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CHXII08:THE D- & F-BLOCK ELEMENTS

321751 Given below are two statements :
Statement (A): In Lanthanoids, the formation ${Ce}^{+ 4}$ is favoured by its noble gas configuration.
Statement (B) : It is a strong oxidant reverting to the common +3 state.

1 Statement A is correct but statement B is incorrect.

2 Statement A is incorrect but statement

B

is correct.

3 Both statement A and statement B are correct.

4 Both statement A and statement B are incorrect.

Explanation:

$_{58} Ce = [Xe] 4 f^{1}, 5 d^{1}, 6 s^{2}$
${Ce}^{+ 4} / {Ce}^{+ 3} (E_{RP}^{\circ}) = 1.74 V$ .

JEE - 2024

CHXII08:THE D- & F-BLOCK ELEMENTS

321752 Assertion :
${Yb}^{2 +}$ is more stable in compare to ${Gd}^{+ 2}$ .
Reason :
The electronic configuration of $Gd$ is $[Xe] 4 f^{7} 5 d^{2} 6 s^{2}$ .

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason is incorrect.

Explanation:

The electronic configuration of
$\begin{aligned} {Yb}^{+ 2} & = [Xe], 4 f^{14}, 5 d^{0}, 6 s^{0} \\ {Gd}^{+ 2} & = [Xe], 4 f^{7}, 5 d^{1} 6 s^{0} \end{aligned}$
Since, ${Yb}^{2 +}$ has full - filled $(f^{14})$ configuration. It is more stable than that of ${Gd}^{2 +}$ .
'Gd' electronic configuration is $(Xe) 4 f^{7} 5 d^{1} 6 s^{2}$

AIIMS - 2019

CHXII08:THE D- & F-BLOCK ELEMENTS

321753 The most common oxidation states of cerium are

1 +2 and +4

2 +3 and +4

3 +3 and +5

4 +2 and +3

CHXII08:THE D- & F-BLOCK ELEMENTS

321754 In which of the following lanthanoids oxidation state +2 is most stable?

1

Ce

2

Eu

3

Tb

4 Dy

Explanation:

$E u^{2 +}$ has electronic configuration $[X e] 4 f^{7}$ hence stable due to half filled atomic orbitals.

CHXII08:THE D- & F-BLOCK ELEMENTS

321751 Given below are two statements :
Statement (A): In Lanthanoids, the formation ${Ce}^{+ 4}$ is favoured by its noble gas configuration.
Statement (B) : It is a strong oxidant reverting to the common +3 state.

1 Statement A is correct but statement B is incorrect.

2 Statement A is incorrect but statement

B

is correct.

3 Both statement A and statement B are correct.

4 Both statement A and statement B are incorrect.

Explanation:

$_{58} Ce = [Xe] 4 f^{1}, 5 d^{1}, 6 s^{2}$
${Ce}^{+ 4} / {Ce}^{+ 3} (E_{RP}^{\circ}) = 1.74 V$ .

JEE - 2024

CHXII08:THE D- & F-BLOCK ELEMENTS

321752 Assertion :
${Yb}^{2 +}$ is more stable in compare to ${Gd}^{+ 2}$ .
Reason :
The electronic configuration of $Gd$ is $[Xe] 4 f^{7} 5 d^{2} 6 s^{2}$ .

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason is incorrect.

Explanation:

The electronic configuration of
$\begin{aligned} {Yb}^{+ 2} & = [Xe], 4 f^{14}, 5 d^{0}, 6 s^{0} \\ {Gd}^{+ 2} & = [Xe], 4 f^{7}, 5 d^{1} 6 s^{0} \end{aligned}$
Since, ${Yb}^{2 +}$ has full - filled $(f^{14})$ configuration. It is more stable than that of ${Gd}^{2 +}$ .
'Gd' electronic configuration is $(Xe) 4 f^{7} 5 d^{1} 6 s^{2}$

AIIMS - 2019

CHXII08:THE D- & F-BLOCK ELEMENTS

321753 The most common oxidation states of cerium are

1 +2 and +4

2 +3 and +4

3 +3 and +5

4 +2 and +3

CHXII08:THE D- & F-BLOCK ELEMENTS

321754 In which of the following lanthanoids oxidation state +2 is most stable?

1

Ce

2

Eu

3

Tb

4 Dy

Explanation:

$E u^{2 +}$ has electronic configuration $[X e] 4 f^{7}$ hence stable due to half filled atomic orbitals.

