358584
What is the self-inductance of solenoid of length \(31.4\;cm\), area of cross-section \({10^{ - 3}}\;{m^2}\) and total number of turns \(10^{3}\)?
358586
In a coil, the current changes from \(-2 A\) to \(2 A\) in \(0.2 s\) and induces an emf of \(0.1\,V.\) The self inductance of the coil is
1 \(5\,mH\)
2 \(4\,mH\)
3 \(1\,mH\)
4 \(2.5\,mH\)
Explanation:
Given: \(dt = 0.2\,s,e = 0.1\;V\) Induced emf in a inductor is \(\varepsilon=-L \dfrac{d i}{d t}\) Change in current in a coil, \(di = 2 - ( - 2) = 4\;A\) \(e=L \dfrac{d i}{d t}\) \( \Rightarrow 0.1 = L \times \frac{4}{{0.2}};L = 5\,mH\)
JEE - 2024
PHXII06:ELECTROMAGNETIC INDUCTION
358587
A long solenoid has 1000 turns. When a current of \(4\;A\) flows through it, the magnetic flux linked with each turn of the solenoid is \(4 \times {10^{ - 3}}\;\,Wb\). The self inductance of the solenoid is
1 \(4\,H\)
2 \(3\,H\)
3 \(2\,H\)
4 \(1\,H\)
Explanation:
\(\therefore\) Total flux linked \( = 1000\left[ {4 \times {{10}^{ - 3}}} \right]\,Wb\) \(\phi_{t o t a l}=4 \Rightarrow L i=4 \Rightarrow L=1 H\)
NEET - 2016
PHXII06:ELECTROMAGNETIC INDUCTION
358588
The back e.m.f. induced in a coil, when current changes from 1 ampere to zero in one millisecond, is 4 volts, the self-inductance of the coil is
1 \(4 \times {10^{ - 3}}H\)
2 \({10^{ - 3}}H\)
3 \(4H\)
4 \(1H\)
Explanation:
The back emf \(\varepsilon=-L \dfrac{d i}{d t}\) but \(\varepsilon=4 V\) and \(\frac{{di}}{{dt}} = \frac{{(0 - 1)}}{{{{10}^{ - 3}}}}\) \(\therefore \frac{{ - 1}}{{{{10}^{ - 3}}}}( - L) = 4 \Rightarrow L = 4 \times {10^{ - 3}}henry\)
358584
What is the self-inductance of solenoid of length \(31.4\;cm\), area of cross-section \({10^{ - 3}}\;{m^2}\) and total number of turns \(10^{3}\)?
358586
In a coil, the current changes from \(-2 A\) to \(2 A\) in \(0.2 s\) and induces an emf of \(0.1\,V.\) The self inductance of the coil is
1 \(5\,mH\)
2 \(4\,mH\)
3 \(1\,mH\)
4 \(2.5\,mH\)
Explanation:
Given: \(dt = 0.2\,s,e = 0.1\;V\) Induced emf in a inductor is \(\varepsilon=-L \dfrac{d i}{d t}\) Change in current in a coil, \(di = 2 - ( - 2) = 4\;A\) \(e=L \dfrac{d i}{d t}\) \( \Rightarrow 0.1 = L \times \frac{4}{{0.2}};L = 5\,mH\)
JEE - 2024
PHXII06:ELECTROMAGNETIC INDUCTION
358587
A long solenoid has 1000 turns. When a current of \(4\;A\) flows through it, the magnetic flux linked with each turn of the solenoid is \(4 \times {10^{ - 3}}\;\,Wb\). The self inductance of the solenoid is
1 \(4\,H\)
2 \(3\,H\)
3 \(2\,H\)
4 \(1\,H\)
Explanation:
\(\therefore\) Total flux linked \( = 1000\left[ {4 \times {{10}^{ - 3}}} \right]\,Wb\) \(\phi_{t o t a l}=4 \Rightarrow L i=4 \Rightarrow L=1 H\)
NEET - 2016
PHXII06:ELECTROMAGNETIC INDUCTION
358588
The back e.m.f. induced in a coil, when current changes from 1 ampere to zero in one millisecond, is 4 volts, the self-inductance of the coil is
1 \(4 \times {10^{ - 3}}H\)
2 \({10^{ - 3}}H\)
3 \(4H\)
4 \(1H\)
Explanation:
The back emf \(\varepsilon=-L \dfrac{d i}{d t}\) but \(\varepsilon=4 V\) and \(\frac{{di}}{{dt}} = \frac{{(0 - 1)}}{{{{10}^{ - 3}}}}\) \(\therefore \frac{{ - 1}}{{{{10}^{ - 3}}}}( - L) = 4 \Rightarrow L = 4 \times {10^{ - 3}}henry\)
358584
What is the self-inductance of solenoid of length \(31.4\;cm\), area of cross-section \({10^{ - 3}}\;{m^2}\) and total number of turns \(10^{3}\)?
