323704
In the following reaction, \(X\) and \(Y\) are respectively: \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{NH}_{3} \rightarrow \mathrm{X} \stackrel{\Delta}{\longrightarrow} \mathrm{Y}+\mathrm{H}_{2} \mathrm{O}\)
323705
Assertion : Fluoroacetic acid is stronger acid than bromoacetic acid. Reason : Acidity depends upon the electron withdrawing effects of the fluorine and bromine.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Fluorine is more electronegative than bromine. Also fluorine is smaller than bromine. These two factors make fluorine highly electron withdrawing (-I effect), which increases the acidic nature of fluoroacetic acid. So the option (1) is correct.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323706
In the compound given below, the correct order of acidity of the positions (X), \((\mathrm{Y})\) and \((\mathrm{Z})\) is
1 \({\rm{Z > X > Y}}\)
2 \({\rm{X > Y > Z}}\)
3 \({\rm{X > Z > Y}}\)
4 \({\rm{Y > X > Z}}\)
Explanation:
Position (X) is most acidic due to – COOH group. \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Y is more acidic than at Z because of presence of electron withdrawing – COOH group in close proximity. Hence, the \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Z is least acidic as it is far away from th ecaboxylic acid group.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323707
Which of the following represents the correct order of the acidity in the given compound?
Group/atom having +I-effect decreases the acidic strength of carboxylic acids while the group/atom having -I-effect increases the acidic strength. Therefore, the correct order is : \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} < \mathrm{CH}_{3} \mathrm{COOH} < \mathrm{HCOOH} < \) \(\mathrm{ClCH}_{2} \mathrm{COOH}\)
323704
In the following reaction, \(X\) and \(Y\) are respectively: \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{NH}_{3} \rightarrow \mathrm{X} \stackrel{\Delta}{\longrightarrow} \mathrm{Y}+\mathrm{H}_{2} \mathrm{O}\)
323705
Assertion : Fluoroacetic acid is stronger acid than bromoacetic acid. Reason : Acidity depends upon the electron withdrawing effects of the fluorine and bromine.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Fluorine is more electronegative than bromine. Also fluorine is smaller than bromine. These two factors make fluorine highly electron withdrawing (-I effect), which increases the acidic nature of fluoroacetic acid. So the option (1) is correct.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323706
In the compound given below, the correct order of acidity of the positions (X), \((\mathrm{Y})\) and \((\mathrm{Z})\) is
1 \({\rm{Z > X > Y}}\)
2 \({\rm{X > Y > Z}}\)
3 \({\rm{X > Z > Y}}\)
4 \({\rm{Y > X > Z}}\)
Explanation:
Position (X) is most acidic due to – COOH group. \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Y is more acidic than at Z because of presence of electron withdrawing – COOH group in close proximity. Hence, the \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Z is least acidic as it is far away from th ecaboxylic acid group.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323707
Which of the following represents the correct order of the acidity in the given compound?
Group/atom having +I-effect decreases the acidic strength of carboxylic acids while the group/atom having -I-effect increases the acidic strength. Therefore, the correct order is : \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} < \mathrm{CH}_{3} \mathrm{COOH} < \mathrm{HCOOH} < \) \(\mathrm{ClCH}_{2} \mathrm{COOH}\)
323704
In the following reaction, \(X\) and \(Y\) are respectively: \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{NH}_{3} \rightarrow \mathrm{X} \stackrel{\Delta}{\longrightarrow} \mathrm{Y}+\mathrm{H}_{2} \mathrm{O}\)
323705
Assertion : Fluoroacetic acid is stronger acid than bromoacetic acid. Reason : Acidity depends upon the electron withdrawing effects of the fluorine and bromine.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Fluorine is more electronegative than bromine. Also fluorine is smaller than bromine. These two factors make fluorine highly electron withdrawing (-I effect), which increases the acidic nature of fluoroacetic acid. So the option (1) is correct.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323706
In the compound given below, the correct order of acidity of the positions (X), \((\mathrm{Y})\) and \((\mathrm{Z})\) is
1 \({\rm{Z > X > Y}}\)
2 \({\rm{X > Y > Z}}\)
3 \({\rm{X > Z > Y}}\)
4 \({\rm{Y > X > Z}}\)
Explanation:
Position (X) is most acidic due to – COOH group. \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Y is more acidic than at Z because of presence of electron withdrawing – COOH group in close proximity. Hence, the \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Z is least acidic as it is far away from th ecaboxylic acid group.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323707
Which of the following represents the correct order of the acidity in the given compound?
