QBManager

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342131 Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.

1 A person will have only two of the three alleles.

2 When

I^{A}

and

I^{B}

are present together they express same type of sugar.

3 Allele ‘i’ does not produce any sugar.

4 The gene (I) has three alleles. They express same type of sugar.

Explanation:

When $I^{A}$ and $I^{B}$ and are present together they express same type of sugar.

NEET - 2020

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342132 With regard to the $A B O$ blood typing system, if a man who has type $B$ blood and a woman who has type $O$ blood were to have children, what blood types could the children have?

1

A

or

O

2

B

or

O

3

AB

or

O

4

A, B, AB

or

O

Explanation:

The man has type B blood group; his genotype $l^{B} l^{B}$ can be or $l^{B} i$ .
The woman has type $O$ blood group; her genotype can be ii only.
The blood type of child will be either B or O This is illustrated below;
$\begin{array}{l} l^{B} l^{B} l^{B} i \\ i l^{B} i l^{B} i o r i \\ l^{B} i i l^{B} i i l^{B} i i \\ i i \end{array}$

KCET - 2012

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342133 In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?

1 4

2 6

3 8

4 12

Explanation:

Formula to calculate number of genotype for multiple allelism if
$\frac{n (n + 1)}{2}$
where
$n$ = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342134 The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?

1 3 genotypes ; 4 phenotypes

2 4 genotypes ; 3 phenotypes

3 4 genotypes ; 4 phenotypes

4 3 genotypes ; 3 phenotypes

Explanation:

Husband - IA IB Wife –IA i $I A I^{B} \times I A i$
Genotypes: IA IA, IA IB, IA i, IB i
Blood group : A, AB, B (Phenotype)
$B l o o d g r o u p G e n o t y p e s$
$A$ $I A I A : I A i$
$A B$ $I A I B$
$B$ $I B i$
Hence there are 4 genotypes and 3 phenotypes.

NEET - 2017

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342135 Match the columns I and II.
Column I
Column II
A
Incomplete dominance
P
ABO blood group
B
Co-dominance
Q
Snapdragon
C
Pleiotropy
R
Sickle cell anaemia

1 A – R , B – P , C – Q

2 A – Q , B – R , C – P

3 A – P , B – R , C – Q

4 A – Q , B – P , C – R

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342131 Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.

1 A person will have only two of the three alleles.

2 When

I^{A}

and

I^{B}

are present together they express same type of sugar.

3 Allele ‘i’ does not produce any sugar.

4 The gene (I) has three alleles. They express same type of sugar.

Explanation:

When $I^{A}$ and $I^{B}$ and are present together they express same type of sugar.

NEET - 2020

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342132 With regard to the $A B O$ blood typing system, if a man who has type $B$ blood and a woman who has type $O$ blood were to have children, what blood types could the children have?

1

A

or

O

2

B

or

O

3

AB

or

O

4

A, B, AB

or

O

Explanation:

The man has type B blood group; his genotype $l^{B} l^{B}$ can be or $l^{B} i$ .
The woman has type $O$ blood group; her genotype can be ii only.
The blood type of child will be either B or O This is illustrated below;
$\begin{array}{l} l^{B} l^{B} l^{B} i \\ i l^{B} i l^{B} i o r i \\ l^{B} i i l^{B} i i l^{B} i i \\ i i \end{array}$

KCET - 2012

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342133 In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?

1 4

2 6

3 8

4 12

Explanation:

Formula to calculate number of genotype for multiple allelism if
$\frac{n (n + 1)}{2}$
where
$n$ = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342134 The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?

1 3 genotypes ; 4 phenotypes

2 4 genotypes ; 3 phenotypes

3 4 genotypes ; 4 phenotypes

4 3 genotypes ; 3 phenotypes

Explanation:

Husband - IA IB Wife –IA i $I A I^{B} \times I A i$
Genotypes: IA IA, IA IB, IA i, IB i
Blood group : A, AB, B (Phenotype)
$B l o o d g r o u p G e n o t y p e s$
$A$ $I A I A : I A i$
$A B$ $I A I B$
$B$ $I B i$
Hence there are 4 genotypes and 3 phenotypes.

NEET - 2017

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342135 Match the columns I and II.
Column I
Column II
A
Incomplete dominance
P
ABO blood group
B
Co-dominance
Q
Snapdragon
C
Pleiotropy
R
Sickle cell anaemia

1 A – R , B – P , C – Q

2 A – Q , B – R , C – P

3 A – P , B – R , C – Q

4 A – Q , B – P , C – R

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342131 Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.

1 A person will have only two of the three alleles.

2 When

I^{A}

and

I^{B}

are present together they express same type of sugar.

3 Allele ‘i’ does not produce any sugar.

4 The gene (I) has three alleles. They express same type of sugar.

Explanation:

When $I^{A}$ and $I^{B}$ and are present together they express same type of sugar.

NEET - 2020

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342132 With regard to the $A B O$ blood typing system, if a man who has type $B$ blood and a woman who has type $O$ blood were to have children, what blood types could the children have?

1

A

or

O

2

B

or

O

3

AB

or

O

4

A, B, AB

or

O

Explanation:

The man has type B blood group; his genotype $l^{B} l^{B}$ can be or $l^{B} i$ .
The woman has type $O$ blood group; her genotype can be ii only.
The blood type of child will be either B or O This is illustrated below;
$\begin{array}{l} l^{B} l^{B} l^{B} i \\ i l^{B} i l^{B} i o r i \\ l^{B} i i l^{B} i i l^{B} i i \\ i i \end{array}$

KCET - 2012

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342133 In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?

