323764
How many isomeric carboxylic acids having \({{\text{C}}_{\text{5}}}{{\text{H}}_{{\text{10}}}}{{\text{O}}_{\text{2}}}\) formula will give Hell-Volhard-Zeilinsky reaction? (Excluding stereoisomers)
1 1
2 2
3 3
4 4
Explanation:
Hell-Volhard-Zeilinsky reaction (or \({\mathrm{\alpha}}\)-halogenation) is given by carboxylic acids having \({\mathrm{\alpha-\mathrm{H}}}\) atom. Carboxylic acids having \({\mathrm{\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}}}\) formula are: Except structure (IV), all (i.e., structure I, II, III) contain \({\mathrm{\alpha}}\)-H atom
2 (i) red \(\mathrm{P}, \mathrm{Br}_{2}\) / (ii) alc. \(\mathrm{NH}_{3}\) (excess)
3 (i) \(\mathrm{PBr}_{3}, \mathrm{NaCN} /\) (ii) \(\mathrm{LiAlH}_{4}\)
4 None of the above
Explanation:
The given hexanoic acid can be converted into 2-amino hexanoic acid in two steps: (i) Hexanoic acid is converted into \(\alpha\)-bromo hexanoic acid through Hell-Volhard Zelinsky reaction (HVZ) (ii) This \(\alpha\)-bromo hexanoic acid is converted into 2-aminohexanoic acid by heating it with an alcoholic solution of ammonia, and this process is called ammonolysis (cleavage of C-X bond by ammonia).
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323766
The number of \({\rm{\pi }}\) - bonds in compound B is / are
1 1
2 2
3 3
4 0
Explanation:
B: \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCOOH}\)
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323767
Consider the following reactions sequence, Isomers are
323768
One mole each of calcium acetate and calcium propionate undergoes dry distillation to form ' \({\mathrm{x}}\) ' mole(s) of ethyl methyl ketone. Find the value of \({\mathrm{x}}\).
323764
How many isomeric carboxylic acids having \({{\text{C}}_{\text{5}}}{{\text{H}}_{{\text{10}}}}{{\text{O}}_{\text{2}}}\) formula will give Hell-Volhard-Zeilinsky reaction? (Excluding stereoisomers)
1 1
2 2
3 3
4 4
Explanation:
Hell-Volhard-Zeilinsky reaction (or \({\mathrm{\alpha}}\)-halogenation) is given by carboxylic acids having \({\mathrm{\alpha-\mathrm{H}}}\) atom. Carboxylic acids having \({\mathrm{\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}}}\) formula are: Except structure (IV), all (i.e., structure I, II, III) contain \({\mathrm{\alpha}}\)-H atom
2 (i) red \(\mathrm{P}, \mathrm{Br}_{2}\) / (ii) alc. \(\mathrm{NH}_{3}\) (excess)
3 (i) \(\mathrm{PBr}_{3}, \mathrm{NaCN} /\) (ii) \(\mathrm{LiAlH}_{4}\)
4 None of the above
Explanation:
The given hexanoic acid can be converted into 2-amino hexanoic acid in two steps: (i) Hexanoic acid is converted into \(\alpha\)-bromo hexanoic acid through Hell-Volhard Zelinsky reaction (HVZ) (ii) This \(\alpha\)-bromo hexanoic acid is converted into 2-aminohexanoic acid by heating it with an alcoholic solution of ammonia, and this process is called ammonolysis (cleavage of C-X bond by ammonia).
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323766
The number of \({\rm{\pi }}\) - bonds in compound B is / are
1 1
2 2
3 3
4 0
Explanation:
B: \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCOOH}\)
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323767
Consider the following reactions sequence, Isomers are
323768
One mole each of calcium acetate and calcium propionate undergoes dry distillation to form ' \({\mathrm{x}}\) ' mole(s) of ethyl methyl ketone. Find the value of \({\mathrm{x}}\).
323764
How many isomeric carboxylic acids having \({{\text{C}}_{\text{5}}}{{\text{H}}_{{\text{10}}}}{{\text{O}}_{\text{2}}}\) formula will give Hell-Volhard-Zeilinsky reaction? (Excluding stereoisomers)
1 1
2 2
3 3
4 4
Explanation:
Hell-Volhard-Zeilinsky reaction (or \({\mathrm{\alpha}}\)-halogenation) is given by carboxylic acids having \({\mathrm{\alpha-\mathrm{H}}}\) atom. Carboxylic acids having \({\mathrm{\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}}}\) formula are: Except structure (IV), all (i.e., structure I, II, III) contain \({\mathrm{\alpha}}\)-H atom
2 (i) red \(\mathrm{P}, \mathrm{Br}_{2}\) / (ii) alc. \(\mathrm{NH}_{3}\) (excess)
3 (i) \(\mathrm{PBr}_{3}, \mathrm{NaCN} /\) (ii) \(\mathrm{LiAlH}_{4}\)
4 None of the above
Explanation:
The given hexanoic acid can be converted into 2-amino hexanoic acid in two steps: (i) Hexanoic acid is converted into \(\alpha\)-bromo hexanoic acid through Hell-Volhard Zelinsky reaction (HVZ) (ii) This \(\alpha\)-bromo hexanoic acid is converted into 2-aminohexanoic acid by heating it with an alcoholic solution of ammonia, and this process is called ammonolysis (cleavage of C-X bond by ammonia).
