D.C. Circuits
PHXII06:ELECTROMAGNETIC INDUCTION

358392 The time constant of an inductor is \(\tau_{1}\). When a pure resistor of \(R\Omega \) is connected in series with it, the time constant is found to decrease to \(\tau_{2}\). The internal resistance of the inductor is

1 \(\dfrac{R \tau_{2}}{\tau_{1}-\tau_{2}}\)
2 \(\dfrac{R \tau_{1}}{\tau_{1}-\tau_{2}}\)
3 \(\dfrac{R\left(\tau_{1}-\tau_{2}\right)}{\tau_{1}}\)
4 \(\dfrac{R\left(\tau_{1}-\tau_{2}\right)}{\tau_{2}}\)
PHXII06:ELECTROMAGNETIC INDUCTION

358393 In given figure, \(R = 15\,\Omega ,L = 5.0\,H\), the ideal battery has \({\varepsilon=10 {~V}}\), and the fuse in the upper branch is an ideal \(3.0\,A\) fuse. It has zero resistance as long as the current through it remains less than \(3.0\,A.\) If the current reaches \(3.0\,A,\) the fuse "blows" and thereafter has infinite resistance. Switch \({S}\) is closed at time \({t=0}\). At what time does the fuse blow ?
supporting img

1 \(2.4\,s\)
2 \(1.5\,s\)
3 \(4.6\,s\)
4 \(6.4\,s\)
PHXII06:ELECTROMAGNETIC INDUCTION

358394 In the following circuit, the switch is closed at \({t}=0\). Initially, there is no current in inductor. The relation of current in the coil with time is given as \({i}=\dfrac{\varepsilon}{{NR}}\left[1-\exp \left(-{Q} \dfrac{{R}}{{L}} {t}\right)\right]\). What is the value of \(\dfrac{{N}}{{Q}}\) ?
supporting img

1 5
2 7
3 2
4 4
PHXII06:ELECTROMAGNETIC INDUCTION

358395 The network shown in the figure is a part of a complete circuit. If at a certain instant the current \(i\) is \(5\;A\) and is decreasing at the rate of \({10^3}\;A/S\,{\text{then}}\,{V_A} - {V_B}\) is:
supporting img

1 \(5\;\,V\)
2 \(10\;\,V\)
3 \(15\,\;V\)
4 \(20\;\,V\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXII06:ELECTROMAGNETIC INDUCTION

358392 The time constant of an inductor is \(\tau_{1}\). When a pure resistor of \(R\Omega \) is connected in series with it, the time constant is found to decrease to \(\tau_{2}\). The internal resistance of the inductor is

1 \(\dfrac{R \tau_{2}}{\tau_{1}-\tau_{2}}\)
2 \(\dfrac{R \tau_{1}}{\tau_{1}-\tau_{2}}\)
3 \(\dfrac{R\left(\tau_{1}-\tau_{2}\right)}{\tau_{1}}\)
4 \(\dfrac{R\left(\tau_{1}-\tau_{2}\right)}{\tau_{2}}\)
PHXII06:ELECTROMAGNETIC INDUCTION

358393 In given figure, \(R = 15\,\Omega ,L = 5.0\,H\), the ideal battery has \({\varepsilon=10 {~V}}\), and the fuse in the upper branch is an ideal \(3.0\,A\) fuse. It has zero resistance as long as the current through it remains less than \(3.0\,A.\) If the current reaches \(3.0\,A,\) the fuse "blows" and thereafter has infinite resistance. Switch \({S}\) is closed at time \({t=0}\). At what time does the fuse blow ?
supporting img

1 \(2.4\,s\)
2 \(1.5\,s\)
3 \(4.6\,s\)
4 \(6.4\,s\)
PHXII06:ELECTROMAGNETIC INDUCTION

358394 In the following circuit, the switch is closed at \({t}=0\). Initially, there is no current in inductor. The relation of current in the coil with time is given as \({i}=\dfrac{\varepsilon}{{NR}}\left[1-\exp \left(-{Q} \dfrac{{R}}{{L}} {t}\right)\right]\). What is the value of \(\dfrac{{N}}{{Q}}\) ?
supporting img

1 5
2 7
3 2
4 4
PHXII06:ELECTROMAGNETIC INDUCTION

358395 The network shown in the figure is a part of a complete circuit. If at a certain instant the current \(i\) is \(5\;A\) and is decreasing at the rate of \({10^3}\;A/S\,{\text{then}}\,{V_A} - {V_B}\) is:
supporting img

