Among the given coordination compounds, \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{SO}_{4}\) gives a white precipitate on treatment with an aqueous solution of barium chloride. This can be explained by the following reaction. \(\begin{aligned}& {\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{SO}_{4}+\mathrm{BaCl}_{2}(\mathrm{aq})} \\& \quad \longrightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{Cl}_{2}+\underset{\text { Whiteppt. }}{\mathrm{BaSO}_{4}(\mathrm{~s})}\end{aligned}\) The other given compounds do not give white ppt. due to absence of \(\mathrm{SO}_{4}^{2-}\) ions.
CHXII09:COORDINATION COMPOUNDS
322373
Pick a poor electrolytic conductor complex in solution
The complex furnishing least number of ions in solution will be poor electrolytic conductor.
CHXII09:COORDINATION COMPOUNDS
322374
Which of the following has the highest molar conductivity under similar conditions?
1 Diamminedichloroplatinum(II)
2 Tetraamminedichlorocobalt(III) chloride
3 Potassium hexacyanoferrate(II)
4 Hexaaquachromium(III) chloride
Explanation:
\({\mathrm{\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right] \rightarrow}}\) No.of ions in aq. solution is 0. \({\mathrm{\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \rightarrow}}\) No. of ions in aq. solution is 2 . \({\mathrm{\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow}}\) No. of ions in aq. solution is 5 \({\mathrm{\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{3} \rightarrow}}\) No. of ions in aq. solution is 4 . So, \({\mathrm{\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]}}\) will show highest conductivity, as it possesses highest no. of ions.
Among the given coordination compounds, \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{SO}_{4}\) gives a white precipitate on treatment with an aqueous solution of barium chloride. This can be explained by the following reaction. \(\begin{aligned}& {\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{SO}_{4}+\mathrm{BaCl}_{2}(\mathrm{aq})} \\& \quad \longrightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{Cl}_{2}+\underset{\text { Whiteppt. }}{\mathrm{BaSO}_{4}(\mathrm{~s})}\end{aligned}\) The other given compounds do not give white ppt. due to absence of \(\mathrm{SO}_{4}^{2-}\) ions.
CHXII09:COORDINATION COMPOUNDS
322373
Pick a poor electrolytic conductor complex in solution
The complex furnishing least number of ions in solution will be poor electrolytic conductor.
CHXII09:COORDINATION COMPOUNDS
322374
Which of the following has the highest molar conductivity under similar conditions?
1 Diamminedichloroplatinum(II)
2 Tetraamminedichlorocobalt(III) chloride
3 Potassium hexacyanoferrate(II)
4 Hexaaquachromium(III) chloride
Explanation:
\({\mathrm{\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right] \rightarrow}}\) No.of ions in aq. solution is 0. \({\mathrm{\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \rightarrow}}\) No. of ions in aq. solution is 2 . \({\mathrm{\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow}}\) No. of ions in aq. solution is 5 \({\mathrm{\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{3} \rightarrow}}\) No. of ions in aq. solution is 4 . So, \({\mathrm{\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]}}\) will show highest conductivity, as it possesses highest no. of ions.
Among the given coordination compounds, \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{SO}_{4}\) gives a white precipitate on treatment with an aqueous solution of barium chloride. This can be explained by the following reaction. \(\begin{aligned}& {\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{SO}_{4}+\mathrm{BaCl}_{2}(\mathrm{aq})} \\& \quad \longrightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{Cl}_{2}+\underset{\text { Whiteppt. }}{\mathrm{BaSO}_{4}(\mathrm{~s})}\end{aligned}\) The other given compounds do not give white ppt. due to absence of \(\mathrm{SO}_{4}^{2-}\) ions.
CHXII09:COORDINATION COMPOUNDS
322373
Pick a poor electrolytic conductor complex in solution
The complex furnishing least number of ions in solution will be poor electrolytic conductor.
CHXII09:COORDINATION COMPOUNDS
322374
Which of the following has the highest molar conductivity under similar conditions?
1 Diamminedichloroplatinum(II)
2 Tetraamminedichlorocobalt(III) chloride
3 Potassium hexacyanoferrate(II)
4 Hexaaquachromium(III) chloride
Explanation:
\({\mathrm{\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right] \rightarrow}}\) No.of ions in aq. solution is 0. \({\mathrm{\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \rightarrow}}\) No. of ions in aq. solution is 2 . \({\mathrm{\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow}}\) No. of ions in aq. solution is 5 \({\mathrm{\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{3} \rightarrow}}\) No. of ions in aq. solution is 4 . So, \({\mathrm{\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]}}\) will show highest conductivity, as it possesses highest no. of ions.
Among the given coordination compounds, \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{SO}_{4}\) gives a white precipitate on treatment with an aqueous solution of barium chloride. This can be explained by the following reaction. \(\begin{aligned}& {\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{SO}_{4}+\mathrm{BaCl}_{2}(\mathrm{aq})} \\& \quad \longrightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{Cl}_{2}+\underset{\text { Whiteppt. }}{\mathrm{BaSO}_{4}(\mathrm{~s})}\end{aligned}\) The other given compounds do not give white ppt. due to absence of \(\mathrm{SO}_{4}^{2-}\) ions.
CHXII09:COORDINATION COMPOUNDS
322373
Pick a poor electrolytic conductor complex in solution
The complex furnishing least number of ions in solution will be poor electrolytic conductor.
CHXII09:COORDINATION COMPOUNDS
322374
Which of the following has the highest molar conductivity under similar conditions?
1 Diamminedichloroplatinum(II)
2 Tetraamminedichlorocobalt(III) chloride
3 Potassium hexacyanoferrate(II)
4 Hexaaquachromium(III) chloride
Explanation:
\({\mathrm{\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right] \rightarrow}}\) No.of ions in aq. solution is 0. \({\mathrm{\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \rightarrow}}\) No. of ions in aq. solution is 2 . \({\mathrm{\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow}}\) No. of ions in aq. solution is 5 \({\mathrm{\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{3} \rightarrow}}\) No. of ions in aq. solution is 4 . So, \({\mathrm{\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]}}\) will show highest conductivity, as it possesses highest no. of ions.
