NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323188
Two organic compounds \({\text{A}}\) and \({\text{B}}\) react with sodium metal and release \(\mathrm{H}_{2}\) gas. \({\text{A}}\) and \({\text{B}}\) react with each other to give ethyl acetate. The \(\mathrm{A}\) and \(\mathrm{B}\) are:
1 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\)
2 \(\mathrm{HCOOH}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\)
3 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{CH}_{3} \mathrm{OH}\)
4 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{HCOOH}\)
Explanation:
Both acids and alcohols react with sodium. \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \stackrel{\mathrm{H}^{+}}{\rightleftharpoons}\) \(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{C}}{{\text{H}}_3}{\text{COO}}{{\text{C}}_2}{{\text{H}}_5} + {{\text{H}}_2}{\text{O}}\)
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323189
The correct order for acidity of the following hydroxyl compound is
Choose the correct answer from the options given below:
1 E \(>\) C \(>\) D \(>\) A \(>\) B
2 E \(>\) D \(>\) C \(>\) B \(>\) A
3 D \(>\) E \(>\) C \(>\) A \(>\) B
4 C \(>\) E \(>\) D \(>\) B \(>\) A
Explanation:
Among the given compounds, p – nitrophenol is the most acidic as it consists of \(-\mathrm{NO}_{2}\) group which is an EWG. Thus, phenol is less acidic than p – nitrophenol. The \(\left(-\mathrm{OCH}_{3}\right)\) groups exhibits \( + \,{\rm{I}}\) effect and is an electron donating group.Thereby, it decreases the acidity of phenol. 2 methylpropan –2 –ol \(\left(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}\right)\) is the least acidic due to +I effect of three alkyl groups. Whereas, methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) is more acidic than \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}\) as only one alkyl group is present in it.Thus, option (1) shows the correct order. Alcohols are less acidic than phenols.
JEE - 2023
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323190
\(\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) is stronger acid than \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) because of :
1 \({\text{ - I}}\) effect of increases negative charge on \(\mathrm{O}\) atom of alcohol.
2 \({\text{ - I}}\) effect of \(\mathrm{Cl}\) disperses negative charge on \(\mathrm{O}\) atom to produce more stable cation
3 \({\text{ - I}}\) effect of \({\text{Cl}}\) disperses negative charge on \({\text{O}}\) atom to produce more stable anion.
4 None of these
Explanation:
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323191
Assertion : Alcohols turn blue litmus red. Reason : Alcohols give red colour with ceric ammonium nitrate solution.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Alcohols are considered weak acids and, as a result, they do not exhibit the typical acidic behavior of turning blue litmus paper red. Ceric ammonium nitrate test serves as an analytical method for identifying alcohols. In this test alcohols react with the reagent to produce a distinctive red coloration. So the option (4) is correct.
323188
Two organic compounds \({\text{A}}\) and \({\text{B}}\) react with sodium metal and release \(\mathrm{H}_{2}\) gas. \({\text{A}}\) and \({\text{B}}\) react with each other to give ethyl acetate. The \(\mathrm{A}\) and \(\mathrm{B}\) are:
1 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\)
2 \(\mathrm{HCOOH}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\)
3 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{CH}_{3} \mathrm{OH}\)
4 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{HCOOH}\)
Explanation:
Both acids and alcohols react with sodium. \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \stackrel{\mathrm{H}^{+}}{\rightleftharpoons}\) \(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{C}}{{\text{H}}_3}{\text{COO}}{{\text{C}}_2}{{\text{H}}_5} + {{\text{H}}_2}{\text{O}}\)
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323189
The correct order for acidity of the following hydroxyl compound is
Choose the correct answer from the options given below:
1 E \(>\) C \(>\) D \(>\) A \(>\) B
2 E \(>\) D \(>\) C \(>\) B \(>\) A
3 D \(>\) E \(>\) C \(>\) A \(>\) B
4 C \(>\) E \(>\) D \(>\) B \(>\) A
Explanation:
Among the given compounds, p – nitrophenol is the most acidic as it consists of \(-\mathrm{NO}_{2}\) group which is an EWG. Thus, phenol is less acidic than p – nitrophenol. The \(\left(-\mathrm{OCH}_{3}\right)\) groups exhibits \( + \,{\rm{I}}\) effect and is an electron donating group.Thereby, it decreases the acidity of phenol. 2 methylpropan –2 –ol \(\left(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}\right)\) is the least acidic due to +I effect of three alkyl groups. Whereas, methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) is more acidic than \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}\) as only one alkyl group is present in it.Thus, option (1) shows the correct order. Alcohols are less acidic than phenols.
JEE - 2023
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323190
\(\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) is stronger acid than \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) because of :
1 \({\text{ - I}}\) effect of increases negative charge on \(\mathrm{O}\) atom of alcohol.
2 \({\text{ - I}}\) effect of \(\mathrm{Cl}\) disperses negative charge on \(\mathrm{O}\) atom to produce more stable cation
3 \({\text{ - I}}\) effect of \({\text{Cl}}\) disperses negative charge on \({\text{O}}\) atom to produce more stable anion.
4 None of these
Explanation:
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323191
Assertion : Alcohols turn blue litmus red. Reason : Alcohols give red colour with ceric ammonium nitrate solution.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Alcohols are considered weak acids and, as a result, they do not exhibit the typical acidic behavior of turning blue litmus paper red. Ceric ammonium nitrate test serves as an analytical method for identifying alcohols. In this test alcohols react with the reagent to produce a distinctive red coloration. So the option (4) is correct.
