NEET Test Series from KOTA - 10 Papers In MS WORD
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BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342482
The gene for haemophilia is located on ' \(\mathrm{X}\) ' chromosome. Hence it is normally impossible for a:
1 Haemophilic father to pass the gene to his daughter
2 Carrier mother to pass the gene to her daughter
3 Carrier mother to pass the gene to her son
4 Haemophilic father to pass the gene to his son
Explanation:
In males, a single gene for defect is able to express itself as the \(\mathrm{Y}\) chromosome has no allele for this gene. If a male is then he is haemophilic. The males inherit the mutation from their heterozygous mothers. These males reproduce and pass the mutation to their daughters, who are not affected as they inherit a wild-type allele from their mothers. Also, affected males never transmit the mutant allele to their sons.
KCET - 2016
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342483
If father shows normal genotype and mother shows a carrier trait for haemophilia:
1 All the female offspring will be normal.
2 All the female offspring will be carriers.
3 A male offspring has \(50 \%\) chances of active disease.
4 Female offspring has probability of \(50 \%\) to have active disease.
Explanation:
If father shows normal genotype (XY) and mother shows a carrier trait for haemophilia \(\left(\mathrm{XX}^{\mathrm{h}}\right)\) Thus, a male offspring has \(50 \%\) chances of getting active disease, while a female offspring has \(50 \%\) chance of being a carrier.
KCET - 2012
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342484
Match the columns I and II to Hemophilia. Column I Column II A Normal female P \({X^h}{X^h}\) B Carrier female Q \({X^H}{X^H}\) C Diseased female R \({X^H}{X^h}\) D Diseased male S \({X^h}Y\)
1 A – R , B – P , C – Q, D – S
2 A – Q , B – R , C – P, D – S
3 A – P , B – R , C – Q, D – S
4 A – Q , B – P , C – R , D – S
Explanation:
A-Q, B-R, C-P, D-S
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342485
Name the disease in which a single protein that is a part of the cascade of proteins involved in the clotting of blood is affected?
1 Haemophilia
2 Sickle cell anemia
3 Beta-thalasemia
4 Color blindness
Explanation:
Hemophilia- In this disease, a single protein that is a part of the cascade of proteins involved in the clotting of blood is affected. Due to this, in an affected individual a simple cut will result in non-stop bleeding
342482
The gene for haemophilia is located on ' \(\mathrm{X}\) ' chromosome. Hence it is normally impossible for a:
1 Haemophilic father to pass the gene to his daughter
2 Carrier mother to pass the gene to her daughter
3 Carrier mother to pass the gene to her son
4 Haemophilic father to pass the gene to his son
Explanation:
In males, a single gene for defect is able to express itself as the \(\mathrm{Y}\) chromosome has no allele for this gene. If a male is then he is haemophilic. The males inherit the mutation from their heterozygous mothers. These males reproduce and pass the mutation to their daughters, who are not affected as they inherit a wild-type allele from their mothers. Also, affected males never transmit the mutant allele to their sons.
KCET - 2016
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342483
If father shows normal genotype and mother shows a carrier trait for haemophilia:
1 All the female offspring will be normal.
2 All the female offspring will be carriers.
3 A male offspring has \(50 \%\) chances of active disease.
4 Female offspring has probability of \(50 \%\) to have active disease.
Explanation:
If father shows normal genotype (XY) and mother shows a carrier trait for haemophilia \(\left(\mathrm{XX}^{\mathrm{h}}\right)\) Thus, a male offspring has \(50 \%\) chances of getting active disease, while a female offspring has \(50 \%\) chance of being a carrier.
KCET - 2012
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342484
Match the columns I and II to Hemophilia. Column I Column II A Normal female P \({X^h}{X^h}\) B Carrier female Q \({X^H}{X^H}\) C Diseased female R \({X^H}{X^h}\) D Diseased male S \({X^h}Y\)
1 A – R , B – P , C – Q, D – S
2 A – Q , B – R , C – P, D – S
3 A – P , B – R , C – Q, D – S
4 A – Q , B – P , C – R , D – S
Explanation:
A-Q, B-R, C-P, D-S
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342485
Name the disease in which a single protein that is a part of the cascade of proteins involved in the clotting of blood is affected?
