324861
Which is \(\mathrm{C}\)-terminal residue in glycyl alanine?
1 Alanine
2 Glutamine
3 Arginine
4 Glycine
Explanation:
In the dipeptide glycylalanine, glycine residue is \(\mathrm{N}\)-terminal and alanine residue is \(\mathrm{C}\)-terminal.
MHTCET - 2021
CHXII14:BIOMOLECULES
324862
In the following polypeptide sequence Arg- Gly - Cys - Leu, C terminal is:
1 \(\operatorname{Arg}\)
2 Cys
3 Leu
4 Gly
Explanation:
In polypeptides , starting aminoacid is named as N-terminal and end amino acid is C-terminal \(\mathop {{\text{Arg}}}\limits_{{\text{N - terminal}}} - {\text{Gly}} - {\text{Cys}} - \mathop {{\text{Leu}}}\limits_{{\text{C - terminal}}} \)
CHXII14:BIOMOLECULES
324863
The sequence in which the \(\mathrm{\alpha}\) - amino acids are linked to one another in a protein molecule is called its
1 Primary structure
2 Secondary structure
3 Tertiary structure
4 Quarternary structure
Explanation:
Primary structure
CHXII14:BIOMOLECULES
324864
The number of sub units present in haemoglobin are
1 2
2 3
3 4
4 5
Explanation:
One molecule of haemoglobin has four heme groups and each of them can take up one molecule of oxygen. Thus, one molecule of haemoglobin can combine with four molecules of \(\mathrm{O}_{2}\) to form oxyhaemoglobin
AIIMS - 2013
CHXII14:BIOMOLECULES
324865
The helical structure of protein is stabilised by
324861
Which is \(\mathrm{C}\)-terminal residue in glycyl alanine?
1 Alanine
2 Glutamine
3 Arginine
4 Glycine
Explanation:
In the dipeptide glycylalanine, glycine residue is \(\mathrm{N}\)-terminal and alanine residue is \(\mathrm{C}\)-terminal.
MHTCET - 2021
CHXII14:BIOMOLECULES
324862
In the following polypeptide sequence Arg- Gly - Cys - Leu, C terminal is:
1 \(\operatorname{Arg}\)
2 Cys
3 Leu
4 Gly
Explanation:
In polypeptides , starting aminoacid is named as N-terminal and end amino acid is C-terminal \(\mathop {{\text{Arg}}}\limits_{{\text{N - terminal}}} - {\text{Gly}} - {\text{Cys}} - \mathop {{\text{Leu}}}\limits_{{\text{C - terminal}}} \)
CHXII14:BIOMOLECULES
324863
The sequence in which the \(\mathrm{\alpha}\) - amino acids are linked to one another in a protein molecule is called its
1 Primary structure
2 Secondary structure
3 Tertiary structure
4 Quarternary structure
Explanation:
Primary structure
CHXII14:BIOMOLECULES
324864
The number of sub units present in haemoglobin are
1 2
2 3
3 4
4 5
Explanation:
One molecule of haemoglobin has four heme groups and each of them can take up one molecule of oxygen. Thus, one molecule of haemoglobin can combine with four molecules of \(\mathrm{O}_{2}\) to form oxyhaemoglobin
AIIMS - 2013
CHXII14:BIOMOLECULES
324865
The helical structure of protein is stabilised by
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXII14:BIOMOLECULES
324861
Which is \(\mathrm{C}\)-terminal residue in glycyl alanine?
1 Alanine
2 Glutamine
3 Arginine
4 Glycine
Explanation:
In the dipeptide glycylalanine, glycine residue is \(\mathrm{N}\)-terminal and alanine residue is \(\mathrm{C}\)-terminal.