323188
Two organic compounds \({\text{A}}\) and \({\text{B}}\) react with sodium metal and release \(\mathrm{H}_{2}\) gas. \({\text{A}}\) and \({\text{B}}\) react with each other to give ethyl acetate. The \(\mathrm{A}\) and \(\mathrm{B}\) are:
1 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\)
2 \(\mathrm{HCOOH}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\)
3 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{CH}_{3} \mathrm{OH}\)
4 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{HCOOH}\)
Explanation:
Both acids and alcohols react with sodium. \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \stackrel{\mathrm{H}^{+}}{\rightleftharpoons}\) \(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{C}}{{\text{H}}_3}{\text{COO}}{{\text{C}}_2}{{\text{H}}_5} + {{\text{H}}_2}{\text{O}}\)
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323189
The correct order for acidity of the following hydroxyl compound is
Choose the correct answer from the options given below:
1 E \(>\) C \(>\) D \(>\) A \(>\) B
2 E \(>\) D \(>\) C \(>\) B \(>\) A
3 D \(>\) E \(>\) C \(>\) A \(>\) B
4 C \(>\) E \(>\) D \(>\) B \(>\) A
Explanation:
Among the given compounds, p – nitrophenol is the most acidic as it consists of \(-\mathrm{NO}_{2}\) group which is an EWG. Thus, phenol is less acidic than p – nitrophenol. The \(\left(-\mathrm{OCH}_{3}\right)\) groups exhibits \( + \,{\rm{I}}\) effect and is an electron donating group.Thereby, it decreases the acidity of phenol. 2 methylpropan –2 –ol \(\left(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}\right)\) is the least acidic due to +I effect of three alkyl groups. Whereas, methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) is more acidic than \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}\) as only one alkyl group is present in it.Thus, option (1) shows the correct order. Alcohols are less acidic than phenols.
JEE - 2023
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323190
\(\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) is stronger acid than \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) because of :
1 \({\text{ - I}}\) effect of increases negative charge on \(\mathrm{O}\) atom of alcohol.
2 \({\text{ - I}}\) effect of \(\mathrm{Cl}\) disperses negative charge on \(\mathrm{O}\) atom to produce more stable cation
3 \({\text{ - I}}\) effect of \({\text{Cl}}\) disperses negative charge on \({\text{O}}\) atom to produce more stable anion.
4 None of these
Explanation:
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323191
Assertion : Alcohols turn blue litmus red. Reason : Alcohols give red colour with ceric ammonium nitrate solution.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Alcohols are considered weak acids and, as a result, they do not exhibit the typical acidic behavior of turning blue litmus paper red. Ceric ammonium nitrate test serves as an analytical method for identifying alcohols. In this test alcohols react with the reagent to produce a distinctive red coloration. So the option (4) is correct.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323188
Two organic compounds \({\text{A}}\) and \({\text{B}}\) react with sodium metal and release \(\mathrm{H}_{2}\) gas. \({\text{A}}\) and \({\text{B}}\) react with each other to give ethyl acetate. The \(\mathrm{A}\) and \(\mathrm{B}\) are:
1 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\)
2 \(\mathrm{HCOOH}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\)
3 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{CH}_{3} \mathrm{OH}\)
4 \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{HCOOH}\)
Explanation:
Both acids and alcohols react with sodium. \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \stackrel{\mathrm{H}^{+}}{\rightleftharpoons}\) \(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{C}}{{\text{H}}_3}{\text{COO}}{{\text{C}}_2}{{\text{H}}_5} + {{\text{H}}_2}{\text{O}}\)
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323189
The correct order for acidity of the following hydroxyl compound is
Choose the correct answer from the options given below:
1 E \(>\) C \(>\) D \(>\) A \(>\) B
2 E \(>\) D \(>\) C \(>\) B \(>\) A
3 D \(>\) E \(>\) C \(>\) A \(>\) B
4 C \(>\) E \(>\) D \(>\) B \(>\) A
Explanation:
Among the given compounds, p – nitrophenol is the most acidic as it consists of \(-\mathrm{NO}_{2}\) group which is an EWG. Thus, phenol is less acidic than p – nitrophenol. The \(\left(-\mathrm{OCH}_{3}\right)\) groups exhibits \( + \,{\rm{I}}\) effect and is an electron donating group.Thereby, it decreases the acidity of phenol. 2 methylpropan –2 –ol \(\left(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}\right)\) is the least acidic due to +I effect of three alkyl groups. Whereas, methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) is more acidic than \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}\) as only one alkyl group is present in it.Thus, option (1) shows the correct order. Alcohols are less acidic than phenols.
JEE - 2023
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323190
\(\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) is stronger acid than \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) because of :
1 \({\text{ - I}}\) effect of increases negative charge on \(\mathrm{O}\) atom of alcohol.
2 \({\text{ - I}}\) effect of \(\mathrm{Cl}\) disperses negative charge on \(\mathrm{O}\) atom to produce more stable cation
3 \({\text{ - I}}\) effect of \({\text{Cl}}\) disperses negative charge on \({\text{O}}\) atom to produce more stable anion.
4 None of these
Explanation:
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323191
Assertion : Alcohols turn blue litmus red. Reason : Alcohols give red colour with ceric ammonium nitrate solution.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Alcohols are considered weak acids and, as a result, they do not exhibit the typical acidic behavior of turning blue litmus paper red. Ceric ammonium nitrate test serves as an analytical method for identifying alcohols. In this test alcohols react with the reagent to produce a distinctive red coloration. So the option (4) is correct.
