324132
Aniline (1 mole) react with bromine to give symmetrical tribromoaniline. The amount of bromine required is
1 3.0 moles
2 1.5 moles
3 4.5 moles
4 6.0 moles
Explanation:
CHXII13:AMINES
324133
Read the Statement - A and Statement - B carefully and mark the correct option. Statement A : Sulphanilic acid gives esterification test for carboxyl group. Statement B : Sulphanilic acid gives red colour in Lassaigne's test for extra element detection.
1 Both Statement A and Statement B are correct.
2 Both Statement A and Statement B are incorrect.
3 Statement A is incorrect but Statement B is correct.
4 Statement A is correct but Statement B is incorrect.
Explanation:
Sulphanilic acid does not contain any - COOH and cannot give a estirification test for carboxylic acid. Thus, statement A is incorrect. Sulphanilic acid gives a blood red colour in Lassaigne's test due to the formation of the complex \(\left[\mathrm{Fe}(\mathrm{SCN})_{3}\right]\). This is because it contains N, S and C. Thus, statement B is correct.
JEE - 2023
CHXII13:AMINES
324134
Select the percentage in which these amine derivatives are formed in the reaction mixture along with the reason.
1 I \(\rightarrow 2 \%\) II \(\rightarrow 47 \%\) III \(\rightarrow 51 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is ortho directing.
2 I \(\rightarrow 51 \%\) II \(\rightarrow 2 \%\) III \(\rightarrow 47 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is para directing.
3 I \(\rightarrow 51 \%\) II \(\rightarrow 47 \%\) III \(\rightarrow 2 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is meta directing.
4 I \(\rightarrow 50 \%\) II \(\rightarrow 20 \%\) III \(\rightarrow 20 \%\) In acidic medium aniline is protonated to form the anilinium ion which is ortho directing.
Explanation:
Anilinium is formed due to acid base reaction of aniline and \({\mathrm{\mathrm{HNO}_{3}}}\), which is a meta director.
CHXII13:AMINES
324135
Assertion : Controlled nitration of aniline at low temperature mainly gives m-nitroaniline. Reason : In acidic medium, \(-\mathrm{NH}_{2}\) group gets converted into \(\mathrm{m}\)-directing group.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Protonation of aniline under acidic conditions forms the anilinium ion, a deactivating group that directs electrophilic substitutions to the meta position, leading to the major product \(\mathrm{m-}\) nitroaniline during nitration.Thus, option (1) is correct.
324132
Aniline (1 mole) react with bromine to give symmetrical tribromoaniline. The amount of bromine required is
1 3.0 moles
2 1.5 moles
3 4.5 moles
4 6.0 moles
Explanation:
CHXII13:AMINES
324133
Read the Statement - A and Statement - B carefully and mark the correct option. Statement A : Sulphanilic acid gives esterification test for carboxyl group. Statement B : Sulphanilic acid gives red colour in Lassaigne's test for extra element detection.
1 Both Statement A and Statement B are correct.
2 Both Statement A and Statement B are incorrect.
3 Statement A is incorrect but Statement B is correct.
4 Statement A is correct but Statement B is incorrect.
Explanation:
Sulphanilic acid does not contain any - COOH and cannot give a estirification test for carboxylic acid. Thus, statement A is incorrect. Sulphanilic acid gives a blood red colour in Lassaigne's test due to the formation of the complex \(\left[\mathrm{Fe}(\mathrm{SCN})_{3}\right]\). This is because it contains N, S and C. Thus, statement B is correct.
JEE - 2023
CHXII13:AMINES
324134
Select the percentage in which these amine derivatives are formed in the reaction mixture along with the reason.
1 I \(\rightarrow 2 \%\) II \(\rightarrow 47 \%\) III \(\rightarrow 51 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is ortho directing.
2 I \(\rightarrow 51 \%\) II \(\rightarrow 2 \%\) III \(\rightarrow 47 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is para directing.
3 I \(\rightarrow 51 \%\) II \(\rightarrow 47 \%\) III \(\rightarrow 2 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is meta directing.
4 I \(\rightarrow 50 \%\) II \(\rightarrow 20 \%\) III \(\rightarrow 20 \%\) In acidic medium aniline is protonated to form the anilinium ion which is ortho directing.
Explanation:
Anilinium is formed due to acid base reaction of aniline and \({\mathrm{\mathrm{HNO}_{3}}}\), which is a meta director.
CHXII13:AMINES
324135
Assertion : Controlled nitration of aniline at low temperature mainly gives m-nitroaniline. Reason : In acidic medium, \(-\mathrm{NH}_{2}\) group gets converted into \(\mathrm{m}\)-directing group.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Protonation of aniline under acidic conditions forms the anilinium ion, a deactivating group that directs electrophilic substitutions to the meta position, leading to the major product \(\mathrm{m-}\) nitroaniline during nitration.Thus, option (1) is correct.
