B as shown when $A$ is moved towards $B$ and current will be zero in $B$ when $A$ stops moving we can infer that
supporting img

1 There is no current in

A

2 There is a constant current in the clockwise direction in

A

3 There is a varying current in

A

4 There is a constant current in the counterclockwise direction in

A

Explanation:

Coil $A$ must be carrying a constant current in counter clockwise direction. That is why when $A$ moves towards $B$ , current induced in $B$ is in counter clockwise direction, as per Lenz's law. The current in $B$ would stop when $A$ stops moving.