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CHXII09:COORDINATION COMPOUNDS

322076 The correct IUPAC name of ${Mn}_{3} (CO)_{12}$ is :

1 Dodecacarbonylmanganate (0)

2 Dodecacarbonylmanganic (II)

3 Dodecacarbonyltrimanganese(0)

4 Manganic dodecacarbonyl (0)

CHXII09:COORDINATION COMPOUNDS

322077 $K_{3} [Al {(C_{2} O_{4})}_{3}]$ is called

1 potassium alumino oxalato

2 potassium alumino (III) trioxalate

3 potassium trioxalato aluminate (III)

4 potassium trioxalato aluminate (IV)

CHXII09:COORDINATION COMPOUNDS

322078 The correct IUPAC name of $K_{2} {MnO}_{4}$ is

1 Potassium tetraoxidomanganate(VI)

2 Potassium tetraoxidomanganese(VI)

3 Dipotassium tetraoxidomanganate(VII)

4 Potassium tetraoxopermanganate(VI).

Explanation:

As the complex is anionic, metal name will be manganate. The ligand is oxido $(O^{- 2})$ so, the name will be potassium tetraoxido manganate (VI). So, the correct option is (1).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322079 Which among the following will be named as dibromidobis-(ethylenediamine) chromium (III) bromide?

1

[Cr (en)_{3}] {Br}_{2}

2

[Cr (en)_{2} {Br}_{2}] Br

3

{[Cr (en) {Br}_{4}]}^{-}

4

[C r (e n) B r_{2}] B r

Explanation:

Two $Br$ , two (en) and one $Cr$ are parts of complex.
Charge on the complex is
$\begin{matrix} 2(Br) = - 2 \\ 2(en) = 0 \\ 1(cr) = + 3 \end{matrix}} = + 1$
Thus, complex ion is ${[Cr (en)_{2} {Br}_{2}]}^{+}$ .
Since anion is bromide thus, complex is
$[Cr (en)_{2} {Br}_{2}] Br$

CHXII09:COORDINATION COMPOUNDS

322076 The correct IUPAC name of ${Mn}_{3} (CO)_{12}$ is :

1 Dodecacarbonylmanganate (0)

2 Dodecacarbonylmanganic (II)

3 Dodecacarbonyltrimanganese(0)

4 Manganic dodecacarbonyl (0)

CHXII09:COORDINATION COMPOUNDS

322077 $K_{3} [Al {(C_{2} O_{4})}_{3}]$ is called

1 potassium alumino oxalato

2 potassium alumino (III) trioxalate

3 potassium trioxalato aluminate (III)

4 potassium trioxalato aluminate (IV)

CHXII09:COORDINATION COMPOUNDS

322078 The correct IUPAC name of $K_{2} {MnO}_{4}$ is

1 Potassium tetraoxidomanganate(VI)

2 Potassium tetraoxidomanganese(VI)

3 Dipotassium tetraoxidomanganate(VII)

4 Potassium tetraoxopermanganate(VI).

Explanation:

As the complex is anionic, metal name will be manganate. The ligand is oxido $(O^{- 2})$ so, the name will be potassium tetraoxido manganate (VI). So, the correct option is (1).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322079 Which among the following will be named as dibromidobis-(ethylenediamine) chromium (III) bromide?

1

[Cr (en)_{3}] {Br}_{2}

2

[Cr (en)_{2} {Br}_{2}] Br

3

{[Cr (en) {Br}_{4}]}^{-}

4

[C r (e n) B r_{2}] B r

Explanation:

Two $Br$ , two (en) and one $Cr$ are parts of complex.
Charge on the complex is
$\begin{matrix} 2(Br) = - 2 \\ 2(en) = 0 \\ 1(cr) = + 3 \end{matrix}} = + 1$
Thus, complex ion is ${[Cr (en)_{2} {Br}_{2}]}^{+}$ .
Since anion is bromide thus, complex is
$[Cr (en)_{2} {Br}_{2}] Br$