358586
In a coil, the current changes from \(-2 A\) to \(2 A\) in \(0.2 s\) and induces an emf of \(0.1\,V.\) The self inductance of the coil is
1 \(5\,mH\)
2 \(4\,mH\)
3 \(1\,mH\)
4 \(2.5\,mH\)
Explanation:
Given: \(dt = 0.2\,s,e = 0.1\;V\) Induced emf in a inductor is \(\varepsilon=-L \dfrac{d i}{d t}\) Change in current in a coil, \(di = 2 - ( - 2) = 4\;A\) \(e=L \dfrac{d i}{d t}\) \( \Rightarrow 0.1 = L \times \frac{4}{{0.2}};L = 5\,mH\)
JEE - 2024
PHXII06:ELECTROMAGNETIC INDUCTION
358587
A long solenoid has 1000 turns. When a current of \(4\;A\) flows through it, the magnetic flux linked with each turn of the solenoid is \(4 \times {10^{ - 3}}\;\,Wb\). The self inductance of the solenoid is
1 \(4\,H\)
2 \(3\,H\)
3 \(2\,H\)
4 \(1\,H\)
Explanation:
\(\therefore\) Total flux linked \( = 1000\left[ {4 \times {{10}^{ - 3}}} \right]\,Wb\) \(\phi_{t o t a l}=4 \Rightarrow L i=4 \Rightarrow L=1 H\)
NEET - 2016
PHXII06:ELECTROMAGNETIC INDUCTION
358588
The back e.m.f. induced in a coil, when current changes from 1 ampere to zero in one millisecond, is 4 volts, the self-inductance of the coil is
1 \(4 \times {10^{ - 3}}H\)
2 \({10^{ - 3}}H\)
3 \(4H\)
4 \(1H\)
Explanation:
The back emf \(\varepsilon=-L \dfrac{d i}{d t}\) but \(\varepsilon=4 V\) and \(\frac{{di}}{{dt}} = \frac{{(0 - 1)}}{{{{10}^{ - 3}}}}\) \(\therefore \frac{{ - 1}}{{{{10}^{ - 3}}}}( - L) = 4 \Rightarrow L = 4 \times {10^{ - 3}}henry\)
358584
What is the self-inductance of solenoid of length \(31.4\;cm\), area of cross-section \({10^{ - 3}}\;{m^2}\) and total number of turns \(10^{3}\)?
