324273 Benzene diazonium chloride on reaction with Phenol in presence of $\mathrm{NaOH}$ gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$ - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
${\text{H}}_{\text{3}}\text{P}{\text{O}}_{\text{2}}$
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.${\text{H}}_{\text{2}}\text{S}{\text{O}}_{\text{4}}$
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.

324273 Benzene diazonium chloride on reaction with Phenol in presence of $\mathrm{NaOH}$ gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$ - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
${\text{H}}_{\text{3}}\text{P}{\text{O}}_{\text{2}}$
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.${\text{H}}_{\text{2}}\text{S}{\text{O}}_{\text{4}}$
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.

324273 Benzene diazonium chloride on reaction with Phenol in presence of $\mathrm{NaOH}$ gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$ - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
${\text{H}}_{\text{3}}\text{P}{\text{O}}_{\text{2}}$
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.${\text{H}}_{\text{2}}\text{S}{\text{O}}_{\text{4}}$
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.

324273 Benzene diazonium chloride on reaction with Phenol in presence of $\mathrm{NaOH}$ gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$ - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
${\text{H}}_{\text{3}}\text{P}{\text{O}}_{\text{2}}$
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.${\text{H}}_{\text{2}}\text{S}{\text{O}}_{\text{4}}$
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.

324273 Benzene diazonium chloride on reaction with Phenol in presence of $\mathrm{NaOH}$ gives diphenyl. This reaction is known as

324274 Assertion :
Aniline on reaction with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
Reason :
The colour of the compound formed in the reaction of aniline with ${\mathrm{NaNO}}_2/\mathrm{HCl}$ at $0^{\circ }\mathrm{C}$ followed by coupling with $\beta$ - naphthol is due to the extended conjugation.

324275 The correct match of Column I (Reagent /Name reaction) and Column II (Replacement of diazo group by) is
Column I
Column II
A
${\text{H}}_{\text{3}}\text{P}{\text{O}}_{\text{2}}$
P
Hydroxy group
B
Sandmeyer reaction
Q
Aryl group
C
Boiling with dil.${\text{H}}_{\text{2}}\text{S}{\text{O}}_{\text{4}}$
R
Hydrogen atom
D
Gomberg reaction
S
Chlorine atom

324276 Compound A from the following reaction sequence is

324277 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
Benzene diazonium salts are soluble in water.
Statement B :
Benzenediazonium fluoroborate is covalent in nature, so it is soluble in water.