Explanation:

In aqueous medium basic strength is dependent on electron density on nitrogen as well as solvation of cation formed after accepting \(\mathrm{H}^{+}\) ion. Considering the combined effects of solvation and inductive effect, the order of basic strength of methyl amines in the aqueous state is
\(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}>\mathrm{NH}_{3}\)
So, the correct option is (3).

Explanation:

Basic character depends upon the availability of lone pair of electrons over nitrogen for donation. Presence of electron releasing group like \(-\mathrm{CH}_{3}\) increases the electron density over nitrogen, thus, lone pair of nitrogen are more available for donation. Hence, basic character increases.But \(3^{\circ}\) methyl amines are less basic as compared to \(2^{\circ}\) and \(1^{\circ}\) amines due to steric hindrance. Thus, the order of basic strength of the given compounds is

Explanation:

In benzimidazole, lone pair of electrons on \({ }^{\mathrm{I}} \mathrm{N}\) is fully available for donation i.e. not involved in delocalisation, hence it is basic. The lone pair of \({ }^{\text {II }} \mathrm{N}\) takes part in delocalisation, hence not available for donation. Thus, \({ }^{\text {II }} \mathrm{N}\) is non - basic.

Hence both statements are wrong.

Explanation:

Explanation:

In aqueous medium basic strength is dependent on electron density on nitrogen as well as solvation of cation formed after accepting \(\mathrm{H}^{+}\) ion. Considering the combined effects of solvation and inductive effect, the order of basic strength of methyl amines in the aqueous state is
\(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}>\mathrm{NH}_{3}\)
So, the correct option is (3).

Explanation:

Basic character depends upon the availability of lone pair of electrons over nitrogen for donation. Presence of electron releasing group like \(-\mathrm{CH}_{3}\) increases the electron density over nitrogen, thus, lone pair of nitrogen are more available for donation. Hence, basic character increases.But \(3^{\circ}\) methyl amines are less basic as compared to \(2^{\circ}\) and \(1^{\circ}\) amines due to steric hindrance. Thus, the order of basic strength of the given compounds is

Explanation:

In benzimidazole, lone pair of electrons on \({ }^{\mathrm{I}} \mathrm{N}\) is fully available for donation i.e. not involved in delocalisation, hence it is basic. The lone pair of \({ }^{\text {II }} \mathrm{N}\) takes part in delocalisation, hence not available for donation. Thus, \({ }^{\text {II }} \mathrm{N}\) is non - basic.

Hence both statements are wrong.

Explanation:

Explanation:

In aqueous medium basic strength is dependent on electron density on nitrogen as well as solvation of cation formed after accepting \(\mathrm{H}^{+}\) ion. Considering the combined effects of solvation and inductive effect, the order of basic strength of methyl amines in the aqueous state is
\(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}>\mathrm{NH}_{3}\)
So, the correct option is (3).

Explanation:

Basic character depends upon the availability of lone pair of electrons over nitrogen for donation. Presence of electron releasing group like \(-\mathrm{CH}_{3}\) increases the electron density over nitrogen, thus, lone pair of nitrogen are more available for donation. Hence, basic character increases.But \(3^{\circ}\) methyl amines are less basic as compared to \(2^{\circ}\) and \(1^{\circ}\) amines due to steric hindrance. Thus, the order of basic strength of the given compounds is

Explanation:

In benzimidazole, lone pair of electrons on \({ }^{\mathrm{I}} \mathrm{N}\) is fully available for donation i.e. not involved in delocalisation, hence it is basic. The lone pair of \({ }^{\text {II }} \mathrm{N}\) takes part in delocalisation, hence not available for donation. Thus, \({ }^{\text {II }} \mathrm{N}\) is non - basic.

Hence both statements are wrong.

Explanation:

Explanation:

In aqueous medium basic strength is dependent on electron density on nitrogen as well as solvation of cation formed after accepting \(\mathrm{H}^{+}\) ion. Considering the combined effects of solvation and inductive effect, the order of basic strength of methyl amines in the aqueous state is
\(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}>\mathrm{NH}_{3}\)
So, the correct option is (3).

Explanation:

Basic character depends upon the availability of lone pair of electrons over nitrogen for donation. Presence of electron releasing group like \(-\mathrm{CH}_{3}\) increases the electron density over nitrogen, thus, lone pair of nitrogen are more available for donation. Hence, basic character increases.But \(3^{\circ}\) methyl amines are less basic as compared to \(2^{\circ}\) and \(1^{\circ}\) amines due to steric hindrance. Thus, the order of basic strength of the given compounds is

Explanation:

In benzimidazole, lone pair of electrons on \({ }^{\mathrm{I}} \mathrm{N}\) is fully available for donation i.e. not involved in delocalisation, hence it is basic. The lone pair of \({ }^{\text {II }} \mathrm{N}\) takes part in delocalisation, hence not available for donation. Thus, \({ }^{\text {II }} \mathrm{N}\) is non - basic.

Hence both statements are wrong.

Explanation: