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CHXII09:COORDINATION COMPOUNDS

322132 The number of moles of ions formed on complete ionisation of 1 mole of $Co {({NH}_{3})}_{3} {Cl}_{3}$ is

1 4

2 3

3 2

4 0

Explanation:

$[Co {({NH}_{3})}_{3} {Cl}_{3}]$ is a neutral complex and will not get ionised.

CHXII09:COORDINATION COMPOUNDS

322133 Which has a complex cation?

1

Ag {({NH}_{3})}_{2} Cl

2

{Na}_{3} {AlF}_{6}

3

{LiAlH}_{4}

4

K_{2} {PtCl}_{6}

Explanation:

${[Ag {({NH}_{3})}_{2}]}^{+}$ is complex cation. Rest all have complex anion i.e.,
${[{AlF}_{6}]}^{3 -}, {[{AlH}_{4}]}^{-}, {[{PtCl}_{6}]}^{2 -}$ .

CHXII09:COORDINATION COMPOUNDS

322134 Which of the following is not an anionic complex?

1

[Cu {({NH}_{3})}_{4}] {Cl}_{2}

2

K_{4} [Fe (CN)_{6}]

3

K_{3} [Fe (CN)_{6}]

4

{[{NiCl}_{4}]}^{2 -}

Explanation:

Positive charge if appears on the coordination sphere, the complex thus obtained is known as cationic complex.
$[Cu {({NH}_{3})}_{4}] {Cl}_{2} ⇌ {[Cu {({NH}_{3})}_{4}]}^{2 +} + 2 {Cl}^{-}$
$K_{4} [Fe (CN)_{6}] ⇌ 4 K^{+} + {[Fe (CN)_{6}]}^{-}$ $K_{3} [Fe (CN)_{6}] ⇌ 3 K^{+} + {[Fe (CN)_{6}]}^{3 -}$
${[{NiCl}_{4}]}^{2 -}$
Therefore, $[Cu {({NH}_{3})}_{4}] {Cl}_{2}$ is not an anionic complex, it is a cationic complex.

CHXII09:COORDINATION COMPOUNDS

322135 What is the charge of the complex formed by a platinum(II) metal ion surrounded by two ammonia molecules and two bromide ions?

1 0

2 1

3

- 1

4 2

Explanation:

Charge on the given complex $= (+ 2) + 2 (0) + 2 (- 1) = 0$

CHXII09:COORDINATION COMPOUNDS

322132 The number of moles of ions formed on complete ionisation of 1 mole of $Co {({NH}_{3})}_{3} {Cl}_{3}$ is

1 4

2 3

3 2

4 0

Explanation:

$[Co {({NH}_{3})}_{3} {Cl}_{3}]$ is a neutral complex and will not get ionised.

CHXII09:COORDINATION COMPOUNDS

322133 Which has a complex cation?

1

Ag {({NH}_{3})}_{2} Cl

2

{Na}_{3} {AlF}_{6}

3

{LiAlH}_{4}

4

K_{2} {PtCl}_{6}

Explanation:

${[Ag {({NH}_{3})}_{2}]}^{+}$ is complex cation. Rest all have complex anion i.e.,
${[{AlF}_{6}]}^{3 -}, {[{AlH}_{4}]}^{-}, {[{PtCl}_{6}]}^{2 -}$ .

CHXII09:COORDINATION COMPOUNDS

322134 Which of the following is not an anionic complex?

1

[Cu {({NH}_{3})}_{4}] {Cl}_{2}

2

K_{4} [Fe (CN)_{6}]

3

K_{3} [Fe (CN)_{6}]

4

{[{NiCl}_{4}]}^{2 -}

Explanation:

Positive charge if appears on the coordination sphere, the complex thus obtained is known as cationic complex.
$[Cu {({NH}_{3})}_{4}] {Cl}_{2} ⇌ {[Cu {({NH}_{3})}_{4}]}^{2 +} + 2 {Cl}^{-}$
$K_{4} [Fe (CN)_{6}] ⇌ 4 K^{+} + {[Fe (CN)_{6}]}^{-}$ $K_{3} [Fe (CN)_{6}] ⇌ 3 K^{+} + {[Fe (CN)_{6}]}^{3 -}$
${[{NiCl}_{4}]}^{2 -}$
Therefore, $[Cu {({NH}_{3})}_{4}] {Cl}_{2}$ is not an anionic complex, it is a cationic complex.

CHXII09:COORDINATION COMPOUNDS

322135 What is the charge of the complex formed by a platinum(II) metal ion surrounded by two ammonia molecules and two bromide ions?

