Carbon tetrachloride has tetrahedral structure and its four polar \(\mathrm{C}-\mathrm{Cl}\) bonds cancel each other dipole moment which results in net dipole moment zero.
CHXII10:HALOALKANES AND HALOARENES
322746
The correct decreasing order of dipole moment \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}\) , \({\rm{C}}{{\rm{H}}_3}B{r_3}\) and \(C{H_3}F\) is
\({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\) is expected to have higest dipole moment But bon length is smaller than bond length. Hence \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\) dipole moment is less than \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}\). Hence the correct decreasing order of dipole moment in \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl,C}}{{\rm{H}}_{\rm{3}}}{\rm{B}}{{\rm{r}}_{\rm{3}}}{\rm{,C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\,\,{\rm{is}}\) \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}{\mkern 1mu} {\mkern 1mu} {\rm{ > }}{\mkern 1mu} {\mkern 1mu} {\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}{\mkern 1mu} {\mkern 1mu} {\rm{ > }}{\mkern 1mu} {\mkern 1mu} {\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{B}}{{\rm{r}}_{\rm{3}}}{\rm{.}}\)
CHXII10:HALOALKANES AND HALOARENES
322747
Which one of the following compounds has the highest dipole moment?
1 \(\mathrm{CH}_{3} \mathrm{NO}_{2}\)
2 \(\mathrm{CH}_{3} \mathrm{Cl}\)
3 \(\mathrm{CCl}_{4}\)
4 \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\)
Explanation:
More polarity more is dipole moment.
CHXII10:HALOALKANES AND HALOARENES
322748
Arrange the following in the decreasing order of dipole moment.
1 I \(>\) II \(>\) III
2 II \(>\) I \(>\) III
3 III \(>\) II \(>\) I
4 I \(>\) III \(>\) II
Explanation:
I \(>\) II \(>\) III
There is intramolecular hydrogen bonding which decreases the bond angle \(\left( < 60^{\circ}\right)\) hence the dipole is decreased.
Dipole-dipole repulsion of two chlorine atoms in ortho-position increases the bond angle \(\left(>60^{\circ}\right)\) hence the dipole is decreased.
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXII10:HALOALKANES AND HALOARENES
322745
The compound with no dipole moment is
1 Methyl chloride
2 Carbon tetrachloride
3 Methylene chloride
4 Chloroform
Explanation:
Carbon tetrachloride has tetrahedral structure and its four polar \(\mathrm{C}-\mathrm{Cl}\) bonds cancel each other dipole moment which results in net dipole moment zero.
CHXII10:HALOALKANES AND HALOARENES
322746
The correct decreasing order of dipole moment \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}\) , \({\rm{C}}{{\rm{H}}_3}B{r_3}\) and \(C{H_3}F\) is
\({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\) is expected to have higest dipole moment But bon length is smaller than bond length. Hence \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\) dipole moment is less than \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}\). Hence the correct decreasing order of dipole moment in \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl,C}}{{\rm{H}}_{\rm{3}}}{\rm{B}}{{\rm{r}}_{\rm{3}}}{\rm{,C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\,\,{\rm{is}}\) \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}{\mkern 1mu} {\mkern 1mu} {\rm{ > }}{\mkern 1mu} {\mkern 1mu} {\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}{\mkern 1mu} {\mkern 1mu} {\rm{ > }}{\mkern 1mu} {\mkern 1mu} {\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{B}}{{\rm{r}}_{\rm{3}}}{\rm{.}}\)
CHXII10:HALOALKANES AND HALOARENES
322747
Which one of the following compounds has the highest dipole moment?
1 \(\mathrm{CH}_{3} \mathrm{NO}_{2}\)
2 \(\mathrm{CH}_{3} \mathrm{Cl}\)
3 \(\mathrm{CCl}_{4}\)
4 \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\)
Explanation:
More polarity more is dipole moment.
CHXII10:HALOALKANES AND HALOARENES
322748
Arrange the following in the decreasing order of dipole moment.
1 I \(>\) II \(>\) III
2 II \(>\) I \(>\) III
3 III \(>\) II \(>\) I
4 I \(>\) III \(>\) II
Explanation:
I \(>\) II \(>\) III
There is intramolecular hydrogen bonding which decreases the bond angle \(\left( < 60^{\circ}\right)\) hence the dipole is decreased.