1 Haemophilia
2 Sickle cell anemia
3 Beta-thalasemia
4 Color blindness
Explanation:
Hemophilia- In this disease, a single protein that is a part of the cascade of proteins involved in the clotting of blood is affected. Due to this, in an affected individual a simple cut will result in non-stop bleeding
342482
The gene for haemophilia is located on ' \(\mathrm{X}\) ' chromosome. Hence it is normally impossible for a:
1 Haemophilic father to pass the gene to his daughter
2 Carrier mother to pass the gene to her daughter
3 Carrier mother to pass the gene to her son
4 Haemophilic father to pass the gene to his son
Explanation:
In males, a single gene for defect is able to express itself as the \(\mathrm{Y}\) chromosome has no allele for this gene. If a male is then he is haemophilic. The males inherit the mutation from their heterozygous mothers. These males reproduce and pass the mutation to their daughters, who are not affected as they inherit a wild-type allele from their mothers. Also, affected males never transmit the mutant allele to their sons.
KCET - 2016
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342483
If father shows normal genotype and mother shows a carrier trait for haemophilia:
1 All the female offspring will be normal.
2 All the female offspring will be carriers.
3 A male offspring has \(50 \%\) chances of active disease.
4 Female offspring has probability of \(50 \%\) to have active disease.
Explanation:
If father shows normal genotype (XY) and mother shows a carrier trait for haemophilia \(\left(\mathrm{XX}^{\mathrm{h}}\right)\) Thus, a male offspring has \(50 \%\) chances of getting active disease, while a female offspring has \(50 \%\) chance of being a carrier.
KCET - 2012
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342484
Match the columns I and II to Hemophilia. Column I Column II A Normal female P \({X^h}{X^h}\) B Carrier female Q \({X^H}{X^H}\) C Diseased female R \({X^H}{X^h}\) D Diseased male S \({X^h}Y\)
1 A – R , B – P , C – Q, D – S
2 A – Q , B – R , C – P, D – S
3 A – P , B – R , C – Q, D – S
4 A – Q , B – P , C – R , D – S
Explanation:
A-Q, B-R, C-P, D-S
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342485
Name the disease in which a single protein that is a part of the cascade of proteins involved in the clotting of blood is affected?
1 Haemophilia
2 Sickle cell anemia
3 Beta-thalasemia
4 Color blindness
Explanation:
Hemophilia- In this disease, a single protein that is a part of the cascade of proteins involved in the clotting of blood is affected. Due to this, in an affected individual a simple cut will result in non-stop bleeding
342482
The gene for haemophilia is located on ' \(\mathrm{X}\) ' chromosome. Hence it is normally impossible for a:
1 Haemophilic father to pass the gene to his daughter
2 Carrier mother to pass the gene to her daughter
3 Carrier mother to pass the gene to her son
4 Haemophilic father to pass the gene to his son
Explanation:
In males, a single gene for defect is able to express itself as the \(\mathrm{Y}\) chromosome has no allele for this gene. If a male is then he is haemophilic. The males inherit the mutation from their heterozygous mothers. These males reproduce and pass the mutation to their daughters, who are not affected as they inherit a wild-type allele from their mothers. Also, affected males never transmit the mutant allele to their sons.
KCET - 2016
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342483
If father shows normal genotype and mother shows a carrier trait for haemophilia:
1 All the female offspring will be normal.
2 All the female offspring will be carriers.
3 A male offspring has \(50 \%\) chances of active disease.
4 Female offspring has probability of \(50 \%\) to have active disease.
Explanation:
If father shows normal genotype (XY) and mother shows a carrier trait for haemophilia \(\left(\mathrm{XX}^{\mathrm{h}}\right)\) Thus, a male offspring has \(50 \%\) chances of getting active disease, while a female offspring has \(50 \%\) chance of being a carrier.
KCET - 2012
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342484
Match the columns I and II to Hemophilia. Column I Column II A Normal female P \({X^h}{X^h}\) B Carrier female Q \({X^H}{X^H}\) C Diseased female R \({X^H}{X^h}\) D Diseased male S \({X^h}Y\)
1 A – R , B – P , C – Q, D – S
2 A – Q , B – R , C – P, D – S
3 A – P , B – R , C – Q, D – S
4 A – Q , B – P , C – R , D – S
Explanation:
A-Q, B-R, C-P, D-S
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342485
Name the disease in which a single protein that is a part of the cascade of proteins involved in the clotting of blood is affected?
1 Haemophilia
2 Sickle cell anemia
3 Beta-thalasemia
4 Color blindness
Explanation:
Hemophilia- In this disease, a single protein that is a part of the cascade of proteins involved in the clotting of blood is affected. Due to this, in an affected individual a simple cut will result in non-stop bleeding