MHTCET - 2021
CHXII14:BIOMOLECULES
324862
In the following polypeptide sequence Arg- Gly - Cys - Leu, C terminal is:
1 \(\operatorname{Arg}\)
2 Cys
3 Leu
4 Gly
Explanation:
In polypeptides , starting aminoacid is named as N-terminal and end amino acid is C-terminal \(\mathop {{\text{Arg}}}\limits_{{\text{N - terminal}}} - {\text{Gly}} - {\text{Cys}} - \mathop {{\text{Leu}}}\limits_{{\text{C - terminal}}} \)
CHXII14:BIOMOLECULES
324863
The sequence in which the \(\mathrm{\alpha}\) - amino acids are linked to one another in a protein molecule is called its
1 Primary structure
2 Secondary structure
3 Tertiary structure
4 Quarternary structure
Explanation:
Primary structure
CHXII14:BIOMOLECULES
324864
The number of sub units present in haemoglobin are
1 2
2 3
3 4
4 5
Explanation:
One molecule of haemoglobin has four heme groups and each of them can take up one molecule of oxygen. Thus, one molecule of haemoglobin can combine with four molecules of \(\mathrm{O}_{2}\) to form oxyhaemoglobin
AIIMS - 2013
CHXII14:BIOMOLECULES
324865
The helical structure of protein is stabilised by
324861
Which is \(\mathrm{C}\)-terminal residue in glycyl alanine?
1 Alanine
2 Glutamine
3 Arginine
4 Glycine
Explanation:
In the dipeptide glycylalanine, glycine residue is \(\mathrm{N}\)-terminal and alanine residue is \(\mathrm{C}\)-terminal.
MHTCET - 2021
CHXII14:BIOMOLECULES
324862
In the following polypeptide sequence Arg- Gly - Cys - Leu, C terminal is:
1 \(\operatorname{Arg}\)
2 Cys
3 Leu
4 Gly
Explanation:
In polypeptides , starting aminoacid is named as N-terminal and end amino acid is C-terminal \(\mathop {{\text{Arg}}}\limits_{{\text{N - terminal}}} - {\text{Gly}} - {\text{Cys}} - \mathop {{\text{Leu}}}\limits_{{\text{C - terminal}}} \)
CHXII14:BIOMOLECULES
324863
The sequence in which the \(\mathrm{\alpha}\) - amino acids are linked to one another in a protein molecule is called its
1 Primary structure
2 Secondary structure
3 Tertiary structure
4 Quarternary structure
Explanation:
Primary structure
CHXII14:BIOMOLECULES
324864
The number of sub units present in haemoglobin are
1 2
2 3
3 4
4 5
Explanation:
One molecule of haemoglobin has four heme groups and each of them can take up one molecule of oxygen. Thus, one molecule of haemoglobin can combine with four molecules of \(\mathrm{O}_{2}\) to form oxyhaemoglobin
AIIMS - 2013
CHXII14:BIOMOLECULES
324865
The helical structure of protein is stabilised by
324861
Which is \(\mathrm{C}\)-terminal residue in glycyl alanine?
1 Alanine
2 Glutamine
3 Arginine
4 Glycine
Explanation:
In the dipeptide glycylalanine, glycine residue is \(\mathrm{N}\)-terminal and alanine residue is \(\mathrm{C}\)-terminal.
MHTCET - 2021
CHXII14:BIOMOLECULES
324862
In the following polypeptide sequence Arg- Gly - Cys - Leu, C terminal is:
1 \(\operatorname{Arg}\)
2 Cys
3 Leu
4 Gly
Explanation:
In polypeptides , starting aminoacid is named as N-terminal and end amino acid is C-terminal \(\mathop {{\text{Arg}}}\limits_{{\text{N - terminal}}} - {\text{Gly}} - {\text{Cys}} - \mathop {{\text{Leu}}}\limits_{{\text{C - terminal}}} \)
CHXII14:BIOMOLECULES
324863
The sequence in which the \(\mathrm{\alpha}\) - amino acids are linked to one another in a protein molecule is called its
1 Primary structure
2 Secondary structure
3 Tertiary structure
4 Quarternary structure
Explanation:
Primary structure
CHXII14:BIOMOLECULES
324864
The number of sub units present in haemoglobin are
1 2
2 3
3 4
4 5
Explanation:
One molecule of haemoglobin has four heme groups and each of them can take up one molecule of oxygen. Thus, one molecule of haemoglobin can combine with four molecules of \(\mathrm{O}_{2}\) to form oxyhaemoglobin
AIIMS - 2013
CHXII14:BIOMOLECULES
324865
The helical structure of protein is stabilised by