324132
Aniline (1 mole) react with bromine to give symmetrical tribromoaniline. The amount of bromine required is
1 3.0 moles
2 1.5 moles
3 4.5 moles
4 6.0 moles
Explanation:
CHXII13:AMINES
324133
Read the Statement - A and Statement - B carefully and mark the correct option. Statement A : Sulphanilic acid gives esterification test for carboxyl group. Statement B : Sulphanilic acid gives red colour in Lassaigne's test for extra element detection.
1 Both Statement A and Statement B are correct.
2 Both Statement A and Statement B are incorrect.
3 Statement A is incorrect but Statement B is correct.
4 Statement A is correct but Statement B is incorrect.
Explanation:
Sulphanilic acid does not contain any - COOH and cannot give a estirification test for carboxylic acid. Thus, statement A is incorrect. Sulphanilic acid gives a blood red colour in Lassaigne's test due to the formation of the complex \(\left[\mathrm{Fe}(\mathrm{SCN})_{3}\right]\). This is because it contains N, S and C. Thus, statement B is correct.
JEE - 2023
CHXII13:AMINES
324134
Select the percentage in which these amine derivatives are formed in the reaction mixture along with the reason.
1 I \(\rightarrow 2 \%\) II \(\rightarrow 47 \%\) III \(\rightarrow 51 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is ortho directing.
2 I \(\rightarrow 51 \%\) II \(\rightarrow 2 \%\) III \(\rightarrow 47 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is para directing.
3 I \(\rightarrow 51 \%\) II \(\rightarrow 47 \%\) III \(\rightarrow 2 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is meta directing.
4 I \(\rightarrow 50 \%\) II \(\rightarrow 20 \%\) III \(\rightarrow 20 \%\) In acidic medium aniline is protonated to form the anilinium ion which is ortho directing.
Explanation:
Anilinium is formed due to acid base reaction of aniline and \({\mathrm{\mathrm{HNO}_{3}}}\), which is a meta director.
CHXII13:AMINES
324135
Assertion : Controlled nitration of aniline at low temperature mainly gives m-nitroaniline. Reason : In acidic medium, \(-\mathrm{NH}_{2}\) group gets converted into \(\mathrm{m}\)-directing group.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Protonation of aniline under acidic conditions forms the anilinium ion, a deactivating group that directs electrophilic substitutions to the meta position, leading to the major product \(\mathrm{m-}\) nitroaniline during nitration.Thus, option (1) is correct.
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CHXII13:AMINES
324132
Aniline (1 mole) react with bromine to give symmetrical tribromoaniline. The amount of bromine required is
1 3.0 moles
2 1.5 moles
3 4.5 moles
4 6.0 moles
Explanation:
CHXII13:AMINES
324133
Read the Statement - A and Statement - B carefully and mark the correct option. Statement A : Sulphanilic acid gives esterification test for carboxyl group. Statement B : Sulphanilic acid gives red colour in Lassaigne's test for extra element detection.
1 Both Statement A and Statement B are correct.
2 Both Statement A and Statement B are incorrect.
3 Statement A is incorrect but Statement B is correct.
4 Statement A is correct but Statement B is incorrect.
Explanation:
Sulphanilic acid does not contain any - COOH and cannot give a estirification test for carboxylic acid. Thus, statement A is incorrect. Sulphanilic acid gives a blood red colour in Lassaigne's test due to the formation of the complex \(\left[\mathrm{Fe}(\mathrm{SCN})_{3}\right]\). This is because it contains N, S and C. Thus, statement B is correct.
JEE - 2023
CHXII13:AMINES
324134
Select the percentage in which these amine derivatives are formed in the reaction mixture along with the reason.
1 I \(\rightarrow 2 \%\) II \(\rightarrow 47 \%\) III \(\rightarrow 51 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is ortho directing.
2 I \(\rightarrow 51 \%\) II \(\rightarrow 2 \%\) III \(\rightarrow 47 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is para directing.
3 I \(\rightarrow 51 \%\) II \(\rightarrow 47 \%\) III \(\rightarrow 2 \%\) In the acidic medium, aniline is protonated to form the anilinium ion which is meta directing.
4 I \(\rightarrow 50 \%\) II \(\rightarrow 20 \%\) III \(\rightarrow 20 \%\) In acidic medium aniline is protonated to form the anilinium ion which is ortho directing.
Explanation:
Anilinium is formed due to acid base reaction of aniline and \({\mathrm{\mathrm{HNO}_{3}}}\), which is a meta director.
CHXII13:AMINES
324135
Assertion : Controlled nitration of aniline at low temperature mainly gives m-nitroaniline. Reason : In acidic medium, \(-\mathrm{NH}_{2}\) group gets converted into \(\mathrm{m}\)-directing group.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Protonation of aniline under acidic conditions forms the anilinium ion, a deactivating group that directs electrophilic substitutions to the meta position, leading to the major product \(\mathrm{m-}\) nitroaniline during nitration.Thus, option (1) is correct.