CHXII08:THE D- & F-BLOCK ELEMENTS

321751 Given below are two statements :
Statement (A): In Lanthanoids, the formation ${Ce}^{+ 4}$ is favoured by its noble gas configuration.
Statement (B) : It is a strong oxidant reverting to the common +3 state.

1 Statement A is correct but statement B is incorrect.

2 Statement A is incorrect but statement

B

is correct.

3 Both statement A and statement B are correct.

4 Both statement A and statement B are incorrect.

Explanation:

$_{58} Ce = [Xe] 4 f^{1}, 5 d^{1}, 6 s^{2}$
${Ce}^{+ 4} / {Ce}^{+ 3} (E_{RP}^{\circ}) = 1.74 V$ .

JEE - 2024

CHXII08:THE D- & F-BLOCK ELEMENTS

321752 Assertion :
${Yb}^{2 +}$ is more stable in compare to ${Gd}^{+ 2}$ .
Reason :
The electronic configuration of $Gd$ is $[Xe] 4 f^{7} 5 d^{2} 6 s^{2}$ .

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason is incorrect.

Explanation:

The electronic configuration of
$\begin{aligned} {Yb}^{+ 2} & = [Xe], 4 f^{14}, 5 d^{0}, 6 s^{0} \\ {Gd}^{+ 2} & = [Xe], 4 f^{7}, 5 d^{1} 6 s^{0} \end{aligned}$
Since, ${Yb}^{2 +}$ has full - filled $(f^{14})$ configuration. It is more stable than that of ${Gd}^{2 +}$ .
'Gd' electronic configuration is $(Xe) 4 f^{7} 5 d^{1} 6 s^{2}$

AIIMS - 2019

CHXII08:THE D- & F-BLOCK ELEMENTS

321753 The most common oxidation states of cerium are

1 +2 and +4

2 +3 and +4

3 +3 and +5

4 +2 and +3

CHXII08:THE D- & F-BLOCK ELEMENTS

321754 In which of the following lanthanoids oxidation state +2 is most stable?

1

Ce

2

Eu

3

Tb

4 Dy

Explanation:

$E u^{2 +}$ has electronic configuration $[X e] 4 f^{7}$ hence stable due to half filled atomic orbitals.

CHXII08:THE D- & F-BLOCK ELEMENTS

321751 Given below are two statements :
Statement (A): In Lanthanoids, the formation ${Ce}^{+ 4}$ is favoured by its noble gas configuration.
Statement (B) : It is a strong oxidant reverting to the common +3 state.

1 Statement A is correct but statement B is incorrect.

2 Statement A is incorrect but statement

B

is correct.

3 Both statement A and statement B are correct.

4 Both statement A and statement B are incorrect.

Explanation:

$_{58} Ce = [Xe] 4 f^{1}, 5 d^{1}, 6 s^{2}$
${Ce}^{+ 4} / {Ce}^{+ 3} (E_{RP}^{\circ}) = 1.74 V$ .

JEE - 2024

CHXII08:THE D- & F-BLOCK ELEMENTS

321752 Assertion :
${Yb}^{2 +}$ is more stable in compare to ${Gd}^{+ 2}$ .
Reason :
The electronic configuration of $Gd$ is $[Xe] 4 f^{7} 5 d^{2} 6 s^{2}$ .

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason is incorrect.

Explanation:

The electronic configuration of
$\begin{aligned} {Yb}^{+ 2} & = [Xe], 4 f^{14}, 5 d^{0}, 6 s^{0} \\ {Gd}^{+ 2} & = [Xe], 4 f^{7}, 5 d^{1} 6 s^{0} \end{aligned}$
Since, ${Yb}^{2 +}$ has full - filled $(f^{14})$ configuration. It is more stable than that of ${Gd}^{2 +}$ .
'Gd' electronic configuration is $(Xe) 4 f^{7} 5 d^{1} 6 s^{2}$

AIIMS - 2019

CHXII08:THE D- & F-BLOCK ELEMENTS

321753 The most common oxidation states of cerium are

1 +2 and +4

2 +3 and +4

3 +3 and +5

4 +2 and +3

CHXII08:THE D- & F-BLOCK ELEMENTS

321754 In which of the following lanthanoids oxidation state +2 is most stable?

1

Ce

2

Eu

3

Tb

4 Dy

Explanation:

$E u^{2 +}$ has electronic configuration $[X e] 4 f^{7}$ hence stable due to half filled atomic orbitals.