Group/atom having +I-effect decreases the acidic strength of carboxylic acids while the group/atom having -I-effect increases the acidic strength. Therefore, the correct order is : \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} < \mathrm{CH}_{3} \mathrm{COOH} < \mathrm{HCOOH} < \) \(\mathrm{ClCH}_{2} \mathrm{COOH}\)
323704
In the following reaction, \(X\) and \(Y\) are respectively: \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{NH}_{3} \rightarrow \mathrm{X} \stackrel{\Delta}{\longrightarrow} \mathrm{Y}+\mathrm{H}_{2} \mathrm{O}\)
323705
Assertion : Fluoroacetic acid is stronger acid than bromoacetic acid. Reason : Acidity depends upon the electron withdrawing effects of the fluorine and bromine.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Fluorine is more electronegative than bromine. Also fluorine is smaller than bromine. These two factors make fluorine highly electron withdrawing (-I effect), which increases the acidic nature of fluoroacetic acid. So the option (1) is correct.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323706
In the compound given below, the correct order of acidity of the positions (X), \((\mathrm{Y})\) and \((\mathrm{Z})\) is
1 \({\rm{Z > X > Y}}\)
2 \({\rm{X > Y > Z}}\)
3 \({\rm{X > Z > Y}}\)
4 \({\rm{Y > X > Z}}\)
Explanation:
Position (X) is most acidic due to – COOH group. \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Y is more acidic than at Z because of presence of electron withdrawing – COOH group in close proximity. Hence, the \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Z is least acidic as it is far away from th ecaboxylic acid group.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323707
Which of the following represents the correct order of the acidity in the given compound?
Group/atom having +I-effect decreases the acidic strength of carboxylic acids while the group/atom having -I-effect increases the acidic strength. Therefore, the correct order is : \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} < \mathrm{CH}_{3} \mathrm{COOH} < \mathrm{HCOOH} < \) \(\mathrm{ClCH}_{2} \mathrm{COOH}\)
323704
In the following reaction, \(X\) and \(Y\) are respectively: \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{NH}_{3} \rightarrow \mathrm{X} \stackrel{\Delta}{\longrightarrow} \mathrm{Y}+\mathrm{H}_{2} \mathrm{O}\)
323705
Assertion : Fluoroacetic acid is stronger acid than bromoacetic acid. Reason : Acidity depends upon the electron withdrawing effects of the fluorine and bromine.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Fluorine is more electronegative than bromine. Also fluorine is smaller than bromine. These two factors make fluorine highly electron withdrawing (-I effect), which increases the acidic nature of fluoroacetic acid. So the option (1) is correct.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323706
In the compound given below, the correct order of acidity of the positions (X), \((\mathrm{Y})\) and \((\mathrm{Z})\) is
1 \({\rm{Z > X > Y}}\)
2 \({\rm{X > Y > Z}}\)
3 \({\rm{X > Z > Y}}\)
4 \({\rm{Y > X > Z}}\)
Explanation:
Position (X) is most acidic due to – COOH group. \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Y is more acidic than at Z because of presence of electron withdrawing – COOH group in close proximity. Hence, the \( - {\rm{NH}}_{\rm{3}}^{\rm{ + }}\) group at position Z is least acidic as it is far away from th ecaboxylic acid group.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323707
Which of the following represents the correct order of the acidity in the given compound?
Group/atom having +I-effect decreases the acidic strength of carboxylic acids while the group/atom having -I-effect increases the acidic strength. Therefore, the correct order is : \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} < \mathrm{CH}_{3} \mathrm{COOH} < \mathrm{HCOOH} < \) \(\mathrm{ClCH}_{2} \mathrm{COOH}\)