358586
In a coil, the current changes from \(-2 A\) to \(2 A\) in \(0.2 s\) and induces an emf of \(0.1\,V.\) The self inductance of the coil is
1 \(5\,mH\)
2 \(4\,mH\)
3 \(1\,mH\)
4 \(2.5\,mH\)
Explanation:
Given: \(dt = 0.2\,s,e = 0.1\;V\) Induced emf in a inductor is \(\varepsilon=-L \dfrac{d i}{d t}\) Change in current in a coil, \(di = 2 - ( - 2) = 4\;A\) \(e=L \dfrac{d i}{d t}\) \( \Rightarrow 0.1 = L \times \frac{4}{{0.2}};L = 5\,mH\)
JEE - 2024
PHXII06:ELECTROMAGNETIC INDUCTION
358587
A long solenoid has 1000 turns. When a current of \(4\;A\) flows through it, the magnetic flux linked with each turn of the solenoid is \(4 \times {10^{ - 3}}\;\,Wb\). The self inductance of the solenoid is
1 \(4\,H\)
2 \(3\,H\)
3 \(2\,H\)
4 \(1\,H\)
Explanation:
\(\therefore\) Total flux linked \( = 1000\left[ {4 \times {{10}^{ - 3}}} \right]\,Wb\) \(\phi_{t o t a l}=4 \Rightarrow L i=4 \Rightarrow L=1 H\)
NEET - 2016
PHXII06:ELECTROMAGNETIC INDUCTION
358588
The back e.m.f. induced in a coil, when current changes from 1 ampere to zero in one millisecond, is 4 volts, the self-inductance of the coil is
1 \(4 \times {10^{ - 3}}H\)
2 \({10^{ - 3}}H\)
3 \(4H\)
4 \(1H\)
Explanation:
The back emf \(\varepsilon=-L \dfrac{d i}{d t}\) but \(\varepsilon=4 V\) and \(\frac{{di}}{{dt}} = \frac{{(0 - 1)}}{{{{10}^{ - 3}}}}\) \(\therefore \frac{{ - 1}}{{{{10}^{ - 3}}}}( - L) = 4 \Rightarrow L = 4 \times {10^{ - 3}}henry\)
358584
What is the self-inductance of solenoid of length \(31.4\;cm\), area of cross-section \({10^{ - 3}}\;{m^2}\) and total number of turns \(10^{3}\)?
358586
In a coil, the current changes from \(-2 A\) to \(2 A\) in \(0.2 s\) and induces an emf of \(0.1\,V.\) The self inductance of the coil is
1 \(5\,mH\)
2 \(4\,mH\)
3 \(1\,mH\)
4 \(2.5\,mH\)
Explanation:
Given: \(dt = 0.2\,s,e = 0.1\;V\) Induced emf in a inductor is \(\varepsilon=-L \dfrac{d i}{d t}\) Change in current in a coil, \(di = 2 - ( - 2) = 4\;A\) \(e=L \dfrac{d i}{d t}\) \( \Rightarrow 0.1 = L \times \frac{4}{{0.2}};L = 5\,mH\)
JEE - 2024
PHXII06:ELECTROMAGNETIC INDUCTION
358587
A long solenoid has 1000 turns. When a current of \(4\;A\) flows through it, the magnetic flux linked with each turn of the solenoid is \(4 \times {10^{ - 3}}\;\,Wb\). The self inductance of the solenoid is
1 \(4\,H\)
2 \(3\,H\)
3 \(2\,H\)
4 \(1\,H\)
Explanation:
\(\therefore\) Total flux linked \( = 1000\left[ {4 \times {{10}^{ - 3}}} \right]\,Wb\) \(\phi_{t o t a l}=4 \Rightarrow L i=4 \Rightarrow L=1 H\)
NEET - 2016
PHXII06:ELECTROMAGNETIC INDUCTION
358588
The back e.m.f. induced in a coil, when current changes from 1 ampere to zero in one millisecond, is 4 volts, the self-inductance of the coil is
1 \(4 \times {10^{ - 3}}H\)
2 \({10^{ - 3}}H\)
3 \(4H\)
4 \(1H\)
Explanation:
The back emf \(\varepsilon=-L \dfrac{d i}{d t}\) but \(\varepsilon=4 V\) and \(\frac{{di}}{{dt}} = \frac{{(0 - 1)}}{{{{10}^{ - 3}}}}\) \(\therefore \frac{{ - 1}}{{{{10}^{ - 3}}}}( - L) = 4 \Rightarrow L = 4 \times {10^{ - 3}}henry\)
