Glucose
CHXII14:BIOMOLECULES

324644 \({\mathrm{\quad \alpha-\mathrm{D}-(+)-}}\) glucose and \({\mathrm{\beta-\mathrm{D}-(+)-}}\) glucose are

1 Enantiomers
2 Conformers
3 Epimers
4 Anomers
CHXII14:BIOMOLECULES

324645 \[{\text{D}} - ( + ) - {\text{Glyceraldehyde}}\xrightarrow[\begin{subarray}{l}
({\text{ii}})\,\,{{\text{H}}_2}{\text{O}}/{{\text{H}}^ + } \\
({\text{iii}})\,\,\,{\text{HN}}{{\text{O}}_3}
\end{subarray} ]{{({\text{i}})\,\,{\text{HCN}}}}\]
The products formed in the above reaction are

1 two optically active products
2 two optically inactive products
3 one optically active and one meso product
4 one optically inactive and one meso product.
CHXII14:BIOMOLECULES

324646 supporting img
The incorrect statement regarding the given structure is

1 has 4 asymmetric carbon atoms
2 will coexist in equilibrium with 2 other cyclic structures
3 can be oxidized to a dicarboxylic acid with \({\mathrm{\mathrm{Br}_{2}}}\) water
4 despite the presence of \(-\)CHO does not give Schiff's test.
CHXII14:BIOMOLECULES

324647 Assertion :
Glucose does not give 2, 4 - DNP test
Reason :
Glucose exists in cyclic hemiacetal form

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are correct.
CHXII14:BIOMOLECULES

324644 \({\mathrm{\quad \alpha-\mathrm{D}-(+)-}}\) glucose and \({\mathrm{\beta-\mathrm{D}-(+)-}}\) glucose are

1 Enantiomers
2 Conformers
3 Epimers
4 Anomers
CHXII14:BIOMOLECULES

324645 \[{\text{D}} - ( + ) - {\text{Glyceraldehyde}}\xrightarrow[\begin{subarray}{l}
({\text{ii}})\,\,{{\text{H}}_2}{\text{O}}/{{\text{H}}^ + } \\
({\text{iii}})\,\,\,{\text{HN}}{{\text{O}}_3}
\end{subarray} ]{{({\text{i}})\,\,{\text{HCN}}}}\]
The products formed in the above reaction are

1 two optically active products
2 two optically inactive products
3 one optically active and one meso product
4 one optically inactive and one meso product.
CHXII14:BIOMOLECULES

324646 supporting img
The incorrect statement regarding the given structure is

1 has 4 asymmetric carbon atoms
2 will coexist in equilibrium with 2 other cyclic structures
3 can be oxidized to a dicarboxylic acid with \({\mathrm{\mathrm{Br}_{2}}}\) water
4 despite the presence of \(-\)CHO does not give Schiff's test.
CHXII14:BIOMOLECULES

324647 Assertion :
Glucose does not give 2, 4 - DNP test
Reason :
Glucose exists in cyclic hemiacetal form

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are correct.
CHXII14:BIOMOLECULES

324644 \({\mathrm{\quad \alpha-\mathrm{D}-(+)-}}\) glucose and \({\mathrm{\beta-\mathrm{D}-(+)-}}\) glucose are

1 Enantiomers
2 Conformers
3 Epimers
4 Anomers
CHXII14:BIOMOLECULES

324645 \[{\text{D}} - ( + ) - {\text{Glyceraldehyde}}\xrightarrow[\begin{subarray}{l}
({\text{ii}})\,\,{{\text{H}}_2}{\text{O}}/{{\text{H}}^ + } \\
({\text{iii}})\,\,\,{\text{HN}}{{\text{O}}_3}
\end{subarray} ]{{({\text{i}})\,\,{\text{HCN}}}}\]
The products formed in the above reaction are

1 two optically active products
2 two optically inactive products
3 one optically active and one meso product
4 one optically inactive and one meso product.
CHXII14:BIOMOLECULES

324646 supporting img
The incorrect statement regarding the given structure is

1 has 4 asymmetric carbon atoms
2 will coexist in equilibrium with 2 other cyclic structures
3 can be oxidized to a dicarboxylic acid with \({\mathrm{\mathrm{Br}_{2}}}\) water
4 despite the presence of \(-\)CHO does not give Schiff's test.
CHXII14:BIOMOLECULES

324647 Assertion :
Glucose does not give 2, 4 - DNP test
Reason :
Glucose exists in cyclic hemiacetal form

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are correct.
CHXII14:BIOMOLECULES

324644 \({\mathrm{\quad \alpha-\mathrm{D}-(+)-}}\) glucose and \({\mathrm{\beta-\mathrm{D}-(+)-}}\) glucose are

1 Enantiomers
2 Conformers
3 Epimers
4 Anomers
CHXII14:BIOMOLECULES

324645 \[{\text{D}} - ( + ) - {\text{Glyceraldehyde}}\xrightarrow[\begin{subarray}{l}
({\text{ii}})\,\,{{\text{H}}_2}{\text{O}}/{{\text{H}}^ + } \\
({\text{iii}})\,\,\,{\text{HN}}{{\text{O}}_3}
\end{subarray} ]{{({\text{i}})\,\,{\text{HCN}}}}\]
The products formed in the above reaction are

1 two optically active products
2 two optically inactive products
3 one optically active and one meso product
4 one optically inactive and one meso product.
CHXII14:BIOMOLECULES

324646 supporting img
The incorrect statement regarding the given structure is

1 has 4 asymmetric carbon atoms
2 will coexist in equilibrium with 2 other cyclic structures
3 can be oxidized to a dicarboxylic acid with \({\mathrm{\mathrm{Br}_{2}}}\) water
4 despite the presence of \(-\)CHO does not give Schiff's test.
CHXII14:BIOMOLECULES

324647 Assertion :
Glucose does not give 2, 4 - DNP test
Reason :
Glucose exists in cyclic hemiacetal form

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are correct.