CHXII15:POLYMERS
324962
\({\text{CHC}}{{\text{l}}_{\text{3}}}\xrightarrow[{{\text{HF}}}]{{{\text{Sb}}{{\text{F}}_{\text{3}}}}}{\text{CH}}{{\text{F}}_{\text{2}}}{\text{Cl}}\xrightarrow{{{\text{1010K}}}}{\text{X + 2HCl}}\)
Identify the compound (X).
1 \({{\rm{F}}_{\rm{2}}}{\rm{C = C}}{{\rm{F}}_{\rm{2}}}\)
2 \({\rm{CIFC = CFCI}}\)
3 \({{\rm{F}}_{\rm{2}}}{\rm{C = CFCI}}\)
4 \({{\text{F}}_{\text{2}}}{\text{C = CC}}{{\text{l}}_{\text{2}}}\)
Explanation:
\({\text{CH}}{{\text{F}}_{\text{2}}}{\text{Cl}}\xrightarrow{{{{10}^ - }10K}}{\text{C}}{{\text{F}}_{\text{2}}}{\text{ = C}}{{\text{F}}_{\text{2}}}{\text{ + 2HCl}}\)
