321348 The number of electrons gained by \(\mathrm{\mathrm{KMnO}_{4}}\) in acidic medium when it reacts with 1 mol of \(\mathrm{\mathrm{H}_{2} \mathrm{O}_{2}}\) is equal to that of:

321349 \(\mathrm{KMnO}_{4}\) oxidises thiosulphate to \(\mathrm{SO}_{4}^{2-}\) as per reaction
\({\rm{xMnO}}_4^ - + 3\;{{\rm{S}}_{\rm{2}}}{\rm{O}}_3^{2 - } + {{\rm{H}}_{\rm{2}}}{\rm{O}} \to \)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{xMn}}{{\text{O}}_2} + 6{\text{SO}}_4^{2 - } + 2{\text{O}}{{\text{H}}^ - }\)
Find the value of \({\rm{x}}\) in above reaction.

321350 Read Assertion and Reason carefully to mark the correct option given below.
Assertion :
Equivalent mass of \(\mathrm{KMnO}_{4}\) is equal to one third of its molecular mass when it acts as an oxidising agent in faintly alkaline medium.
Reason :
Oxidation number of manganese in \(\mathrm{KMnO}_{4}\) is +7

321351 In permanganate ion \(\mathrm{\mathrm{MnO}_{4}^{-}}\), manganese has an oxidation number of +7 . Therefore it is

321348 The number of electrons gained by \(\mathrm{\mathrm{KMnO}_{4}}\) in acidic medium when it reacts with 1 mol of \(\mathrm{\mathrm{H}_{2} \mathrm{O}_{2}}\) is equal to that of:

321349 \(\mathrm{KMnO}_{4}\) oxidises thiosulphate to \(\mathrm{SO}_{4}^{2-}\) as per reaction
\({\rm{xMnO}}_4^ - + 3\;{{\rm{S}}_{\rm{2}}}{\rm{O}}_3^{2 - } + {{\rm{H}}_{\rm{2}}}{\rm{O}} \to \)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{xMn}}{{\text{O}}_2} + 6{\text{SO}}_4^{2 - } + 2{\text{O}}{{\text{H}}^ - }\)
Find the value of \({\rm{x}}\) in above reaction.

321350 Read Assertion and Reason carefully to mark the correct option given below.
Assertion :
Equivalent mass of \(\mathrm{KMnO}_{4}\) is equal to one third of its molecular mass when it acts as an oxidising agent in faintly alkaline medium.
Reason :
Oxidation number of manganese in \(\mathrm{KMnO}_{4}\) is +7

321351 In permanganate ion \(\mathrm{\mathrm{MnO}_{4}^{-}}\), manganese has an oxidation number of +7 . Therefore it is

321348 The number of electrons gained by \(\mathrm{\mathrm{KMnO}_{4}}\) in acidic medium when it reacts with 1 mol of \(\mathrm{\mathrm{H}_{2} \mathrm{O}_{2}}\) is equal to that of:

321349 \(\mathrm{KMnO}_{4}\) oxidises thiosulphate to \(\mathrm{SO}_{4}^{2-}\) as per reaction
\({\rm{xMnO}}_4^ - + 3\;{{\rm{S}}_{\rm{2}}}{\rm{O}}_3^{2 - } + {{\rm{H}}_{\rm{2}}}{\rm{O}} \to \)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{xMn}}{{\text{O}}_2} + 6{\text{SO}}_4^{2 - } + 2{\text{O}}{{\text{H}}^ - }\)
Find the value of \({\rm{x}}\) in above reaction.

321350 Read Assertion and Reason carefully to mark the correct option given below.
Assertion :
Equivalent mass of \(\mathrm{KMnO}_{4}\) is equal to one third of its molecular mass when it acts as an oxidising agent in faintly alkaline medium.
Reason :
Oxidation number of manganese in \(\mathrm{KMnO}_{4}\) is +7

321351 In permanganate ion \(\mathrm{\mathrm{MnO}_{4}^{-}}\), manganese has an oxidation number of +7 . Therefore it is

321348 The number of electrons gained by \(\mathrm{\mathrm{KMnO}_{4}}\) in acidic medium when it reacts with 1 mol of \(\mathrm{\mathrm{H}_{2} \mathrm{O}_{2}}\) is equal to that of:

321349 \(\mathrm{KMnO}_{4}\) oxidises thiosulphate to \(\mathrm{SO}_{4}^{2-}\) as per reaction
\({\rm{xMnO}}_4^ - + 3\;{{\rm{S}}_{\rm{2}}}{\rm{O}}_3^{2 - } + {{\rm{H}}_{\rm{2}}}{\rm{O}} \to \)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{xMn}}{{\text{O}}_2} + 6{\text{SO}}_4^{2 - } + 2{\text{O}}{{\text{H}}^ - }\)
Find the value of \({\rm{x}}\) in above reaction.

321350 Read Assertion and Reason carefully to mark the correct option given below.
Assertion :
Equivalent mass of \(\mathrm{KMnO}_{4}\) is equal to one third of its molecular mass when it acts as an oxidising agent in faintly alkaline medium.
Reason :
Oxidation number of manganese in \(\mathrm{KMnO}_{4}\) is +7

321351 In permanganate ion \(\mathrm{\mathrm{MnO}_{4}^{-}}\), manganese has an oxidation number of +7 . Therefore it is