1 4

2 6

3 8

4 12

Explanation:

Formula to calculate number of genotype for multiple allelism if
$\frac{n (n + 1)}{2}$
where
$n$ = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342134 The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?

1 3 genotypes ; 4 phenotypes

2 4 genotypes ; 3 phenotypes

3 4 genotypes ; 4 phenotypes

4 3 genotypes ; 3 phenotypes

Explanation:

Husband - IA IB Wife –IA i $I A I^{B} \times I A i$
Genotypes: IA IA, IA IB, IA i, IB i
Blood group : A, AB, B (Phenotype)
$B l o o d g r o u p G e n o t y p e s$
$A$ $I A I A : I A i$
$A B$ $I A I B$
$B$ $I B i$
Hence there are 4 genotypes and 3 phenotypes.

NEET - 2017

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342135 Match the columns I and II.
Column I
Column II
A
Incomplete dominance
P
ABO blood group
B
Co-dominance
Q
Snapdragon
C
Pleiotropy
R
Sickle cell anaemia

1 A – R , B – P , C – Q

2 A – Q , B – R , C – P

3 A – P , B – R , C – Q

4 A – Q , B – P , C – R

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342131 Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.

1 A person will have only two of the three alleles.

2 When

I^{A}

and

I^{B}

are present together they express same type of sugar.

3 Allele ‘i’ does not produce any sugar.

4 The gene (I) has three alleles. They express same type of sugar.

Explanation:

When $I^{A}$ and $I^{B}$ and are present together they express same type of sugar.

NEET - 2020

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342132 With regard to the $A B O$ blood typing system, if a man who has type $B$ blood and a woman who has type $O$ blood were to have children, what blood types could the children have?

1

A

or

O

2

B

or

O

3

AB

or

O

4

A, B, AB

or

O

Explanation:

The man has type B blood group; his genotype $l^{B} l^{B}$ can be or $l^{B} i$ .
The woman has type $O$ blood group; her genotype can be ii only.
The blood type of child will be either B or O This is illustrated below;
$\begin{array}{l} l^{B} l^{B} l^{B} i \\ i l^{B} i l^{B} i o r i \\ l^{B} i i l^{B} i i l^{B} i i \\ i i \end{array}$

KCET - 2012

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342133 In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?

1 4

2 6

3 8

4 12

Explanation:

Formula to calculate number of genotype for multiple allelism if
$\frac{n (n + 1)}{2}$
where
$n$ = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342134 The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?

1 3 genotypes ; 4 phenotypes

2 4 genotypes ; 3 phenotypes

3 4 genotypes ; 4 phenotypes

4 3 genotypes ; 3 phenotypes

Explanation:

Husband - IA IB Wife –IA i $I A I^{B} \times I A i$
Genotypes: IA IA, IA IB, IA i, IB i
Blood group : A, AB, B (Phenotype)
$B l o o d g r o u p G e n o t y p e s$
$A$ $I A I A : I A i$
$A B$ $I A I B$
$B$ $I B i$
Hence there are 4 genotypes and 3 phenotypes.

NEET - 2017

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342135 Match the columns I and II.
Column I
Column II
A
Incomplete dominance
P
ABO blood group
B
Co-dominance
Q
Snapdragon
C
Pleiotropy
R
Sickle cell anaemia

1 A – R , B – P , C – Q

2 A – Q , B – R , C – P

3 A – P , B – R , C – Q

4 A – Q , B – P , C – R

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342131 Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.

1 A person will have only two of the three alleles.

2 When

I^{A}

and

I^{B}

are present together they express same type of sugar.

3 Allele ‘i’ does not produce any sugar.

4 The gene (I) has three alleles. They express same type of sugar.

Explanation:

When $I^{A}$ and $I^{B}$ and are present together they express same type of sugar.

NEET - 2020

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342132 With regard to the $A B O$ blood typing system, if a man who has type $B$ blood and a woman who has type $O$ blood were to have children, what blood types could the children have?

1

A

or

O

2

B

or

O

3

AB

or

O

4

A, B, AB

or

O

Explanation:

The man has type B blood group; his genotype $l^{B} l^{B}$ can be or $l^{B} i$ .
The woman has type $O$ blood group; her genotype can be ii only.
The blood type of child will be either B or O This is illustrated below;
$\begin{array}{l} l^{B} l^{B} l^{B} i \\ i l^{B} i l^{B} i o r i \\ l^{B} i i l^{B} i i l^{B} i i \\ i i \end{array}$

KCET - 2012

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342133 In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?

1 4

2 6

3 8

4 12

Explanation:

Formula to calculate number of genotype for multiple allelism if
$\frac{n (n + 1)}{2}$
where
$n$ = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342134 The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?

1 3 genotypes ; 4 phenotypes

2 4 genotypes ; 3 phenotypes

3 4 genotypes ; 4 phenotypes

4 3 genotypes ; 3 phenotypes

Explanation:

Husband - IA IB Wife –IA i $I A I^{B} \times I A i$
Genotypes: IA IA, IA IB, IA i, IB i
Blood group : A, AB, B (Phenotype)
$B l o o d g r o u p G e n o t y p e s$
$A$ $I A I A : I A i$
$A B$ $I A I B$
$B$ $I B i$
Hence there are 4 genotypes and 3 phenotypes.

NEET - 2017

BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION

342135 Match the columns I and II.
Column I
Column II
A
Incomplete dominance
P
ABO blood group
B
Co-dominance
Q
Snapdragon
C
Pleiotropy
R
Sickle cell anaemia

1 A – R , B – P , C – Q

2 A – Q , B – R , C – P

3 A – P , B – R , C – Q

4 A – Q , B – P , C – R

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