Blue vitriol is \({\rm{CuS}}{{\rm{O}}_{\rm{4}}}{\rm{.5}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321433
Identify the metal that forms colourless compounds.
1 Iron \(\mathrm{(Z=26)}\)
2 \({\rm{Chromium}}\,\,{\rm{(Z = 24)}}\)
3 Vanadium \(\mathrm{(Z=23)}\)
4 Scandium \(\mathrm{(Z=21)}\)
Explanation:
d-block elements show +3 as the most common oxidation state. For scandium \(\mathrm{(Z=21)}\), electronic configuration is \(\mathrm{\mathrm{d}^{1}, \mathrm{~s}^{2}}\). After the removal of +3 electrons \(\mathrm{\left(\mathrm{Sc}^{3+}\right)}\), it acquires a stable configuration \(\mathrm{\left(\mathrm{d}^{0}\right)}\). Hence, it forms colourless compounds.
MHTCET - 2016
CHXII08:THE D- & F-BLOCK ELEMENTS
321434
The property which is not a characteristic of transition metal is
1 Variable oxidation state
2 Tendency to form complex
3 Formation of coloured compound
4 Natural radioactivity
Explanation:
Natural radioactivity is not a characteristic of transition elements
CHXII08:THE D- & F-BLOCK ELEMENTS
321435
Assertion : Hydrated \(\mathrm{CuSO}_{4}\) turns white on heating. Reason : Hydrated \(\mathrm{CuSO}_{4}\) is also known as blue vitriol.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Hydrated copper sulphate \(\left(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\right)\) is blue which on heating loses water of crystallization to form anhydrous \(\mathrm{CuSO}_{4}\), a white compound. \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { heat }} \underset{\text { (White) }}{\mathrm{CuSO}_{4}}+5 \mathrm{H}_{2} \mathrm{O}\) \(\mathrm{CuSO}_{4} .5 \mathrm{H}_{2} \mathrm{O}\) is commonly called blue vitriol. It is blue in colour due to the presence of 5 molecules of water of crystallization. So option (2) is correct.
Blue vitriol is \({\rm{CuS}}{{\rm{O}}_{\rm{4}}}{\rm{.5}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321433
Identify the metal that forms colourless compounds.
1 Iron \(\mathrm{(Z=26)}\)
2 \({\rm{Chromium}}\,\,{\rm{(Z = 24)}}\)
3 Vanadium \(\mathrm{(Z=23)}\)
4 Scandium \(\mathrm{(Z=21)}\)
Explanation:
d-block elements show +3 as the most common oxidation state. For scandium \(\mathrm{(Z=21)}\), electronic configuration is \(\mathrm{\mathrm{d}^{1}, \mathrm{~s}^{2}}\). After the removal of +3 electrons \(\mathrm{\left(\mathrm{Sc}^{3+}\right)}\), it acquires a stable configuration \(\mathrm{\left(\mathrm{d}^{0}\right)}\). Hence, it forms colourless compounds.
MHTCET - 2016
CHXII08:THE D- & F-BLOCK ELEMENTS
321434
The property which is not a characteristic of transition metal is
1 Variable oxidation state
2 Tendency to form complex
3 Formation of coloured compound
4 Natural radioactivity
Explanation:
Natural radioactivity is not a characteristic of transition elements
CHXII08:THE D- & F-BLOCK ELEMENTS
321435
Assertion : Hydrated \(\mathrm{CuSO}_{4}\) turns white on heating. Reason : Hydrated \(\mathrm{CuSO}_{4}\) is also known as blue vitriol.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Hydrated copper sulphate \(\left(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\right)\) is blue which on heating loses water of crystallization to form anhydrous \(\mathrm{CuSO}_{4}\), a white compound. \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { heat }} \underset{\text { (White) }}{\mathrm{CuSO}_{4}}+5 \mathrm{H}_{2} \mathrm{O}\) \(\mathrm{CuSO}_{4} .5 \mathrm{H}_{2} \mathrm{O}\) is commonly called blue vitriol. It is blue in colour due to the presence of 5 molecules of water of crystallization. So option (2) is correct.
Blue vitriol is \({\rm{CuS}}{{\rm{O}}_{\rm{4}}}{\rm{.5}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321433
Identify the metal that forms colourless compounds.
1 Iron \(\mathrm{(Z=26)}\)
2 \({\rm{Chromium}}\,\,{\rm{(Z = 24)}}\)
3 Vanadium \(\mathrm{(Z=23)}\)
4 Scandium \(\mathrm{(Z=21)}\)
Explanation:
d-block elements show +3 as the most common oxidation state. For scandium \(\mathrm{(Z=21)}\), electronic configuration is \(\mathrm{\mathrm{d}^{1}, \mathrm{~s}^{2}}\). After the removal of +3 electrons \(\mathrm{\left(\mathrm{Sc}^{3+}\right)}\), it acquires a stable configuration \(\mathrm{\left(\mathrm{d}^{0}\right)}\). Hence, it forms colourless compounds.