1 \(5\;\,V\)
2 \(10\;\,V\)
3 \(15\,\;V\)
4 \(20\;\,V\)
PHXII06:ELECTROMAGNETIC INDUCTION

358392 The time constant of an inductor is \(\tau_{1}\). When a pure resistor of \(R\Omega \) is connected in series with it, the time constant is found to decrease to \(\tau_{2}\). The internal resistance of the inductor is

1 \(\dfrac{R \tau_{2}}{\tau_{1}-\tau_{2}}\)
2 \(\dfrac{R \tau_{1}}{\tau_{1}-\tau_{2}}\)
3 \(\dfrac{R\left(\tau_{1}-\tau_{2}\right)}{\tau_{1}}\)
4 \(\dfrac{R\left(\tau_{1}-\tau_{2}\right)}{\tau_{2}}\)
PHXII06:ELECTROMAGNETIC INDUCTION

358393 In given figure, \(R = 15\,\Omega ,L = 5.0\,H\), the ideal battery has \({\varepsilon=10 {~V}}\), and the fuse in the upper branch is an ideal \(3.0\,A\) fuse. It has zero resistance as long as the current through it remains less than \(3.0\,A.\) If the current reaches \(3.0\,A,\) the fuse "blows" and thereafter has infinite resistance. Switch \({S}\) is closed at time \({t=0}\). At what time does the fuse blow ?
supporting img

1 \(2.4\,s\)
2 \(1.5\,s\)
3 \(4.6\,s\)
4 \(6.4\,s\)
PHXII06:ELECTROMAGNETIC INDUCTION

358394 In the following circuit, the switch is closed at \({t}=0\). Initially, there is no current in inductor. The relation of current in the coil with time is given as \({i}=\dfrac{\varepsilon}{{NR}}\left[1-\exp \left(-{Q} \dfrac{{R}}{{L}} {t}\right)\right]\). What is the value of \(\dfrac{{N}}{{Q}}\) ?
supporting img

1 5
2 7
3 2
4 4
PHXII06:ELECTROMAGNETIC INDUCTION

358395 The network shown in the figure is a part of a complete circuit. If at a certain instant the current \(i\) is \(5\;A\) and is decreasing at the rate of \({10^3}\;A/S\,{\text{then}}\,{V_A} - {V_B}\) is:
supporting img

1 \(5\;\,V\)
2 \(10\;\,V\)
3 \(15\,\;V\)
4 \(20\;\,V\)
PHXII06:ELECTROMAGNETIC INDUCTION

358392 The time constant of an inductor is \(\tau_{1}\). When a pure resistor of \(R\Omega \) is connected in series with it, the time constant is found to decrease to \(\tau_{2}\). The internal resistance of the inductor is

1 \(\dfrac{R \tau_{2}}{\tau_{1}-\tau_{2}}\)
2 \(\dfrac{R \tau_{1}}{\tau_{1}-\tau_{2}}\)
3 \(\dfrac{R\left(\tau_{1}-\tau_{2}\right)}{\tau_{1}}\)
4 \(\dfrac{R\left(\tau_{1}-\tau_{2}\right)}{\tau_{2}}\)
PHXII06:ELECTROMAGNETIC INDUCTION

358393 In given figure, \(R = 15\,\Omega ,L = 5.0\,H\), the ideal battery has \({\varepsilon=10 {~V}}\), and the fuse in the upper branch is an ideal \(3.0\,A\) fuse. It has zero resistance as long as the current through it remains less than \(3.0\,A.\) If the current reaches \(3.0\,A,\) the fuse "blows" and thereafter has infinite resistance. Switch \({S}\) is closed at time \({t=0}\). At what time does the fuse blow ?
supporting img

1 \(2.4\,s\)
2 \(1.5\,s\)
3 \(4.6\,s\)
4 \(6.4\,s\)
PHXII06:ELECTROMAGNETIC INDUCTION

358394 In the following circuit, the switch is closed at \({t}=0\). Initially, there is no current in inductor. The relation of current in the coil with time is given as \({i}=\dfrac{\varepsilon}{{NR}}\left[1-\exp \left(-{Q} \dfrac{{R}}{{L}} {t}\right)\right]\). What is the value of \(\dfrac{{N}}{{Q}}\) ?
supporting img

1 5
2 7
3 2
4 4
PHXII06:ELECTROMAGNETIC INDUCTION

358395 The network shown in the figure is a part of a complete circuit. If at a certain instant the current \(i\) is \(5\;A\) and is decreasing at the rate of \({10^3}\;A/S\,{\text{then}}\,{V_A} - {V_B}\) is:
supporting img

1 \(5\;\,V\)
2 \(10\;\,V\)
3 \(15\,\;V\)
4 \(20\;\,V\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here