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323766
The number of \({\rm{\pi }}\) - bonds in compound B is / are
1 1
2 2
3 3
4 0
Explanation:
B: \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCOOH}\)
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323767
Consider the following reactions sequence, Isomers are
323768
One mole each of calcium acetate and calcium propionate undergoes dry distillation to form ' \({\mathrm{x}}\) ' mole(s) of ethyl methyl ketone. Find the value of \({\mathrm{x}}\).
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323764
How many isomeric carboxylic acids having \({{\text{C}}_{\text{5}}}{{\text{H}}_{{\text{10}}}}{{\text{O}}_{\text{2}}}\) formula will give Hell-Volhard-Zeilinsky reaction? (Excluding stereoisomers)
1 1
2 2
3 3
4 4
Explanation:
Hell-Volhard-Zeilinsky reaction (or \({\mathrm{\alpha}}\)-halogenation) is given by carboxylic acids having \({\mathrm{\alpha-\mathrm{H}}}\) atom. Carboxylic acids having \({\mathrm{\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}}}\) formula are: Except structure (IV), all (i.e., structure I, II, III) contain \({\mathrm{\alpha}}\)-H atom
2 (i) red \(\mathrm{P}, \mathrm{Br}_{2}\) / (ii) alc. \(\mathrm{NH}_{3}\) (excess)
3 (i) \(\mathrm{PBr}_{3}, \mathrm{NaCN} /\) (ii) \(\mathrm{LiAlH}_{4}\)
4 None of the above
Explanation:
The given hexanoic acid can be converted into 2-amino hexanoic acid in two steps: (i) Hexanoic acid is converted into \(\alpha\)-bromo hexanoic acid through Hell-Volhard Zelinsky reaction (HVZ) (ii) This \(\alpha\)-bromo hexanoic acid is converted into 2-aminohexanoic acid by heating it with an alcoholic solution of ammonia, and this process is called ammonolysis (cleavage of C-X bond by ammonia).
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323766
The number of \({\rm{\pi }}\) - bonds in compound B is / are
1 1
2 2
3 3
4 0
Explanation:
B: \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCOOH}\)
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323767
Consider the following reactions sequence, Isomers are
323768
One mole each of calcium acetate and calcium propionate undergoes dry distillation to form ' \({\mathrm{x}}\) ' mole(s) of ethyl methyl ketone. Find the value of \({\mathrm{x}}\).
323764
How many isomeric carboxylic acids having \({{\text{C}}_{\text{5}}}{{\text{H}}_{{\text{10}}}}{{\text{O}}_{\text{2}}}\) formula will give Hell-Volhard-Zeilinsky reaction? (Excluding stereoisomers)
1 1
2 2
3 3
4 4
Explanation:
Hell-Volhard-Zeilinsky reaction (or \({\mathrm{\alpha}}\)-halogenation) is given by carboxylic acids having \({\mathrm{\alpha-\mathrm{H}}}\) atom. Carboxylic acids having \({\mathrm{\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}}}\) formula are: Except structure (IV), all (i.e., structure I, II, III) contain \({\mathrm{\alpha}}\)-H atom
2 (i) red \(\mathrm{P}, \mathrm{Br}_{2}\) / (ii) alc. \(\mathrm{NH}_{3}\) (excess)
3 (i) \(\mathrm{PBr}_{3}, \mathrm{NaCN} /\) (ii) \(\mathrm{LiAlH}_{4}\)
4 None of the above
Explanation:
The given hexanoic acid can be converted into 2-amino hexanoic acid in two steps: (i) Hexanoic acid is converted into \(\alpha\)-bromo hexanoic acid through Hell-Volhard Zelinsky reaction (HVZ) (ii) This \(\alpha\)-bromo hexanoic acid is converted into 2-aminohexanoic acid by heating it with an alcoholic solution of ammonia, and this process is called ammonolysis (cleavage of C-X bond by ammonia).
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323766
The number of \({\rm{\pi }}\) - bonds in compound B is / are
1 1
2 2
3 3
4 0
Explanation:
B: \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCOOH}\)
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323767
Consider the following reactions sequence, Isomers are
323768
One mole each of calcium acetate and calcium propionate undergoes dry distillation to form ' \({\mathrm{x}}\) ' mole(s) of ethyl methyl ketone. Find the value of \({\mathrm{x}}\).
