\(\mathrm{R}-\mathrm{NH}_{2}\) is \(1^{\circ}\) - amine
CHXII13:AMINES
323999
Diethyl amine is an example for
1 \(1^{\circ}\) amine
2 \(3^{\circ}\) amine
3 \(2^{\circ}\) amine
4 quaternary ammonium salt
Explanation:
The lone pair of electrons present on nitrogen atom of benzylamine are not involved in it is strongest base among the given amines.
CHXII13:AMINES
324056
The correct order of the increasing basicity of methyl amine, ammonia and aniline is
1 methyl amine \( < \) aniline \( < \) ammonia
2 aniline \( < \) ammonia \( < \) methyl amine
3 aniline \( < \) methyl amine \( < \) ammonia
4 ammonia \( < \) aniline \( < \) methyl amine
Explanation:
In aniline the lone pair on N is involved in delocalization with benzene ring and is not available for protonation. Methyl amine is a stronger base than ammonia because + I effect of methyl group increases electron density on N making it more basic than \({\rm{N}}{{\rm{H}}_{\rm{3}}}\). Cannot be protonated. least basic
CHXII13:AMINES
324057
The increasing order of \({\rm{p}}{{\rm{K}}_{\rm{b}}}\) for the following compounds will be (A) \(\mathrm{NH}_{2}-\mathrm{CH}=\mathrm{NH}\), (B) (C) \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{NHC}}{{\rm{H}}_{\rm{3}}}\)
\(\mathrm{R}-\mathrm{NH}_{2}\) is \(1^{\circ}\) - amine
CHXII13:AMINES
323999
Diethyl amine is an example for
1 \(1^{\circ}\) amine
2 \(3^{\circ}\) amine
3 \(2^{\circ}\) amine
4 quaternary ammonium salt
Explanation:
The lone pair of electrons present on nitrogen atom of benzylamine are not involved in it is strongest base among the given amines.
CHXII13:AMINES
324056
The correct order of the increasing basicity of methyl amine, ammonia and aniline is
1 methyl amine \( < \) aniline \( < \) ammonia
2 aniline \( < \) ammonia \( < \) methyl amine
3 aniline \( < \) methyl amine \( < \) ammonia
4 ammonia \( < \) aniline \( < \) methyl amine
Explanation:
In aniline the lone pair on N is involved in delocalization with benzene ring and is not available for protonation. Methyl amine is a stronger base than ammonia because + I effect of methyl group increases electron density on N making it more basic than \({\rm{N}}{{\rm{H}}_{\rm{3}}}\). Cannot be protonated. least basic
CHXII13:AMINES
324057
The increasing order of \({\rm{p}}{{\rm{K}}_{\rm{b}}}\) for the following compounds will be (A) \(\mathrm{NH}_{2}-\mathrm{CH}=\mathrm{NH}\), (B) (C) \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{NHC}}{{\rm{H}}_{\rm{3}}}\)
\(\mathrm{R}-\mathrm{NH}_{2}\) is \(1^{\circ}\) - amine
CHXII13:AMINES
323999
Diethyl amine is an example for
1 \(1^{\circ}\) amine
2 \(3^{\circ}\) amine
3 \(2^{\circ}\) amine
4 quaternary ammonium salt
Explanation:
The lone pair of electrons present on nitrogen atom of benzylamine are not involved in it is strongest base among the given amines.
CHXII13:AMINES
324056
The correct order of the increasing basicity of methyl amine, ammonia and aniline is
1 methyl amine \( < \) aniline \( < \) ammonia
2 aniline \( < \) ammonia \( < \) methyl amine
3 aniline \( < \) methyl amine \( < \) ammonia
4 ammonia \( < \) aniline \( < \) methyl amine
Explanation:
In aniline the lone pair on N is involved in delocalization with benzene ring and is not available for protonation. Methyl amine is a stronger base than ammonia because + I effect of methyl group increases electron density on N making it more basic than \({\rm{N}}{{\rm{H}}_{\rm{3}}}\). Cannot be protonated. least basic
CHXII13:AMINES
324057
The increasing order of \({\rm{p}}{{\rm{K}}_{\rm{b}}}\) for the following compounds will be (A) \(\mathrm{NH}_{2}-\mathrm{CH}=\mathrm{NH}\), (B) (C) \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{NHC}}{{\rm{H}}_{\rm{3}}}\)
\(\mathrm{R}-\mathrm{NH}_{2}\) is \(1^{\circ}\) - amine
CHXII13:AMINES
323999
Diethyl amine is an example for
1 \(1^{\circ}\) amine
2 \(3^{\circ}\) amine
3 \(2^{\circ}\) amine
4 quaternary ammonium salt
Explanation:
The lone pair of electrons present on nitrogen atom of benzylamine are not involved in it is strongest base among the given amines.
CHXII13:AMINES
324056
The correct order of the increasing basicity of methyl amine, ammonia and aniline is
1 methyl amine \( < \) aniline \( < \) ammonia
2 aniline \( < \) ammonia \( < \) methyl amine
3 aniline \( < \) methyl amine \( < \) ammonia
4 ammonia \( < \) aniline \( < \) methyl amine
Explanation:
In aniline the lone pair on N is involved in delocalization with benzene ring and is not available for protonation. Methyl amine is a stronger base than ammonia because + I effect of methyl group increases electron density on N making it more basic than \({\rm{N}}{{\rm{H}}_{\rm{3}}}\). Cannot be protonated. least basic
CHXII13:AMINES
324057
The increasing order of \({\rm{p}}{{\rm{K}}_{\rm{b}}}\) for the following compounds will be (A) \(\mathrm{NH}_{2}-\mathrm{CH}=\mathrm{NH}\), (B) (C) \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{NHC}}{{\rm{H}}_{\rm{3}}}\)
