343008
Escherichia coli fully labelled with \(15 \mathrm{~N}\) is allowed to grow in \(14 \mathrm{~N}\) medium. The two strands of DNA molecule of the first generation bacteria have
1 Different density and do not resemble parent DNA
2 Different density but resemble parent DNA
3 Same density and resemble parent DNA
4 Same density but do not resemble parent DNA
Explanation:
Will have different density and do not resemble parent DNA
BIOXII06: MOLECULAR BASIS OF INHERITANCE
343010
Match the columns I and II. Column I Column II A Frederick Griffith P 1952 B Oswald Avery Q British bacteriologist - 1928 C Alfred Hershey & Matha Chase R Radioactive thymidine D Taylor S 1958 E Mathew Messelson & Franklin Stahl T 1933 - 34
343011
If Messelson and Stahl's experiment is continued for five generations in bacteria, the ratio of \(15 \mathrm{~N} / 14 \mathrm{~N}: 14 \mathrm{~N} / 14 \mathrm{~N}\) containing DNA in the fifth generation would be:
1 \(1: 0\)
2 \(4: 0\)
3 \(1: 7\)
4 \(1: 15\)
Explanation:
The solution consists of \(\mathrm{N}^{14}\), therefore after fifth generation there would be \(2 \mathrm{~N}^{15} \mathrm{~N}^{14}\) and 30 \(\mathrm{N}^{14} \mathrm{~N}^{14}\)
BIOXII06: MOLECULAR BASIS OF INHERITANCE
343012
Ten E.coli cells with \({ }^{15} \mathrm{~N}\)-dsDNA are incubated in medium containing \({ }^{14} \mathrm{~N}\) nucleotide. After 60 minutes, how many E.coli cells will have DNA totally free from \({ }^{15} \mathrm{~N}\) ?
1 40 cells
2 60 cells
3 80 cells
4 20 cells
Explanation:
Initially we have \(^{{\rm{15}}}{{\rm{N}}^{{\rm{15}}}}{\rm{N}}\). After 1 st generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \({{\rm{2}}^{{\rm{15}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA After 2nd generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \(2{ }^{15} \mathrm{~N}^{14} \mathrm{~N}\) DNA and \(4{ }^{14} \mathrm{~N}^{14} \mathrm{~N}\) DNA.After 3rd generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \({{\rm{2}}^{{\rm{15}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA and \({\rm{6}}{{\rm{ }}^{{\rm{14}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA.
343008
Escherichia coli fully labelled with \(15 \mathrm{~N}\) is allowed to grow in \(14 \mathrm{~N}\) medium. The two strands of DNA molecule of the first generation bacteria have
1 Different density and do not resemble parent DNA
2 Different density but resemble parent DNA
3 Same density and resemble parent DNA
4 Same density but do not resemble parent DNA
Explanation:
Will have different density and do not resemble parent DNA
BIOXII06: MOLECULAR BASIS OF INHERITANCE
343010
Match the columns I and II. Column I Column II A Frederick Griffith P 1952 B Oswald Avery Q British bacteriologist - 1928 C Alfred Hershey & Matha Chase R Radioactive thymidine D Taylor S 1958 E Mathew Messelson & Franklin Stahl T 1933 - 34
343011
If Messelson and Stahl's experiment is continued for five generations in bacteria, the ratio of \(15 \mathrm{~N} / 14 \mathrm{~N}: 14 \mathrm{~N} / 14 \mathrm{~N}\) containing DNA in the fifth generation would be:
1 \(1: 0\)
2 \(4: 0\)
3 \(1: 7\)
4 \(1: 15\)
Explanation:
The solution consists of \(\mathrm{N}^{14}\), therefore after fifth generation there would be \(2 \mathrm{~N}^{15} \mathrm{~N}^{14}\) and 30 \(\mathrm{N}^{14} \mathrm{~N}^{14}\)
BIOXII06: MOLECULAR BASIS OF INHERITANCE
343012
Ten E.coli cells with \({ }^{15} \mathrm{~N}\)-dsDNA are incubated in medium containing \({ }^{14} \mathrm{~N}\) nucleotide. After 60 minutes, how many E.coli cells will have DNA totally free from \({ }^{15} \mathrm{~N}\) ?
1 40 cells
2 60 cells
3 80 cells
4 20 cells
Explanation:
Initially we have \(^{{\rm{15}}}{{\rm{N}}^{{\rm{15}}}}{\rm{N}}\). After 1 st generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \({{\rm{2}}^{{\rm{15}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA After 2nd generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \(2{ }^{15} \mathrm{~N}^{14} \mathrm{~N}\) DNA and \(4{ }^{14} \mathrm{~N}^{14} \mathrm{~N}\) DNA.After 3rd generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \({{\rm{2}}^{{\rm{15}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA and \({\rm{6}}{{\rm{ }}^{{\rm{14}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA.
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BIOXII06: MOLECULAR BASIS OF INHERITANCE
343008
Escherichia coli fully labelled with \(15 \mathrm{~N}\) is allowed to grow in \(14 \mathrm{~N}\) medium. The two strands of DNA molecule of the first generation bacteria have
1 Different density and do not resemble parent DNA
2 Different density but resemble parent DNA
3 Same density and resemble parent DNA
4 Same density but do not resemble parent DNA
Explanation:
Will have different density and do not resemble parent DNA
BIOXII06: MOLECULAR BASIS OF INHERITANCE
343010
Match the columns I and II. Column I Column II A Frederick Griffith P 1952 B Oswald Avery Q British bacteriologist - 1928 C Alfred Hershey & Matha Chase R Radioactive thymidine D Taylor S 1958 E Mathew Messelson & Franklin Stahl T 1933 - 34
343011
If Messelson and Stahl's experiment is continued for five generations in bacteria, the ratio of \(15 \mathrm{~N} / 14 \mathrm{~N}: 14 \mathrm{~N} / 14 \mathrm{~N}\) containing DNA in the fifth generation would be:
1 \(1: 0\)
2 \(4: 0\)
3 \(1: 7\)
4 \(1: 15\)
Explanation:
The solution consists of \(\mathrm{N}^{14}\), therefore after fifth generation there would be \(2 \mathrm{~N}^{15} \mathrm{~N}^{14}\) and 30 \(\mathrm{N}^{14} \mathrm{~N}^{14}\)
BIOXII06: MOLECULAR BASIS OF INHERITANCE
343012
Ten E.coli cells with \({ }^{15} \mathrm{~N}\)-dsDNA are incubated in medium containing \({ }^{14} \mathrm{~N}\) nucleotide. After 60 minutes, how many E.coli cells will have DNA totally free from \({ }^{15} \mathrm{~N}\) ?
1 40 cells
2 60 cells
3 80 cells
4 20 cells
Explanation:
Initially we have \(^{{\rm{15}}}{{\rm{N}}^{{\rm{15}}}}{\rm{N}}\). After 1 st generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \({{\rm{2}}^{{\rm{15}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA After 2nd generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \(2{ }^{15} \mathrm{~N}^{14} \mathrm{~N}\) DNA and \(4{ }^{14} \mathrm{~N}^{14} \mathrm{~N}\) DNA.After 3rd generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \({{\rm{2}}^{{\rm{15}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA and \({\rm{6}}{{\rm{ }}^{{\rm{14}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA.
343008
Escherichia coli fully labelled with \(15 \mathrm{~N}\) is allowed to grow in \(14 \mathrm{~N}\) medium. The two strands of DNA molecule of the first generation bacteria have
1 Different density and do not resemble parent DNA
2 Different density but resemble parent DNA
3 Same density and resemble parent DNA
4 Same density but do not resemble parent DNA
Explanation:
Will have different density and do not resemble parent DNA
BIOXII06: MOLECULAR BASIS OF INHERITANCE
343010
Match the columns I and II. Column I Column II A Frederick Griffith P 1952 B Oswald Avery Q British bacteriologist - 1928 C Alfred Hershey & Matha Chase R Radioactive thymidine D Taylor S 1958 E Mathew Messelson & Franklin Stahl T 1933 - 34
343011
If Messelson and Stahl's experiment is continued for five generations in bacteria, the ratio of \(15 \mathrm{~N} / 14 \mathrm{~N}: 14 \mathrm{~N} / 14 \mathrm{~N}\) containing DNA in the fifth generation would be:
1 \(1: 0\)
2 \(4: 0\)
3 \(1: 7\)
4 \(1: 15\)
Explanation:
The solution consists of \(\mathrm{N}^{14}\), therefore after fifth generation there would be \(2 \mathrm{~N}^{15} \mathrm{~N}^{14}\) and 30 \(\mathrm{N}^{14} \mathrm{~N}^{14}\)
BIOXII06: MOLECULAR BASIS OF INHERITANCE
343012
Ten E.coli cells with \({ }^{15} \mathrm{~N}\)-dsDNA are incubated in medium containing \({ }^{14} \mathrm{~N}\) nucleotide. After 60 minutes, how many E.coli cells will have DNA totally free from \({ }^{15} \mathrm{~N}\) ?
1 40 cells
2 60 cells
3 80 cells
4 20 cells
Explanation:
Initially we have \(^{{\rm{15}}}{{\rm{N}}^{{\rm{15}}}}{\rm{N}}\). After 1 st generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \({{\rm{2}}^{{\rm{15}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA After 2nd generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \(2{ }^{15} \mathrm{~N}^{14} \mathrm{~N}\) DNA and \(4{ }^{14} \mathrm{~N}^{14} \mathrm{~N}\) DNA.After 3rd generation in medium containing \(\mathrm{N}^{14}\) nucleotide we will get, \({{\rm{2}}^{{\rm{15}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA and \({\rm{6}}{{\rm{ }}^{{\rm{14}}}}{{\rm{N}}^{{\rm{14}}}}{\rm{N}}\) DNA.