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CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323941 Arrange the following compounds in decreasing order of their boiling points.
$C H_{3} CHO, C H_{3} C H_{2} OH, C H_{3} OC H_{3},$ $C H_{3} C H_{2} C H_{3}$

1

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} {OCH}_{3} < {CH}_{3} CHO < {CH}_{3} {CH}_{2} OH

2

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} CHO < {CH}_{3} {OCH}_{3} < {CH}_{3} {CH}_{2} OH

3

{CH}_{3} {CH}_{2} {CH}_{3} > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} OH

4

{CH}_{3} {CH}_{2} OH > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} {CH}_{3}

Explanation:

Among these only ${CH}_{3} {CH}_{2} OH$ undergoes H-bonding.
So, it will have the highest boiling point.
In the case of remaining compounds,
${CH}_{3} {COCH}_{3}$ has slightly
higher boiling point, than $H_{3} CCHO$ and
$H_{3} {CCH}_{2} {CH}_{3}$ .
This is due to higher molecular weight
of ${CH}_{3} {OCH}_{3}$ than ${CH}_{3} {CH}_{2} {CH}_{3}$ and ${CH}_{3} CHO . {CH}_{3} CHO$
has higher boiling point than alkane due to appreciable intermolecular attraction
(dipole-dipole interaction).
Thus, the correct order is
$\begin{array}{l} C H_{3} C H_{2} C H_{3} < C H_{3} C H O \\ < C H_{3} O C H_{3} < C H_{3} C H_{2} O H \end{array}$

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323935 Assertion :
Boiling point of aldehydes lie in between parent alkanes, and corresponding alcohols.
Reason :
Intermolecular forces of attraction in aldehydes is stronger than that in found in parent alkanes, but weaker than that in alcohols.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Boiling point of aldehydes is lower than parent alkane because they contain polar carbonyl group. The carbonyl group undergoes weak intermolecular dipole-dipole interactions between the opposite ends of the $= C = O$ dipoles.
supporting img
However, these dipole interactions are weaker than the intermolecular hydrogen bonding found in alcohols. Thus, aldehydes have lesser b.p than alcohols. So the option (1) is correct.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323936 Arrange the following compounds in the increasing order of their boiling points.
$\begin{matrix} C H_{3} C H_{2} C H_{2} C H O (I) & C H_{3} C H_{2} C H_{2} C H_{2} O H (I I) \\ H_{5} C_{2} O C_{2} H_{5} (I I I) & C H_{3} C H_{2} C H_{2} C H_{2} C H_{3} (I V) \end{matrix}$

1 IV

<

I

<

II

<

III

2 IV

<

III

<

II

<

I

3 IV

<

III

<

I

<

II

4 IV

<

II

<

III

<

I

Explanation:

The boiling point of butan-1-ol would be highest, due to extensive intermolecular hydrogen bonding. Butanal is more polar than ethoxyethane. The intermolecular dipole-dipole attraction is stronger in the butanal. n-pentane molecules have only weak van der Waal's forces. The increasing order of boiling point of the given compounds are IV $<$ III $<$ I $<$ II.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323937 Given below are two statements :-
Statement I :
The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.
Statements II :
The boiling points aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
In the light of the statements, choose the most appropriate answer from the options given below

1 Both statements I and statements II are incorrect.

2 Statement I is correct but statements II is incorrect

3 Statements I is incorrect but statements II is correct.

4 Both statements I and statements II are correct.

Explanation:

Boiling point of comparable molecular mass molecules:
$\underset{}{\underset{⏟}{R - O H}} > \underset{}{\underset{⏟}{A l d e h y d e > K e t o n e}} > \underset{}{\underset{⏟}{A l k a n e}}$
H-bonding Dipole-dipole interaction Non-polar (strong molecular (weak molecular association) association)

NEET - 2022

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323938 Statement A :
The boiling points of aldehydes and ketones are higher than hydrocarbons and ethers of comparable molecular masses.
Statement B :
There is a weak molecular association in aldehydes and ketones arising out of the dipole-dipole interactions.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323941 Arrange the following compounds in decreasing order of their boiling points.
$C H_{3} CHO, C H_{3} C H_{2} OH, C H_{3} OC H_{3},$ $C H_{3} C H_{2} C H_{3}$

1

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} {OCH}_{3} < {CH}_{3} CHO < {CH}_{3} {CH}_{2} OH

2

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} CHO < {CH}_{3} {OCH}_{3} < {CH}_{3} {CH}_{2} OH

3

{CH}_{3} {CH}_{2} {CH}_{3} > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} OH

4

{CH}_{3} {CH}_{2} OH > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} {CH}_{3}

Explanation:

Among these only ${CH}_{3} {CH}_{2} OH$ undergoes H-bonding.
So, it will have the highest boiling point.
In the case of remaining compounds,
${CH}_{3} {COCH}_{3}$ has slightly
higher boiling point, than $H_{3} CCHO$ and
$H_{3} {CCH}_{2} {CH}_{3}$ .
This is due to higher molecular weight
of ${CH}_{3} {OCH}_{3}$ than ${CH}_{3} {CH}_{2} {CH}_{3}$ and ${CH}_{3} CHO . {CH}_{3} CHO$
has higher boiling point than alkane due to appreciable intermolecular attraction
(dipole-dipole interaction).
Thus, the correct order is
$\begin{array}{l} C H_{3} C H_{2} C H_{3} < C H_{3} C H O \\ < C H_{3} O C H_{3} < C H_{3} C H_{2} O H \end{array}$

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323935 Assertion :
Boiling point of aldehydes lie in between parent alkanes, and corresponding alcohols.
Reason :
Intermolecular forces of attraction in aldehydes is stronger than that in found in parent alkanes, but weaker than that in alcohols.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Boiling point of aldehydes is lower than parent alkane because they contain polar carbonyl group. The carbonyl group undergoes weak intermolecular dipole-dipole interactions between the opposite ends of the $= C = O$ dipoles.
supporting img
However, these dipole interactions are weaker than the intermolecular hydrogen bonding found in alcohols. Thus, aldehydes have lesser b.p than alcohols. So the option (1) is correct.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323936 Arrange the following compounds in the increasing order of their boiling points.
$\begin{matrix} C H_{3} C H_{2} C H_{2} C H O (I) & C H_{3} C H_{2} C H_{2} C H_{2} O H (I I) \\ H_{5} C_{2} O C_{2} H_{5} (I I I) & C H_{3} C H_{2} C H_{2} C H_{2} C H_{3} (I V) \end{matrix}$

1 IV

<

I

<

II

<

III

2 IV

<

III

<

II

<

I

3 IV

<

III

<

I

<

II

4 IV

<

II

<

III

<

I

Explanation:

The boiling point of butan-1-ol would be highest, due to extensive intermolecular hydrogen bonding. Butanal is more polar than ethoxyethane. The intermolecular dipole-dipole attraction is stronger in the butanal. n-pentane molecules have only weak van der Waal's forces. The increasing order of boiling point of the given compounds are IV $<$ III $<$ I $<$ II.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323937 Given below are two statements :-
Statement I :
The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.
Statements II :
The boiling points aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
In the light of the statements, choose the most appropriate answer from the options given below

1 Both statements I and statements II are incorrect.

2 Statement I is correct but statements II is incorrect

3 Statements I is incorrect but statements II is correct.

4 Both statements I and statements II are correct.

Explanation:

Boiling point of comparable molecular mass molecules:
$\underset{}{\underset{⏟}{R - O H}} > \underset{}{\underset{⏟}{A l d e h y d e > K e t o n e}} > \underset{}{\underset{⏟}{A l k a n e}}$
H-bonding Dipole-dipole interaction Non-polar (strong molecular (weak molecular association) association)

NEET - 2022

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323938 Statement A :
The boiling points of aldehydes and ketones are higher than hydrocarbons and ethers of comparable molecular masses.
Statement B :
There is a weak molecular association in aldehydes and ketones arising out of the dipole-dipole interactions.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323941 Arrange the following compounds in decreasing order of their boiling points.
$C H_{3} CHO, C H_{3} C H_{2} OH, C H_{3} OC H_{3},$ $C H_{3} C H_{2} C H_{3}$

1

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} {OCH}_{3} < {CH}_{3} CHO < {CH}_{3} {CH}_{2} OH

2

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} CHO < {CH}_{3} {OCH}_{3} < {CH}_{3} {CH}_{2} OH

3

{CH}_{3} {CH}_{2} {CH}_{3} > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} OH

4

{CH}_{3} {CH}_{2} OH > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} {CH}_{3}

Explanation:

Among these only ${CH}_{3} {CH}_{2} OH$ undergoes H-bonding.
So, it will have the highest boiling point.
In the case of remaining compounds,
${CH}_{3} {COCH}_{3}$ has slightly
higher boiling point, than $H_{3} CCHO$ and
$H_{3} {CCH}_{2} {CH}_{3}$ .
This is due to higher molecular weight
of ${CH}_{3} {OCH}_{3}$ than ${CH}_{3} {CH}_{2} {CH}_{3}$ and ${CH}_{3} CHO . {CH}_{3} CHO$
has higher boiling point than alkane due to appreciable intermolecular attraction
(dipole-dipole interaction).
Thus, the correct order is
$\begin{array}{l} C H_{3} C H_{2} C H_{3} < C H_{3} C H O \\ < C H_{3} O C H_{3} < C H_{3} C H_{2} O H \end{array}$

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323935 Assertion :
Boiling point of aldehydes lie in between parent alkanes, and corresponding alcohols.
Reason :
Intermolecular forces of attraction in aldehydes is stronger than that in found in parent alkanes, but weaker than that in alcohols.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Boiling point of aldehydes is lower than parent alkane because they contain polar carbonyl group. The carbonyl group undergoes weak intermolecular dipole-dipole interactions between the opposite ends of the $= C = O$ dipoles.
supporting img
However, these dipole interactions are weaker than the intermolecular hydrogen bonding found in alcohols. Thus, aldehydes have lesser b.p than alcohols. So the option (1) is correct.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323936 Arrange the following compounds in the increasing order of their boiling points.
$\begin{matrix} C H_{3} C H_{2} C H_{2} C H O (I) & C H_{3} C H_{2} C H_{2} C H_{2} O H (I I) \\ H_{5} C_{2} O C_{2} H_{5} (I I I) & C H_{3} C H_{2} C H_{2} C H_{2} C H_{3} (I V) \end{matrix}$

1 IV

<

I

<

II

<

III

2 IV

<

III

<

II

<

I

3 IV

<

III

<

I

<

II

4 IV

<

II

<

III

<

I

Explanation:

The boiling point of butan-1-ol would be highest, due to extensive intermolecular hydrogen bonding. Butanal is more polar than ethoxyethane. The intermolecular dipole-dipole attraction is stronger in the butanal. n-pentane molecules have only weak van der Waal's forces. The increasing order of boiling point of the given compounds are IV $<$ III $<$ I $<$ II.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323937 Given below are two statements :-
Statement I :
The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.
Statements II :
The boiling points aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
In the light of the statements, choose the most appropriate answer from the options given below

1 Both statements I and statements II are incorrect.

2 Statement I is correct but statements II is incorrect

3 Statements I is incorrect but statements II is correct.

4 Both statements I and statements II are correct.

Explanation:

Boiling point of comparable molecular mass molecules:
$\underset{}{\underset{⏟}{R - O H}} > \underset{}{\underset{⏟}{A l d e h y d e > K e t o n e}} > \underset{}{\underset{⏟}{A l k a n e}}$
H-bonding Dipole-dipole interaction Non-polar (strong molecular (weak molecular association) association)

NEET - 2022

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323938 Statement A :
The boiling points of aldehydes and ketones are higher than hydrocarbons and ethers of comparable molecular masses.
Statement B :
There is a weak molecular association in aldehydes and ketones arising out of the dipole-dipole interactions.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323941 Arrange the following compounds in decreasing order of their boiling points.
$C H_{3} CHO, C H_{3} C H_{2} OH, C H_{3} OC H_{3},$ $C H_{3} C H_{2} C H_{3}$

1

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} {OCH}_{3} < {CH}_{3} CHO < {CH}_{3} {CH}_{2} OH

2

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} CHO < {CH}_{3} {OCH}_{3} < {CH}_{3} {CH}_{2} OH

3

{CH}_{3} {CH}_{2} {CH}_{3} > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} OH

4

{CH}_{3} {CH}_{2} OH > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} {CH}_{3}

Explanation:

Among these only ${CH}_{3} {CH}_{2} OH$ undergoes H-bonding.
So, it will have the highest boiling point.
In the case of remaining compounds,
${CH}_{3} {COCH}_{3}$ has slightly
higher boiling point, than $H_{3} CCHO$ and
$H_{3} {CCH}_{2} {CH}_{3}$ .
This is due to higher molecular weight
of ${CH}_{3} {OCH}_{3}$ than ${CH}_{3} {CH}_{2} {CH}_{3}$ and ${CH}_{3} CHO . {CH}_{3} CHO$
has higher boiling point than alkane due to appreciable intermolecular attraction
(dipole-dipole interaction).
Thus, the correct order is
$\begin{array}{l} C H_{3} C H_{2} C H_{3} < C H_{3} C H O \\ < C H_{3} O C H_{3} < C H_{3} C H_{2} O H \end{array}$

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323935 Assertion :
Boiling point of aldehydes lie in between parent alkanes, and corresponding alcohols.
Reason :
Intermolecular forces of attraction in aldehydes is stronger than that in found in parent alkanes, but weaker than that in alcohols.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Boiling point of aldehydes is lower than parent alkane because they contain polar carbonyl group. The carbonyl group undergoes weak intermolecular dipole-dipole interactions between the opposite ends of the $= C = O$ dipoles.
supporting img
However, these dipole interactions are weaker than the intermolecular hydrogen bonding found in alcohols. Thus, aldehydes have lesser b.p than alcohols. So the option (1) is correct.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323936 Arrange the following compounds in the increasing order of their boiling points.
$\begin{matrix} C H_{3} C H_{2} C H_{2} C H O (I) & C H_{3} C H_{2} C H_{2} C H_{2} O H (I I) \\ H_{5} C_{2} O C_{2} H_{5} (I I I) & C H_{3} C H_{2} C H_{2} C H_{2} C H_{3} (I V) \end{matrix}$

1 IV

<

I

<

II

<

III

2 IV

<

III

<

II

<

I

3 IV

<

III

<

I

<

II

4 IV

<

II

<

III

<

I

Explanation:

The boiling point of butan-1-ol would be highest, due to extensive intermolecular hydrogen bonding. Butanal is more polar than ethoxyethane. The intermolecular dipole-dipole attraction is stronger in the butanal. n-pentane molecules have only weak van der Waal's forces. The increasing order of boiling point of the given compounds are IV $<$ III $<$ I $<$ II.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323937 Given below are two statements :-
Statement I :
The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.
Statements II :
The boiling points aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
In the light of the statements, choose the most appropriate answer from the options given below

1 Both statements I and statements II are incorrect.

2 Statement I is correct but statements II is incorrect

3 Statements I is incorrect but statements II is correct.

4 Both statements I and statements II are correct.

Explanation:

Boiling point of comparable molecular mass molecules:
$\underset{}{\underset{⏟}{R - O H}} > \underset{}{\underset{⏟}{A l d e h y d e > K e t o n e}} > \underset{}{\underset{⏟}{A l k a n e}}$
H-bonding Dipole-dipole interaction Non-polar (strong molecular (weak molecular association) association)

NEET - 2022

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323938 Statement A :
The boiling points of aldehydes and ketones are higher than hydrocarbons and ethers of comparable molecular masses.
Statement B :
There is a weak molecular association in aldehydes and ketones arising out of the dipole-dipole interactions.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323941 Arrange the following compounds in decreasing order of their boiling points.
$C H_{3} CHO, C H_{3} C H_{2} OH, C H_{3} OC H_{3},$ $C H_{3} C H_{2} C H_{3}$

1

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} {OCH}_{3} < {CH}_{3} CHO < {CH}_{3} {CH}_{2} OH

2

{CH}_{3} {CH}_{2} {CH}_{3} < {CH}_{3} CHO < {CH}_{3} {OCH}_{3} < {CH}_{3} {CH}_{2} OH

3

{CH}_{3} {CH}_{2} {CH}_{3} > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} OH

4

{CH}_{3} {CH}_{2} OH > {CH}_{3} CHO > {CH}_{3} {OCH}_{3} > {CH}_{3} {CH}_{2} {CH}_{3}

Explanation:

Among these only ${CH}_{3} {CH}_{2} OH$ undergoes H-bonding.
So, it will have the highest boiling point.
In the case of remaining compounds,
${CH}_{3} {COCH}_{3}$ has slightly
higher boiling point, than $H_{3} CCHO$ and
$H_{3} {CCH}_{2} {CH}_{3}$ .
This is due to higher molecular weight
of ${CH}_{3} {OCH}_{3}$ than ${CH}_{3} {CH}_{2} {CH}_{3}$ and ${CH}_{3} CHO . {CH}_{3} CHO$
has higher boiling point than alkane due to appreciable intermolecular attraction
(dipole-dipole interaction).
Thus, the correct order is
$\begin{array}{l} C H_{3} C H_{2} C H_{3} < C H_{3} C H O \\ < C H_{3} O C H_{3} < C H_{3} C H_{2} O H \end{array}$

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323935 Assertion :
Boiling point of aldehydes lie in between parent alkanes, and corresponding alcohols.
Reason :
Intermolecular forces of attraction in aldehydes is stronger than that in found in parent alkanes, but weaker than that in alcohols.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Boiling point of aldehydes is lower than parent alkane because they contain polar carbonyl group. The carbonyl group undergoes weak intermolecular dipole-dipole interactions between the opposite ends of the $= C = O$ dipoles.
supporting img
However, these dipole interactions are weaker than the intermolecular hydrogen bonding found in alcohols. Thus, aldehydes have lesser b.p than alcohols. So the option (1) is correct.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323936 Arrange the following compounds in the increasing order of their boiling points.
$\begin{matrix} C H_{3} C H_{2} C H_{2} C H O (I) & C H_{3} C H_{2} C H_{2} C H_{2} O H (I I) \\ H_{5} C_{2} O C_{2} H_{5} (I I I) & C H_{3} C H_{2} C H_{2} C H_{2} C H_{3} (I V) \end{matrix}$

1 IV

<

I

<

II

<

III

2 IV

<

III

<

II

<

I

3 IV

<

III

<

I

<

II

4 IV

<

II

<

III

<

I

Explanation:

The boiling point of butan-1-ol would be highest, due to extensive intermolecular hydrogen bonding. Butanal is more polar than ethoxyethane. The intermolecular dipole-dipole attraction is stronger in the butanal. n-pentane molecules have only weak van der Waal's forces. The increasing order of boiling point of the given compounds are IV $<$ III $<$ I $<$ II.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323937 Given below are two statements :-
Statement I :
The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.
Statements II :
The boiling points aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
In the light of the statements, choose the most appropriate answer from the options given below

1 Both statements I and statements II are incorrect.

2 Statement I is correct but statements II is incorrect

3 Statements I is incorrect but statements II is correct.

4 Both statements I and statements II are correct.

Explanation:

Boiling point of comparable molecular mass molecules:
$\underset{}{\underset{⏟}{R - O H}} > \underset{}{\underset{⏟}{A l d e h y d e > K e t o n e}} > \underset{}{\underset{⏟}{A l k a n e}}$
H-bonding Dipole-dipole interaction Non-polar (strong molecular (weak molecular association) association)

NEET - 2022

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323938 Statement A :
The boiling points of aldehydes and ketones are higher than hydrocarbons and ethers of comparable molecular masses.
Statement B :
There is a weak molecular association in aldehydes and ketones arising out of the dipole-dipole interactions.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

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