358509
Assertion : An electric field is induced in a closed loop where magnetic flux is varied with time. The induced \(\vec{E}\) is not a conservative field. Reason : The line integral \(\vec{E} \cdot d \vec{l}\) around the closed loop is non-zero.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The induced electric field in a time varying magnetic field is always non-conservative. So \(\vec{E} \cdot d \vec{\ell}\) in a closed loop is non zero. So option (1) is correct.
PHXII06:ELECTROMAGNETIC INDUCTION
358510
In a closed loop, which has some inductance but negligible resistance, uniform but time varying magnetic field is applied directed into the plane of the loop. Variation of field with time is shown. Predict the correct option.
1 Emf induced in the loop is zero at \(t = 2\;s\)
2 Current in the loop will be maximum at \(t = 2\;s\)
3 Direction of emf in the loop will change at \(t = 2\;s\)
4 None of the above
Explanation:
\(\varepsilon = - \frac{{d\phi }}{{dt}} = - A\left( {\frac{{dB}}{{dt}}} \right)\) At \(t=2 s\), slope is zero and it changes its sign. \(\dfrac{d B}{d t}\) is non-zero at \(t=0\) and hence \(\varepsilon_{\text {ind }} \neq 0\)
358509
Assertion : An electric field is induced in a closed loop where magnetic flux is varied with time. The induced \(\vec{E}\) is not a conservative field. Reason : The line integral \(\vec{E} \cdot d \vec{l}\) around the closed loop is non-zero.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
The induced electric field in a time varying magnetic field is always non-conservative. So \(\vec{E} \cdot d \vec{\ell}\) in a closed loop is non zero. So option (1) is correct.
PHXII06:ELECTROMAGNETIC INDUCTION
358510
In a closed loop, which has some inductance but negligible resistance, uniform but time varying magnetic field is applied directed into the plane of the loop. Variation of field with time is shown. Predict the correct option.
1 Emf induced in the loop is zero at \(t = 2\;s\)
2 Current in the loop will be maximum at \(t = 2\;s\)
3 Direction of emf in the loop will change at \(t = 2\;s\)
4 None of the above
Explanation:
\(\varepsilon = - \frac{{d\phi }}{{dt}} = - A\left( {\frac{{dB}}{{dt}}} \right)\) At \(t=2 s\), slope is zero and it changes its sign. \(\dfrac{d B}{d t}\) is non-zero at \(t=0\) and hence \(\varepsilon_{\text {ind }} \neq 0\)
