324273 Benzene diazonium chloride on reaction with Phenol in presence of \(\mathrm{NaOH}\) gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \)-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \) - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
\({{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{2}}}\)
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.\({{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\)
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.

324273 Benzene diazonium chloride on reaction with Phenol in presence of \(\mathrm{NaOH}\) gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \)-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \) - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
\({{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{2}}}\)
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.\({{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\)
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.

324273 Benzene diazonium chloride on reaction with Phenol in presence of \(\mathrm{NaOH}\) gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \)-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \) - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
\({{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{2}}}\)
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.\({{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\)
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.

324273 Benzene diazonium chloride on reaction with Phenol in presence of \(\mathrm{NaOH}\) gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \)-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \) - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
\({{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{2}}}\)
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.\({{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\)
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.

324273 Benzene diazonium chloride on reaction with Phenol in presence of \(\mathrm{NaOH}\) gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \)-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with \(\mathrm{NaNO}_{2} / \mathrm{HCl}\) at \(0^{\circ} \mathrm{C}\) followed by coupling with \(\beta \) - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
\({{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{2}}}\)
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.\({{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\)
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.