The increasing order of intermolecular forces in different polymers is elastomers \( < \) plastics \( < \) fibres. So, in order to solve such problem, first classify the given polymer into the above classes and then arrange them in increasing order of forces. Neoprene (synthetic rubber) is an elastomer, buna-S is also an elastomer, polythene is plastic and nylon-6, 6 is a fibre. So, the increasing order of intermolecular forces of the given polymer is : Neoprene \( < \) buna-S \( < \) polythene\( < \text { nylon-6, } 6\)
CHXII15:POLYMERS
325009
Which of the following polymer has strongest intermolecular forces of attraction?
1 Terylene
2 Polythene
3 Polystryene
4 Neoprene
Explanation:
Increasing order of inter-molecular forces in polymers is fibres \(>\) thermoplastic polymers \(>\) elastomers. Terylene is a fibre.
KCET - 2020
CHXII15:POLYMERS
325010
Fibres have the characteristic features like
1 Thread forming solids
2 High tensile strength and high modulus
3 Crystalline nature
4 All of the above
Explanation:
Fibres are basically thread forming solids which possess high tensile strength and high modulus. This is due to the strong intermolecular forces like Hydrogen bonding. These strong forces also lead to close packing of chains and hence impart crystalline structure. E.g., terylene, Nylon-6,6 etc.
The increasing order of intermolecular forces in different polymers is elastomers \( < \) plastics \( < \) fibres. So, in order to solve such problem, first classify the given polymer into the above classes and then arrange them in increasing order of forces. Neoprene (synthetic rubber) is an elastomer, buna-S is also an elastomer, polythene is plastic and nylon-6, 6 is a fibre. So, the increasing order of intermolecular forces of the given polymer is : Neoprene \( < \) buna-S \( < \) polythene\( < \text { nylon-6, } 6\)
CHXII15:POLYMERS
325009
Which of the following polymer has strongest intermolecular forces of attraction?
1 Terylene
2 Polythene
3 Polystryene
4 Neoprene
Explanation:
Increasing order of inter-molecular forces in polymers is fibres \(>\) thermoplastic polymers \(>\) elastomers. Terylene is a fibre.
KCET - 2020
CHXII15:POLYMERS
325010
Fibres have the characteristic features like
1 Thread forming solids
2 High tensile strength and high modulus
3 Crystalline nature
4 All of the above
Explanation:
Fibres are basically thread forming solids which possess high tensile strength and high modulus. This is due to the strong intermolecular forces like Hydrogen bonding. These strong forces also lead to close packing of chains and hence impart crystalline structure. E.g., terylene, Nylon-6,6 etc.
The increasing order of intermolecular forces in different polymers is elastomers \( < \) plastics \( < \) fibres. So, in order to solve such problem, first classify the given polymer into the above classes and then arrange them in increasing order of forces. Neoprene (synthetic rubber) is an elastomer, buna-S is also an elastomer, polythene is plastic and nylon-6, 6 is a fibre. So, the increasing order of intermolecular forces of the given polymer is : Neoprene \( < \) buna-S \( < \) polythene\( < \text { nylon-6, } 6\)
CHXII15:POLYMERS
325009
Which of the following polymer has strongest intermolecular forces of attraction?
1 Terylene
2 Polythene
3 Polystryene
4 Neoprene
Explanation:
Increasing order of inter-molecular forces in polymers is fibres \(>\) thermoplastic polymers \(>\) elastomers. Terylene is a fibre.
KCET - 2020
CHXII15:POLYMERS
325010
Fibres have the characteristic features like
1 Thread forming solids
2 High tensile strength and high modulus
3 Crystalline nature
4 All of the above
Explanation:
Fibres are basically thread forming solids which possess high tensile strength and high modulus. This is due to the strong intermolecular forces like Hydrogen bonding. These strong forces also lead to close packing of chains and hence impart crystalline structure. E.g., terylene, Nylon-6,6 etc.
The increasing order of intermolecular forces in different polymers is elastomers \( < \) plastics \( < \) fibres. So, in order to solve such problem, first classify the given polymer into the above classes and then arrange them in increasing order of forces. Neoprene (synthetic rubber) is an elastomer, buna-S is also an elastomer, polythene is plastic and nylon-6, 6 is a fibre. So, the increasing order of intermolecular forces of the given polymer is : Neoprene \( < \) buna-S \( < \) polythene\( < \text { nylon-6, } 6\)
CHXII15:POLYMERS
325009
Which of the following polymer has strongest intermolecular forces of attraction?
1 Terylene
2 Polythene
3 Polystryene
4 Neoprene
Explanation:
Increasing order of inter-molecular forces in polymers is fibres \(>\) thermoplastic polymers \(>\) elastomers. Terylene is a fibre.
KCET - 2020
CHXII15:POLYMERS
325010
Fibres have the characteristic features like
1 Thread forming solids
2 High tensile strength and high modulus
3 Crystalline nature
4 All of the above
Explanation:
Fibres are basically thread forming solids which possess high tensile strength and high modulus. This is due to the strong intermolecular forces like Hydrogen bonding. These strong forces also lead to close packing of chains and hence impart crystalline structure. E.g., terylene, Nylon-6,6 etc.