1 0

2 1

3

- 1

4 2

Explanation:

Charge on the given complex $= (+ 2) + 2 (0) + 2 (- 1) = 0$

CHXII09:COORDINATION COMPOUNDS

322132 The number of moles of ions formed on complete ionisation of 1 mole of $Co {({NH}_{3})}_{3} {Cl}_{3}$ is

1 4

2 3

3 2

4 0

Explanation:

$[Co {({NH}_{3})}_{3} {Cl}_{3}]$ is a neutral complex and will not get ionised.

CHXII09:COORDINATION COMPOUNDS

322133 Which has a complex cation?

1

Ag {({NH}_{3})}_{2} Cl

2

{Na}_{3} {AlF}_{6}

3

{LiAlH}_{4}

4

K_{2} {PtCl}_{6}

Explanation:

${[Ag {({NH}_{3})}_{2}]}^{+}$ is complex cation. Rest all have complex anion i.e.,
${[{AlF}_{6}]}^{3 -}, {[{AlH}_{4}]}^{-}, {[{PtCl}_{6}]}^{2 -}$ .

CHXII09:COORDINATION COMPOUNDS

322134 Which of the following is not an anionic complex?

1

[Cu {({NH}_{3})}_{4}] {Cl}_{2}

2

K_{4} [Fe (CN)_{6}]

3

K_{3} [Fe (CN)_{6}]

4

{[{NiCl}_{4}]}^{2 -}

Explanation:

Positive charge if appears on the coordination sphere, the complex thus obtained is known as cationic complex.
$[Cu {({NH}_{3})}_{4}] {Cl}_{2} ⇌ {[Cu {({NH}_{3})}_{4}]}^{2 +} + 2 {Cl}^{-}$
$K_{4} [Fe (CN)_{6}] ⇌ 4 K^{+} + {[Fe (CN)_{6}]}^{-}$ $K_{3} [Fe (CN)_{6}] ⇌ 3 K^{+} + {[Fe (CN)_{6}]}^{3 -}$
${[{NiCl}_{4}]}^{2 -}$
Therefore, $[Cu {({NH}_{3})}_{4}] {Cl}_{2}$ is not an anionic complex, it is a cationic complex.

CHXII09:COORDINATION COMPOUNDS

322135 What is the charge of the complex formed by a platinum(II) metal ion surrounded by two ammonia molecules and two bromide ions?

1 0

2 1

3

- 1

4 2

Explanation:

Charge on the given complex $= (+ 2) + 2 (0) + 2 (- 1) = 0$

CHXII09:COORDINATION COMPOUNDS

322132 The number of moles of ions formed on complete ionisation of 1 mole of $Co {({NH}_{3})}_{3} {Cl}_{3}$ is

1 4

2 3

3 2

4 0

Explanation:

$[Co {({NH}_{3})}_{3} {Cl}_{3}]$ is a neutral complex and will not get ionised.

CHXII09:COORDINATION COMPOUNDS

322133 Which has a complex cation?

1

Ag {({NH}_{3})}_{2} Cl

2

{Na}_{3} {AlF}_{6}

3

{LiAlH}_{4}

4

K_{2} {PtCl}_{6}

Explanation:

${[Ag {({NH}_{3})}_{2}]}^{+}$ is complex cation. Rest all have complex anion i.e.,
${[{AlF}_{6}]}^{3 -}, {[{AlH}_{4}]}^{-}, {[{PtCl}_{6}]}^{2 -}$ .

CHXII09:COORDINATION COMPOUNDS

322134 Which of the following is not an anionic complex?

1

[Cu {({NH}_{3})}_{4}] {Cl}_{2}

2

K_{4} [Fe (CN)_{6}]

3

K_{3} [Fe (CN)_{6}]

4

{[{NiCl}_{4}]}^{2 -}

Explanation:

Positive charge if appears on the coordination sphere, the complex thus obtained is known as cationic complex.
$[Cu {({NH}_{3})}_{4}] {Cl}_{2} ⇌ {[Cu {({NH}_{3})}_{4}]}^{2 +} + 2 {Cl}^{-}$
$K_{4} [Fe (CN)_{6}] ⇌ 4 K^{+} + {[Fe (CN)_{6}]}^{-}$ $K_{3} [Fe (CN)_{6}] ⇌ 3 K^{+} + {[Fe (CN)_{6}]}^{3 -}$
${[{NiCl}_{4}]}^{2 -}$
Therefore, $[Cu {({NH}_{3})}_{4}] {Cl}_{2}$ is not an anionic complex, it is a cationic complex.

CHXII09:COORDINATION COMPOUNDS

322135 What is the charge of the complex formed by a platinum(II) metal ion surrounded by two ammonia molecules and two bromide ions?

1 0

2 1

3

- 1

4 2

Explanation:

Charge on the given complex $= (+ 2) + 2 (0) + 2 (- 1) = 0$