MHTCET - 2016
CHXII08:THE D- & F-BLOCK ELEMENTS
321434
The property which is not a characteristic of transition metal is
1 Variable oxidation state
2 Tendency to form complex
3 Formation of coloured compound
4 Natural radioactivity
Explanation:
Natural radioactivity is not a characteristic of transition elements
CHXII08:THE D- & F-BLOCK ELEMENTS
321435
Assertion : Hydrated \(\mathrm{CuSO}_{4}\) turns white on heating. Reason : Hydrated \(\mathrm{CuSO}_{4}\) is also known as blue vitriol.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Hydrated copper sulphate \(\left(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\right)\) is blue which on heating loses water of crystallization to form anhydrous \(\mathrm{CuSO}_{4}\), a white compound. \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { heat }} \underset{\text { (White) }}{\mathrm{CuSO}_{4}}+5 \mathrm{H}_{2} \mathrm{O}\) \(\mathrm{CuSO}_{4} .5 \mathrm{H}_{2} \mathrm{O}\) is commonly called blue vitriol. It is blue in colour due to the presence of 5 molecules of water of crystallization. So option (2) is correct.
Blue vitriol is \({\rm{CuS}}{{\rm{O}}_{\rm{4}}}{\rm{.5}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321433
Identify the metal that forms colourless compounds.
1 Iron \(\mathrm{(Z=26)}\)
2 \({\rm{Chromium}}\,\,{\rm{(Z = 24)}}\)
3 Vanadium \(\mathrm{(Z=23)}\)
4 Scandium \(\mathrm{(Z=21)}\)
Explanation:
d-block elements show +3 as the most common oxidation state. For scandium \(\mathrm{(Z=21)}\), electronic configuration is \(\mathrm{\mathrm{d}^{1}, \mathrm{~s}^{2}}\). After the removal of +3 electrons \(\mathrm{\left(\mathrm{Sc}^{3+}\right)}\), it acquires a stable configuration \(\mathrm{\left(\mathrm{d}^{0}\right)}\). Hence, it forms colourless compounds.
MHTCET - 2016
CHXII08:THE D- & F-BLOCK ELEMENTS
321434
The property which is not a characteristic of transition metal is
1 Variable oxidation state
2 Tendency to form complex
3 Formation of coloured compound
4 Natural radioactivity
Explanation:
Natural radioactivity is not a characteristic of transition elements
CHXII08:THE D- & F-BLOCK ELEMENTS
321435
Assertion : Hydrated \(\mathrm{CuSO}_{4}\) turns white on heating. Reason : Hydrated \(\mathrm{CuSO}_{4}\) is also known as blue vitriol.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Hydrated copper sulphate \(\left(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\right)\) is blue which on heating loses water of crystallization to form anhydrous \(\mathrm{CuSO}_{4}\), a white compound. \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { heat }} \underset{\text { (White) }}{\mathrm{CuSO}_{4}}+5 \mathrm{H}_{2} \mathrm{O}\) \(\mathrm{CuSO}_{4} .5 \mathrm{H}_{2} \mathrm{O}\) is commonly called blue vitriol. It is blue in colour due to the presence of 5 molecules of water of crystallization. So option (2) is correct.
Blue vitriol is \({\rm{CuS}}{{\rm{O}}_{\rm{4}}}{\rm{.5}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321433
Identify the metal that forms colourless compounds.
1 Iron \(\mathrm{(Z=26)}\)
2 \({\rm{Chromium}}\,\,{\rm{(Z = 24)}}\)
3 Vanadium \(\mathrm{(Z=23)}\)
4 Scandium \(\mathrm{(Z=21)}\)
Explanation:
d-block elements show +3 as the most common oxidation state. For scandium \(\mathrm{(Z=21)}\), electronic configuration is \(\mathrm{\mathrm{d}^{1}, \mathrm{~s}^{2}}\). After the removal of +3 electrons \(\mathrm{\left(\mathrm{Sc}^{3+}\right)}\), it acquires a stable configuration \(\mathrm{\left(\mathrm{d}^{0}\right)}\). Hence, it forms colourless compounds.
MHTCET - 2016
CHXII08:THE D- & F-BLOCK ELEMENTS
321434
The property which is not a characteristic of transition metal is
1 Variable oxidation state
2 Tendency to form complex
3 Formation of coloured compound
4 Natural radioactivity
Explanation:
Natural radioactivity is not a characteristic of transition elements
CHXII08:THE D- & F-BLOCK ELEMENTS
321435
Assertion : Hydrated \(\mathrm{CuSO}_{4}\) turns white on heating. Reason : Hydrated \(\mathrm{CuSO}_{4}\) is also known as blue vitriol.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Hydrated copper sulphate \(\left(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\right)\) is blue which on heating loses water of crystallization to form anhydrous \(\mathrm{CuSO}_{4}\), a white compound. \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { heat }} \underset{\text { (White) }}{\mathrm{CuSO}_{4}}+5 \mathrm{H}_{2} \mathrm{O}\) \(\mathrm{CuSO}_{4} .5 \mathrm{H}_{2} \mathrm{O}\) is commonly called blue vitriol. It is blue in colour due to the presence of 5 molecules of water of crystallization. So option (2) is correct.