CHXII09:COORDINATION COMPOUNDS

322076 The correct IUPAC name of ${Mn}_{3} (CO)_{12}$ is :

1 Dodecacarbonylmanganate (0)

2 Dodecacarbonylmanganic (II)

3 Dodecacarbonyltrimanganese(0)

4 Manganic dodecacarbonyl (0)

CHXII09:COORDINATION COMPOUNDS

322077 $K_{3} [Al {(C_{2} O_{4})}_{3}]$ is called

1 potassium alumino oxalato

2 potassium alumino (III) trioxalate

3 potassium trioxalato aluminate (III)

4 potassium trioxalato aluminate (IV)

CHXII09:COORDINATION COMPOUNDS

322078 The correct IUPAC name of $K_{2} {MnO}_{4}$ is

1 Potassium tetraoxidomanganate(VI)

2 Potassium tetraoxidomanganese(VI)

3 Dipotassium tetraoxidomanganate(VII)

4 Potassium tetraoxopermanganate(VI).

Explanation:

As the complex is anionic, metal name will be manganate. The ligand is oxido $(O^{- 2})$ so, the name will be potassium tetraoxido manganate (VI). So, the correct option is (1).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322079 Which among the following will be named as dibromidobis-(ethylenediamine) chromium (III) bromide?

1

[Cr (en)_{3}] {Br}_{2}

2

[Cr (en)_{2} {Br}_{2}] Br

3

{[Cr (en) {Br}_{4}]}^{-}

4

[C r (e n) B r_{2}] B r

Explanation:

Two $Br$ , two (en) and one $Cr$ are parts of complex.
Charge on the complex is
$\begin{matrix} 2(Br) = - 2 \\ 2(en) = 0 \\ 1(cr) = + 3 \end{matrix}} = + 1$
Thus, complex ion is ${[Cr (en)_{2} {Br}_{2}]}^{+}$ .
Since anion is bromide thus, complex is
$[Cr (en)_{2} {Br}_{2}] Br$

CHXII09:COORDINATION COMPOUNDS

322076 The correct IUPAC name of ${Mn}_{3} (CO)_{12}$ is :

1 Dodecacarbonylmanganate (0)

2 Dodecacarbonylmanganic (II)

3 Dodecacarbonyltrimanganese(0)

4 Manganic dodecacarbonyl (0)

CHXII09:COORDINATION COMPOUNDS

322077 $K_{3} [Al {(C_{2} O_{4})}_{3}]$ is called

1 potassium alumino oxalato

2 potassium alumino (III) trioxalate

3 potassium trioxalato aluminate (III)

4 potassium trioxalato aluminate (IV)

CHXII09:COORDINATION COMPOUNDS

322078 The correct IUPAC name of $K_{2} {MnO}_{4}$ is

1 Potassium tetraoxidomanganate(VI)

2 Potassium tetraoxidomanganese(VI)

3 Dipotassium tetraoxidomanganate(VII)

4 Potassium tetraoxopermanganate(VI).

Explanation:

As the complex is anionic, metal name will be manganate. The ligand is oxido $(O^{- 2})$ so, the name will be potassium tetraoxido manganate (VI). So, the correct option is (1).

JEE Main - 2024

CHXII09:COORDINATION COMPOUNDS

322079 Which among the following will be named as dibromidobis-(ethylenediamine) chromium (III) bromide?

1

[Cr (en)_{3}] {Br}_{2}

2

[Cr (en)_{2} {Br}_{2}] Br

3

{[Cr (en) {Br}_{4}]}^{-}

4

[C r (e n) B r_{2}] B r

Explanation:

Two $Br$ , two (en) and one $Cr$ are parts of complex.
Charge on the complex is
$\begin{matrix} 2(Br) = - 2 \\ 2(en) = 0 \\ 1(cr) = + 3 \end{matrix}} = + 1$
Thus, complex ion is ${[Cr (en)_{2} {Br}_{2}]}^{+}$ .
Since anion is bromide thus, complex is
$[Cr (en)_{2} {Br}_{2}] Br$

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