342131
Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.
1 A person will have only two of the three alleles.
2 When \({I^A}\) and \({I^B}\) are present together they express same type of sugar.
3 Allele ‘i’ does not produce any sugar.
4 The gene (I) has three alleles. They express same type of sugar.
Explanation:
When \({I^A}\) and \({I^B}\) and are present together they express same type of sugar.
NEET - 2020
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342132
With regard to the \({\rm{A B O}}\) blood typing system, if a man who has type \(\mathrm{B}\) blood and a woman who has type \(\mathrm{O}\) blood were to have children, what blood types could the children have?
1 \(\mathrm{A}\) or \(\mathrm{O}\)
2 \(\mathrm{B}\) or \(\mathrm{O}\)
3 \(\mathrm{AB}\) or \(\mathrm{O}\)
4 \(\mathrm{A}, \mathrm{B}, \mathrm{AB}\) or \(\mathrm{O}\)
Explanation:
The man has type B blood group; his genotype \(l^{B} l^{B}\) can be or \(l^{B} \mathrm{i}\). The woman has type \(\mathrm{O}\) blood group; her genotype can be ii only. The blood type of child will be either B or O This is illustrated below; \[\begin{array}{l} {l^B}\;\;\;\;\;{l^B}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}\;\;\;\;\;\;\;{\rm{i}}\\ {\rm{i}}\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;{\rm{or}}\;\;{\rm{i}}\\ {l^B}\;\;\;\;\;{\rm{ii}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;{\rm{i}}{l^B}{\rm{ii}}\;\\ {\rm{ii}}\; \end{array}\]
KCET - 2012
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342133
In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?
1 4
2 6
3 8
4 12
Explanation:
Formula to calculate number of genotype for multiple allelism if \(\frac{{n(n + 1)}}{2}\) where \(n\) = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342134
The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?
1 3 genotypes ; 4 phenotypes
2 4 genotypes ; 3 phenotypes
3 4 genotypes ; 4 phenotypes
4 3 genotypes ; 3 phenotypes
Explanation:
Husband - IA IB Wife –IA i \({\rm{IA{I^B} \times IAi}}\) Genotypes: IA IA, IA IB, IA i, IB i Blood group : A, AB, B (Phenotype) \(Blood\;group\;\;\;\;\;\;\;Genotypes\) \(A\) \(IA\;IA:IAi\) \(AB\) \(IA\;IB\) \(B\) \(IBi\) Hence there are 4 genotypes and 3 phenotypes.
NEET - 2017
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342135
Match the columns I and II. Column I Column II A Incomplete dominance P ABO blood group B Co-dominance Q Snapdragon C Pleiotropy R Sickle cell anaemia
342131
Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.
1 A person will have only two of the three alleles.
2 When \({I^A}\) and \({I^B}\) are present together they express same type of sugar.
3 Allele ‘i’ does not produce any sugar.
4 The gene (I) has three alleles. They express same type of sugar.
Explanation:
When \({I^A}\) and \({I^B}\) and are present together they express same type of sugar.
NEET - 2020
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342132
With regard to the \({\rm{A B O}}\) blood typing system, if a man who has type \(\mathrm{B}\) blood and a woman who has type \(\mathrm{O}\) blood were to have children, what blood types could the children have?
1 \(\mathrm{A}\) or \(\mathrm{O}\)
2 \(\mathrm{B}\) or \(\mathrm{O}\)
3 \(\mathrm{AB}\) or \(\mathrm{O}\)
4 \(\mathrm{A}, \mathrm{B}, \mathrm{AB}\) or \(\mathrm{O}\)
Explanation:
The man has type B blood group; his genotype \(l^{B} l^{B}\) can be or \(l^{B} \mathrm{i}\). The woman has type \(\mathrm{O}\) blood group; her genotype can be ii only. The blood type of child will be either B or O This is illustrated below; \[\begin{array}{l} {l^B}\;\;\;\;\;{l^B}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}\;\;\;\;\;\;\;{\rm{i}}\\ {\rm{i}}\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;{\rm{or}}\;\;{\rm{i}}\\ {l^B}\;\;\;\;\;{\rm{ii}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;{\rm{i}}{l^B}{\rm{ii}}\;\\ {\rm{ii}}\; \end{array}\]
KCET - 2012
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342133
In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?
1 4
2 6
3 8
4 12
Explanation:
Formula to calculate number of genotype for multiple allelism if \(\frac{{n(n + 1)}}{2}\) where \(n\) = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342134
The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?
