341474
Isogamous condition with non-flagellated gametes is found in :
1 Spirogyra
2 Volvox
3 Fucus
4 Chlamydomonas
Explanation:
The isogamy with non-flagellated gametes is found in Spirogyra.
BIOXII01: REPRODUCTION IN ORGANISMS
341475
Which one of the following shows isogamy with non-flagellated gametes?
1 Sargassum
2 Ectocarpus
3 Ulothrix
4 Spirogyra
Explanation:
Spirogyra grows as filaments of cells. When two filaments of opposing mating types come close together, the cells form conjugation tubes between the filaments. Once the tubes are formed, one cell balls up and crawls through the tube into the other cell to fuse with it, forming a zygote. Conjugation is a type of isogamy.
AIPMT - 2014
BIOXII01: REPRODUCTION IN ORGANISMS
341476
Select the example/s of hermaphrodite organisms among these.
1 Earthworm
2 Tapeworm
3 Leech
4 All of these
Explanation:
All are bisexual
BIOXII01: REPRODUCTION IN ORGANISMS
341477
If primary spermatocyte have \(2 n=16\) chromosomes during first meiotic division, in such case how many chromatids could be present in each secondary spermatocyte?
1 32
2 24
3 16
4 8
Explanation:
Spermatogonium (2N) divides by mitosis and we get primary spermatocyte \((2 \mathrm{~N})\) and by meiosis from one primary spermatocyte \((2 \mathrm{~N})\), we get two secondary spermatocytes (N). Now, the number of chromosomes present in secondary spermatocyte is \(\mathrm{N}\) and in one chromosome, there are two sister chromatids. So, if there are 16 chromosomes in primary spermatocyte, the secondary spermatocyte will have half the number i.e.; 8 chromsomes and the chromatids will be \(8 * 2=16\).
341474
Isogamous condition with non-flagellated gametes is found in :
1 Spirogyra
2 Volvox
3 Fucus
4 Chlamydomonas
Explanation:
The isogamy with non-flagellated gametes is found in Spirogyra.
BIOXII01: REPRODUCTION IN ORGANISMS
341475
Which one of the following shows isogamy with non-flagellated gametes?
1 Sargassum
2 Ectocarpus
3 Ulothrix
4 Spirogyra
Explanation:
Spirogyra grows as filaments of cells. When two filaments of opposing mating types come close together, the cells form conjugation tubes between the filaments. Once the tubes are formed, one cell balls up and crawls through the tube into the other cell to fuse with it, forming a zygote. Conjugation is a type of isogamy.
AIPMT - 2014
BIOXII01: REPRODUCTION IN ORGANISMS
341476
Select the example/s of hermaphrodite organisms among these.
1 Earthworm
2 Tapeworm
3 Leech
4 All of these
Explanation:
All are bisexual
BIOXII01: REPRODUCTION IN ORGANISMS
341477
If primary spermatocyte have \(2 n=16\) chromosomes during first meiotic division, in such case how many chromatids could be present in each secondary spermatocyte?
1 32
2 24
3 16
4 8
Explanation:
Spermatogonium (2N) divides by mitosis and we get primary spermatocyte \((2 \mathrm{~N})\) and by meiosis from one primary spermatocyte \((2 \mathrm{~N})\), we get two secondary spermatocytes (N). Now, the number of chromosomes present in secondary spermatocyte is \(\mathrm{N}\) and in one chromosome, there are two sister chromatids. So, if there are 16 chromosomes in primary spermatocyte, the secondary spermatocyte will have half the number i.e.; 8 chromsomes and the chromatids will be \(8 * 2=16\).
341474
Isogamous condition with non-flagellated gametes is found in :
1 Spirogyra
2 Volvox
3 Fucus
4 Chlamydomonas
Explanation:
The isogamy with non-flagellated gametes is found in Spirogyra.
BIOXII01: REPRODUCTION IN ORGANISMS
341475
Which one of the following shows isogamy with non-flagellated gametes?
1 Sargassum
2 Ectocarpus
3 Ulothrix
4 Spirogyra
Explanation:
Spirogyra grows as filaments of cells. When two filaments of opposing mating types come close together, the cells form conjugation tubes between the filaments. Once the tubes are formed, one cell balls up and crawls through the tube into the other cell to fuse with it, forming a zygote. Conjugation is a type of isogamy.
AIPMT - 2014
BIOXII01: REPRODUCTION IN ORGANISMS
341476
Select the example/s of hermaphrodite organisms among these.
1 Earthworm
2 Tapeworm
3 Leech
4 All of these
Explanation:
All are bisexual
BIOXII01: REPRODUCTION IN ORGANISMS
341477
If primary spermatocyte have \(2 n=16\) chromosomes during first meiotic division, in such case how many chromatids could be present in each secondary spermatocyte?
1 32
2 24
3 16
4 8
Explanation:
Spermatogonium (2N) divides by mitosis and we get primary spermatocyte \((2 \mathrm{~N})\) and by meiosis from one primary spermatocyte \((2 \mathrm{~N})\), we get two secondary spermatocytes (N). Now, the number of chromosomes present in secondary spermatocyte is \(\mathrm{N}\) and in one chromosome, there are two sister chromatids. So, if there are 16 chromosomes in primary spermatocyte, the secondary spermatocyte will have half the number i.e.; 8 chromsomes and the chromatids will be \(8 * 2=16\).
341474
Isogamous condition with non-flagellated gametes is found in :
1 Spirogyra
2 Volvox
3 Fucus
4 Chlamydomonas
Explanation:
The isogamy with non-flagellated gametes is found in Spirogyra.
BIOXII01: REPRODUCTION IN ORGANISMS
341475
Which one of the following shows isogamy with non-flagellated gametes?
1 Sargassum
2 Ectocarpus
3 Ulothrix
4 Spirogyra
Explanation:
Spirogyra grows as filaments of cells. When two filaments of opposing mating types come close together, the cells form conjugation tubes between the filaments. Once the tubes are formed, one cell balls up and crawls through the tube into the other cell to fuse with it, forming a zygote. Conjugation is a type of isogamy.
AIPMT - 2014
BIOXII01: REPRODUCTION IN ORGANISMS
341476
Select the example/s of hermaphrodite organisms among these.
1 Earthworm
2 Tapeworm
3 Leech
4 All of these
Explanation:
All are bisexual
BIOXII01: REPRODUCTION IN ORGANISMS
341477
If primary spermatocyte have \(2 n=16\) chromosomes during first meiotic division, in such case how many chromatids could be present in each secondary spermatocyte?
1 32
2 24
3 16
4 8
Explanation:
Spermatogonium (2N) divides by mitosis and we get primary spermatocyte \((2 \mathrm{~N})\) and by meiosis from one primary spermatocyte \((2 \mathrm{~N})\), we get two secondary spermatocytes (N). Now, the number of chromosomes present in secondary spermatocyte is \(\mathrm{N}\) and in one chromosome, there are two sister chromatids. So, if there are 16 chromosomes in primary spermatocyte, the secondary spermatocyte will have half the number i.e.; 8 chromsomes and the chromatids will be \(8 * 2=16\).