Dipole-dipole repulsion of two chlorine atoms in ortho-position increases the bond angle \(\left(>60^{\circ}\right)\) hence the dipole is decreased.
Carbon tetrachloride has tetrahedral structure and its four polar \(\mathrm{C}-\mathrm{Cl}\) bonds cancel each other dipole moment which results in net dipole moment zero.
CHXII10:HALOALKANES AND HALOARENES
322746
The correct decreasing order of dipole moment \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}\) , \({\rm{C}}{{\rm{H}}_3}B{r_3}\) and \(C{H_3}F\) is
\({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\) is expected to have higest dipole moment But bon length is smaller than bond length. Hence \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\) dipole moment is less than \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}\). Hence the correct decreasing order of dipole moment in \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl,C}}{{\rm{H}}_{\rm{3}}}{\rm{B}}{{\rm{r}}_{\rm{3}}}{\rm{,C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\,\,{\rm{is}}\) \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}{\mkern 1mu} {\mkern 1mu} {\rm{ > }}{\mkern 1mu} {\mkern 1mu} {\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}{\mkern 1mu} {\mkern 1mu} {\rm{ > }}{\mkern 1mu} {\mkern 1mu} {\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{B}}{{\rm{r}}_{\rm{3}}}{\rm{.}}\)
CHXII10:HALOALKANES AND HALOARENES
322747
Which one of the following compounds has the highest dipole moment?
1 \(\mathrm{CH}_{3} \mathrm{NO}_{2}\)
2 \(\mathrm{CH}_{3} \mathrm{Cl}\)
3 \(\mathrm{CCl}_{4}\)
4 \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\)
Explanation:
More polarity more is dipole moment.
CHXII10:HALOALKANES AND HALOARENES
322748
Arrange the following in the decreasing order of dipole moment.
1 I \(>\) II \(>\) III
2 II \(>\) I \(>\) III
3 III \(>\) II \(>\) I
4 I \(>\) III \(>\) II
Explanation:
I \(>\) II \(>\) III
There is intramolecular hydrogen bonding which decreases the bond angle \(\left( < 60^{\circ}\right)\) hence the dipole is decreased.
Dipole-dipole repulsion of two chlorine atoms in ortho-position increases the bond angle \(\left(>60^{\circ}\right)\) hence the dipole is decreased.
Carbon tetrachloride has tetrahedral structure and its four polar \(\mathrm{C}-\mathrm{Cl}\) bonds cancel each other dipole moment which results in net dipole moment zero.
CHXII10:HALOALKANES AND HALOARENES
322746
The correct decreasing order of dipole moment \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}\) , \({\rm{C}}{{\rm{H}}_3}B{r_3}\) and \(C{H_3}F\) is
\({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\) is expected to have higest dipole moment But bon length is smaller than bond length. Hence \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\) dipole moment is less than \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}\). Hence the correct decreasing order of dipole moment in \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl,C}}{{\rm{H}}_{\rm{3}}}{\rm{B}}{{\rm{r}}_{\rm{3}}}{\rm{,C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}\,\,{\rm{is}}\) \({\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{Cl}}{\mkern 1mu} {\mkern 1mu} {\rm{ > }}{\mkern 1mu} {\mkern 1mu} {\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{F}}{\mkern 1mu} {\mkern 1mu} {\rm{ > }}{\mkern 1mu} {\mkern 1mu} {\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{B}}{{\rm{r}}_{\rm{3}}}{\rm{.}}\)
CHXII10:HALOALKANES AND HALOARENES
322747
Which one of the following compounds has the highest dipole moment?
1 \(\mathrm{CH}_{3} \mathrm{NO}_{2}\)
2 \(\mathrm{CH}_{3} \mathrm{Cl}\)
3 \(\mathrm{CCl}_{4}\)
4 \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\)
Explanation:
More polarity more is dipole moment.
CHXII10:HALOALKANES AND HALOARENES
322748
Arrange the following in the decreasing order of dipole moment.
1 I \(>\) II \(>\) III
2 II \(>\) I \(>\) III
3 III \(>\) II \(>\) I
4 I \(>\) III \(>\) II
Explanation:
I \(>\) II \(>\) III
There is intramolecular hydrogen bonding which decreases the bond angle \(\left( < 60^{\circ}\right)\) hence the dipole is decreased.
Dipole-dipole repulsion of two chlorine atoms in ortho-position increases the bond angle \(\left(>60^{\circ}\right)\) hence the dipole is decreased.
