Explanation:
The self inductance of the solenoid is
\(L=\dfrac{\mu_{r} \mu_{0} N^{2} A}{l}\)
Here, \({\mu _r} = 600,{\mu _0} = 4\pi \times {10^{ - 7}}H{m^{ - 1}}\)
\(N = 2000,A = 1.5\;c{m^2} = 1.5 \times {10^{ - 4}}\;{m^2}\)
\(l = 30\;cm = 30 \times {10^{ - 2}}\;m\)
\[L = \frac{{\left[ \begin{gathered}
(600)\left( {4\pi \times {{10}^{ - 7}}H{m^{ - 1}}} \right){(2000)^2} \hfill \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( {1.5 \times {{10}^{ - 4}}{m^2}} \right) \hfill \\
\end{gathered} \right]}}{{\left( {30 \times {{10}^{ - 2}}m} \right)}}\]
\(\,\,\,\,\,\,\, = 1.5H\)
