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CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323752 Which reagent distinguish between pentanoic acid and pentanamide?

1 Cold dil.

NaOH

2 Cold. Dil.

{NaHCO}_{3}

3 Cold conc.

H_{2} {SO}_{4}

4 All

Explanation:

(1) Amides are hydrolysed by dilute $NaOH$ to give ${NH}_{3}$
(2) ${NaHCO}_{3}$ reacts with acids to give ${CO}_{2} (g)$ .
(3) Amides are also hydrolysed in acidic conditions.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323753 Assertion :
Both formic acid and oxalic acid decolourize ${KMnO}_{4}$ solution
Reason :
Both are easily oxidised to
${CO}_{2}$ and $H_{2} O$ .

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Formic acid $(HCOOH)$ and oxalic acid $(C_{2} H_{2} O_{4})$ decolorize potassium permanganate by acting as reducing agents in an acidic medium, causing the reduction of permanganate ions $({MnO}_{4}^{-})$ to manganese ions $({Mn}^{2 +})$ and resulting in decolorization. So the option (1) is correct.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323754 Formic acid and acetic acid are distinguished by

1

{NaHCO}_{3}

2

{FeCl}_{3}

3 Victor Meyer's test

4 Tollen's reagent

Explanation:

supporting img
silver mirror
Formic acid(Aldehyde group)
$C H_{3} COOH \to_{reagent}^{Tollen's} Negative test$
Absence of aldehyde group

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323755 Phenol and benzoic acid may be distinguished by

1

{NaHCO}_{3}

2

NaOH

3

Na

4 Both (1) and (3)

Explanation:

Benzoic acid reacts with ${NaHCO}_{3}$ to give effervescence due to the evolution of ${CO}_{2}$ .
supporting img
Phenol does not give effervescence. Phenol and benzoic acid cannot be distinguished by $NaOH$ and $Na$ because both can react with $NaOH$ and $Na$ .

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323752 Which reagent distinguish between pentanoic acid and pentanamide?

1 Cold dil.

NaOH

2 Cold. Dil.

{NaHCO}_{3}

3 Cold conc.

H_{2} {SO}_{4}

4 All

Explanation:

(1) Amides are hydrolysed by dilute $NaOH$ to give ${NH}_{3}$
(2) ${NaHCO}_{3}$ reacts with acids to give ${CO}_{2} (g)$ .
(3) Amides are also hydrolysed in acidic conditions.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323753 Assertion :
Both formic acid and oxalic acid decolourize ${KMnO}_{4}$ solution
Reason :
Both are easily oxidised to
${CO}_{2}$ and $H_{2} O$ .

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Formic acid $(HCOOH)$ and oxalic acid $(C_{2} H_{2} O_{4})$ decolorize potassium permanganate by acting as reducing agents in an acidic medium, causing the reduction of permanganate ions $({MnO}_{4}^{-})$ to manganese ions $({Mn}^{2 +})$ and resulting in decolorization. So the option (1) is correct.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323754 Formic acid and acetic acid are distinguished by

1

{NaHCO}_{3}

2

{FeCl}_{3}

3 Victor Meyer's test

4 Tollen's reagent

Explanation:

supporting img
silver mirror
Formic acid(Aldehyde group)
$C H_{3} COOH \to_{reagent}^{Tollen's} Negative test$
Absence of aldehyde group

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323755 Phenol and benzoic acid may be distinguished by

1

{NaHCO}_{3}

2

NaOH

3

Na

4 Both (1) and (3)

Explanation:

Benzoic acid reacts with ${NaHCO}_{3}$ to give effervescence due to the evolution of ${CO}_{2}$ .
supporting img
Phenol does not give effervescence. Phenol and benzoic acid cannot be distinguished by $NaOH$ and $Na$ because both can react with $NaOH$ and $Na$ .

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323752 Which reagent distinguish between pentanoic acid and pentanamide?

1 Cold dil.

NaOH

2 Cold. Dil.

{NaHCO}_{3}

3 Cold conc.

H_{2} {SO}_{4}

4 All

Explanation:

(1) Amides are hydrolysed by dilute $NaOH$ to give ${NH}_{3}$
(2) ${NaHCO}_{3}$ reacts with acids to give ${CO}_{2} (g)$ .
(3) Amides are also hydrolysed in acidic conditions.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323753 Assertion :
Both formic acid and oxalic acid decolourize ${KMnO}_{4}$ solution
Reason :
Both are easily oxidised to
${CO}_{2}$ and $H_{2} O$ .

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Formic acid $(HCOOH)$ and oxalic acid $(C_{2} H_{2} O_{4})$ decolorize potassium permanganate by acting as reducing agents in an acidic medium, causing the reduction of permanganate ions $({MnO}_{4}^{-})$ to manganese ions $({Mn}^{2 +})$ and resulting in decolorization. So the option (1) is correct.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323754 Formic acid and acetic acid are distinguished by

1

{NaHCO}_{3}

2

{FeCl}_{3}

3 Victor Meyer's test

4 Tollen's reagent

Explanation:

supporting img
silver mirror
Formic acid(Aldehyde group)
$C H_{3} COOH \to_{reagent}^{Tollen's} Negative test$
Absence of aldehyde group

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323755 Phenol and benzoic acid may be distinguished by

1

{NaHCO}_{3}

2

NaOH

3

Na

4 Both (1) and (3)

Explanation:

Benzoic acid reacts with ${NaHCO}_{3}$ to give effervescence due to the evolution of ${CO}_{2}$ .
supporting img
Phenol does not give effervescence. Phenol and benzoic acid cannot be distinguished by $NaOH$ and $Na$ because both can react with $NaOH$ and $Na$ .

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323752 Which reagent distinguish between pentanoic acid and pentanamide?

1 Cold dil.

NaOH

2 Cold. Dil.

{NaHCO}_{3}

3 Cold conc.

H_{2} {SO}_{4}

4 All

Explanation:

(1) Amides are hydrolysed by dilute $NaOH$ to give ${NH}_{3}$
(2) ${NaHCO}_{3}$ reacts with acids to give ${CO}_{2} (g)$ .
(3) Amides are also hydrolysed in acidic conditions.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323753 Assertion :
Both formic acid and oxalic acid decolourize ${KMnO}_{4}$ solution
Reason :
Both are easily oxidised to
${CO}_{2}$ and $H_{2} O$ .

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Formic acid $(HCOOH)$ and oxalic acid $(C_{2} H_{2} O_{4})$ decolorize potassium permanganate by acting as reducing agents in an acidic medium, causing the reduction of permanganate ions $({MnO}_{4}^{-})$ to manganese ions $({Mn}^{2 +})$ and resulting in decolorization. So the option (1) is correct.

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323754 Formic acid and acetic acid are distinguished by

1

{NaHCO}_{3}

2

{FeCl}_{3}

3 Victor Meyer's test

4 Tollen's reagent

Explanation:

supporting img
silver mirror
Formic acid(Aldehyde group)
$C H_{3} COOH \to_{reagent}^{Tollen's} Negative test$
Absence of aldehyde group

CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS

323755 Phenol and benzoic acid may be distinguished by

1

{NaHCO}_{3}

2

NaOH

3

Na

4 Both (1) and (3)

Explanation:

Benzoic acid reacts with ${NaHCO}_{3}$ to give effervescence due to the evolution of ${CO}_{2}$ .
supporting img
Phenol does not give effervescence. Phenol and benzoic acid cannot be distinguished by $NaOH$ and $Na$ because both can react with $NaOH$ and $Na$ .

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