1 3 genotypes ; 4 phenotypes
2 4 genotypes ; 3 phenotypes
3 4 genotypes ; 4 phenotypes
4 3 genotypes ; 3 phenotypes
Explanation:
Husband - IA IB Wife –IA i \({\rm{IA{I^B} \times IAi}}\) Genotypes: IA IA, IA IB, IA i, IB i Blood group : A, AB, B (Phenotype) \(Blood\;group\;\;\;\;\;\;\;Genotypes\) \(A\) \(IA\;IA:IAi\) \(AB\) \(IA\;IB\) \(B\) \(IBi\) Hence there are 4 genotypes and 3 phenotypes.
NEET - 2017
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342135
Match the columns I and II. Column I Column II A Incomplete dominance P ABO blood group B Co-dominance Q Snapdragon C Pleiotropy R Sickle cell anaemia
NEET Test Series from KOTA - 10 Papers In MS WORD
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BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342131
Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.
1 A person will have only two of the three alleles.
2 When \({I^A}\) and \({I^B}\) are present together they express same type of sugar.
3 Allele ‘i’ does not produce any sugar.
4 The gene (I) has three alleles. They express same type of sugar.
Explanation:
When \({I^A}\) and \({I^B}\) and are present together they express same type of sugar.
NEET - 2020
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342132
With regard to the \({\rm{A B O}}\) blood typing system, if a man who has type \(\mathrm{B}\) blood and a woman who has type \(\mathrm{O}\) blood were to have children, what blood types could the children have?
1 \(\mathrm{A}\) or \(\mathrm{O}\)
2 \(\mathrm{B}\) or \(\mathrm{O}\)
3 \(\mathrm{AB}\) or \(\mathrm{O}\)
4 \(\mathrm{A}, \mathrm{B}, \mathrm{AB}\) or \(\mathrm{O}\)
Explanation:
The man has type B blood group; his genotype \(l^{B} l^{B}\) can be or \(l^{B} \mathrm{i}\). The woman has type \(\mathrm{O}\) blood group; her genotype can be ii only. The blood type of child will be either B or O This is illustrated below; \[\begin{array}{l} {l^B}\;\;\;\;\;{l^B}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}\;\;\;\;\;\;\;{\rm{i}}\\ {\rm{i}}\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;{\rm{or}}\;\;{\rm{i}}\\ {l^B}\;\;\;\;\;{\rm{ii}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;{\rm{i}}{l^B}{\rm{ii}}\;\\ {\rm{ii}}\; \end{array}\]
KCET - 2012
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342133
In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?
1 4
2 6
3 8
4 12
Explanation:
Formula to calculate number of genotype for multiple allelism if \(\frac{{n(n + 1)}}{2}\) where \(n\) = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342134
The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?
1 3 genotypes ; 4 phenotypes
2 4 genotypes ; 3 phenotypes
3 4 genotypes ; 4 phenotypes
4 3 genotypes ; 3 phenotypes
Explanation:
Husband - IA IB Wife –IA i \({\rm{IA{I^B} \times IAi}}\) Genotypes: IA IA, IA IB, IA i, IB i Blood group : A, AB, B (Phenotype) \(Blood\;group\;\;\;\;\;\;\;Genotypes\) \(A\) \(IA\;IA:IAi\) \(AB\) \(IA\;IB\) \(B\) \(IBi\) Hence there are 4 genotypes and 3 phenotypes.
NEET - 2017
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342135
Match the columns I and II. Column I Column II A Incomplete dominance P ABO blood group B Co-dominance Q Snapdragon C Pleiotropy R Sickle cell anaemia
342131
Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.
1 A person will have only two of the three alleles.
2 When \({I^A}\) and \({I^B}\) are present together they express same type of sugar.
3 Allele ‘i’ does not produce any sugar.
4 The gene (I) has three alleles. They express same type of sugar.
Explanation:
When \({I^A}\) and \({I^B}\) and are present together they express same type of sugar.
NEET - 2020
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342132
With regard to the \({\rm{A B O}}\) blood typing system, if a man who has type \(\mathrm{B}\) blood and a woman who has type \(\mathrm{O}\) blood were to have children, what blood types could the children have?
1 \(\mathrm{A}\) or \(\mathrm{O}\)
2 \(\mathrm{B}\) or \(\mathrm{O}\)
3 \(\mathrm{AB}\) or \(\mathrm{O}\)
4 \(\mathrm{A}, \mathrm{B}, \mathrm{AB}\) or \(\mathrm{O}\)
Explanation:
The man has type B blood group; his genotype \(l^{B} l^{B}\) can be or \(l^{B} \mathrm{i}\). The woman has type \(\mathrm{O}\) blood group; her genotype can be ii only. The blood type of child will be either B or O This is illustrated below; \[\begin{array}{l} {l^B}\;\;\;\;\;{l^B}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}\;\;\;\;\;\;\;{\rm{i}}\\ {\rm{i}}\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;{\rm{or}}\;\;{\rm{i}}\\ {l^B}\;\;\;\;\;{\rm{ii}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;{\rm{i}}{l^B}{\rm{ii}}\;\\ {\rm{ii}}\; \end{array}\]
KCET - 2012
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342133
In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?
