Crystal field splitting depends upon the nature of ligand. The nature of ligand \(\Delta\) decreases as shown below \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-} < \mathrm{H}_{2} \mathrm{O} < \mathrm{NH}_{3} < \mathrm{CN}^{-}\) Hence the crystal field splitting will be maximum for \(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\).
JEE - 2013
CHXII09:COORDINATION COMPOUNDS
321865
The crystal field stabilisation energy (in \(\mathrm{cm}^{-1}\) ) of a \(\mathrm{d}^{6}\) complex having \(\Delta_{0}=25000 \mathrm{~cm}^{-1}\) and \({\rm{P}} = 15000\;{\rm{c}}{{\rm{m}}^{ - 1}}\) is ____.
1 40000
2 \( - 15000\)
3 \( - 10000\)
4 \( - 40000\)
Explanation:
For \({{\text{d}}^6}\) complex, when \(\Delta_{0}=25000 \mathrm{~cm}^{-1}\) and \({\text{P}} = 15000\;{\text{c}}{{\text{m}}^{ - 1}},\) i.e., \({\Delta _0} > {\text{P}}\), pairing occurs
Higher the strength of ligand, higher will be the splitting energy. \(\mathrm{I}^{-} < \mathrm{Br}^{-} < \mathrm{Cl}^{-} < \mathrm{F}^{-} < \mathrm{OH}^{-} < \mathrm{C}_{2} \mathrm{O}_{4}^{2-} < \mathrm{H}_{2} \mathrm{O}\) \( < \mathrm{EDTA}^{4} < \mathrm{NH}_{3} < \mathrm{en} < \mathrm{CN}^{-} < \mathrm{CO}\) \(\mathrm{CN}^{-}\) being strongest ligand among given options will lead to largest splitting of d - orbitals for \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}\).
Crystal field splitting depends upon the nature of ligand. The nature of ligand \(\Delta\) decreases as shown below \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-} < \mathrm{H}_{2} \mathrm{O} < \mathrm{NH}_{3} < \mathrm{CN}^{-}\) Hence the crystal field splitting will be maximum for \(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\).
JEE - 2013
CHXII09:COORDINATION COMPOUNDS
321865
The crystal field stabilisation energy (in \(\mathrm{cm}^{-1}\) ) of a \(\mathrm{d}^{6}\) complex having \(\Delta_{0}=25000 \mathrm{~cm}^{-1}\) and \({\rm{P}} = 15000\;{\rm{c}}{{\rm{m}}^{ - 1}}\) is ____.
1 40000
2 \( - 15000\)
3 \( - 10000\)
4 \( - 40000\)
Explanation:
For \({{\text{d}}^6}\) complex, when \(\Delta_{0}=25000 \mathrm{~cm}^{-1}\) and \({\text{P}} = 15000\;{\text{c}}{{\text{m}}^{ - 1}},\) i.e., \({\Delta _0} > {\text{P}}\), pairing occurs
Higher the strength of ligand, higher will be the splitting energy. \(\mathrm{I}^{-} < \mathrm{Br}^{-} < \mathrm{Cl}^{-} < \mathrm{F}^{-} < \mathrm{OH}^{-} < \mathrm{C}_{2} \mathrm{O}_{4}^{2-} < \mathrm{H}_{2} \mathrm{O}\) \( < \mathrm{EDTA}^{4} < \mathrm{NH}_{3} < \mathrm{en} < \mathrm{CN}^{-} < \mathrm{CO}\) \(\mathrm{CN}^{-}\) being strongest ligand among given options will lead to largest splitting of d - orbitals for \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}\).
Crystal field splitting depends upon the nature of ligand. The nature of ligand \(\Delta\) decreases as shown below \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-} < \mathrm{H}_{2} \mathrm{O} < \mathrm{NH}_{3} < \mathrm{CN}^{-}\) Hence the crystal field splitting will be maximum for \(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\).
JEE - 2013
CHXII09:COORDINATION COMPOUNDS
321865
The crystal field stabilisation energy (in \(\mathrm{cm}^{-1}\) ) of a \(\mathrm{d}^{6}\) complex having \(\Delta_{0}=25000 \mathrm{~cm}^{-1}\) and \({\rm{P}} = 15000\;{\rm{c}}{{\rm{m}}^{ - 1}}\) is ____.
1 40000
2 \( - 15000\)
3 \( - 10000\)
4 \( - 40000\)
Explanation:
For \({{\text{d}}^6}\) complex, when \(\Delta_{0}=25000 \mathrm{~cm}^{-1}\) and \({\text{P}} = 15000\;{\text{c}}{{\text{m}}^{ - 1}},\) i.e., \({\Delta _0} > {\text{P}}\), pairing occurs
Higher the strength of ligand, higher will be the splitting energy. \(\mathrm{I}^{-} < \mathrm{Br}^{-} < \mathrm{Cl}^{-} < \mathrm{F}^{-} < \mathrm{OH}^{-} < \mathrm{C}_{2} \mathrm{O}_{4}^{2-} < \mathrm{H}_{2} \mathrm{O}\) \( < \mathrm{EDTA}^{4} < \mathrm{NH}_{3} < \mathrm{en} < \mathrm{CN}^{-} < \mathrm{CO}\) \(\mathrm{CN}^{-}\) being strongest ligand among given options will lead to largest splitting of d - orbitals for \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}\).
Crystal field splitting depends upon the nature of ligand. The nature of ligand \(\Delta\) decreases as shown below \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-} < \mathrm{H}_{2} \mathrm{O} < \mathrm{NH}_{3} < \mathrm{CN}^{-}\) Hence the crystal field splitting will be maximum for \(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\).
JEE - 2013
CHXII09:COORDINATION COMPOUNDS
321865
The crystal field stabilisation energy (in \(\mathrm{cm}^{-1}\) ) of a \(\mathrm{d}^{6}\) complex having \(\Delta_{0}=25000 \mathrm{~cm}^{-1}\) and \({\rm{P}} = 15000\;{\rm{c}}{{\rm{m}}^{ - 1}}\) is ____.
1 40000
2 \( - 15000\)
3 \( - 10000\)
4 \( - 40000\)
Explanation:
For \({{\text{d}}^6}\) complex, when \(\Delta_{0}=25000 \mathrm{~cm}^{-1}\) and \({\text{P}} = 15000\;{\text{c}}{{\text{m}}^{ - 1}},\) i.e., \({\Delta _0} > {\text{P}}\), pairing occurs
Higher the strength of ligand, higher will be the splitting energy. \(\mathrm{I}^{-} < \mathrm{Br}^{-} < \mathrm{Cl}^{-} < \mathrm{F}^{-} < \mathrm{OH}^{-} < \mathrm{C}_{2} \mathrm{O}_{4}^{2-} < \mathrm{H}_{2} \mathrm{O}\) \( < \mathrm{EDTA}^{4} < \mathrm{NH}_{3} < \mathrm{en} < \mathrm{CN}^{-} < \mathrm{CO}\) \(\mathrm{CN}^{-}\) being strongest ligand among given options will lead to largest splitting of d - orbitals for \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}\).