1 4
2 6
3 8
4 12
Explanation:
Formula to calculate number of genotype for multiple allelism if \(\frac{{n(n + 1)}}{2}\) where \(n\) = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342134
The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?
1 3 genotypes ; 4 phenotypes
2 4 genotypes ; 3 phenotypes
3 4 genotypes ; 4 phenotypes
4 3 genotypes ; 3 phenotypes
Explanation:
Husband - IA IB Wife –IA i \({\rm{IA{I^B} \times IAi}}\) Genotypes: IA IA, IA IB, IA i, IB i Blood group : A, AB, B (Phenotype) \(Blood\;group\;\;\;\;\;\;\;Genotypes\) \(A\) \(IA\;IA:IAi\) \(AB\) \(IA\;IB\) \(B\) \(IBi\) Hence there are 4 genotypes and 3 phenotypes.
NEET - 2017
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342135
Match the columns I and II. Column I Column II A Incomplete dominance P ABO blood group B Co-dominance Q Snapdragon C Pleiotropy R Sickle cell anaemia
342131
Identify the wrong statement with reference to the gene ‘I’ that controls ABO blood groups.
1 A person will have only two of the three alleles.
2 When \({I^A}\) and \({I^B}\) are present together they express same type of sugar.
3 Allele ‘i’ does not produce any sugar.
4 The gene (I) has three alleles. They express same type of sugar.
Explanation:
When \({I^A}\) and \({I^B}\) and are present together they express same type of sugar.
NEET - 2020
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342132
With regard to the \({\rm{A B O}}\) blood typing system, if a man who has type \(\mathrm{B}\) blood and a woman who has type \(\mathrm{O}\) blood were to have children, what blood types could the children have?
1 \(\mathrm{A}\) or \(\mathrm{O}\)
2 \(\mathrm{B}\) or \(\mathrm{O}\)
3 \(\mathrm{AB}\) or \(\mathrm{O}\)
4 \(\mathrm{A}, \mathrm{B}, \mathrm{AB}\) or \(\mathrm{O}\)
Explanation:
The man has type B blood group; his genotype \(l^{B} l^{B}\) can be or \(l^{B} \mathrm{i}\). The woman has type \(\mathrm{O}\) blood group; her genotype can be ii only. The blood type of child will be either B or O This is illustrated below; \[\begin{array}{l} {l^B}\;\;\;\;\;{l^B}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}\;\;\;\;\;\;\;{\rm{i}}\\ {\rm{i}}\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;{\rm{or}}\;\;{\rm{i}}\\ {l^B}\;\;\;\;\;{\rm{ii}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{l^B}{\rm{i}}\;\;\;\;\;\;\;{\rm{i}}{l^B}{\rm{ii}}\;\\ {\rm{ii}}\; \end{array}\]
KCET - 2012
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342133
In the human ABO blood system, the alleles A and B are dominant to O. What will be number of different possible genotype?
1 4
2 6
3 8
4 12
Explanation:
Formula to calculate number of genotype for multiple allelism if \(\frac{{n(n + 1)}}{2}\) where \(n\) = no. of alleles controlling the trait. Thus, the number of different possible genotype would be 6 viz., AA, AB, Ai, BB, Bi and ii.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342134
The genotypes of a husband and wife are IAIB and IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible?
1 3 genotypes ; 4 phenotypes
2 4 genotypes ; 3 phenotypes
3 4 genotypes ; 4 phenotypes
4 3 genotypes ; 3 phenotypes
Explanation:
Husband - IA IB Wife –IA i \({\rm{IA{I^B} \times IAi}}\) Genotypes: IA IA, IA IB, IA i, IB i Blood group : A, AB, B (Phenotype) \(Blood\;group\;\;\;\;\;\;\;Genotypes\) \(A\) \(IA\;IA:IAi\) \(AB\) \(IA\;IB\) \(B\) \(IBi\) Hence there are 4 genotypes and 3 phenotypes.
NEET - 2017
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342135
Match the columns I and II. Column I Column II A Incomplete dominance P ABO blood group B Co-dominance Q Snapdragon C Pleiotropy R Sickle cell anaemia