CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321191
Although thermodynamically feasible, in practice, magnesium metal is not used for the reduction of alumina in the metallurgy of aluminium. Why?
1 \(\mathrm{\mathrm{Mg}}\) can reduce Alumina below point \(\mathrm{\mathrm{A}}\) at temperature lower than at \(\mathrm{\mathrm{A}}\)
2 The process is uneconomical
3 Though thermodynamically feasible practically not possible
4 Both (1) and (2)
Explanation:
Temperature below the point of intersection of \(\mathrm{\mathrm{Al}_{2} \mathrm{O}_{3}}\) and \(\mathrm{\mathrm{MgO}}\) curves, magnesium can reduce alumina. But the process will be uneconomical.
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321192
Ellingham diagram represents:
1 Change of \(\mathrm{\Delta G}\) with temperature.
2 Change of \(\mathrm{\Delta H}\) with temperature.
3 Change of \(\mathrm{\Delta G}\) with pressure.
4 Change of \(\mathrm{(\Delta G-T \Delta S)}\) with temperature.
Explanation:
Conceptual Questions
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321193
Which of the following best explains why the free energy of formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) becomes less negative as the temperature increases?
1 The free energy of formation is independent of the absolute temperature.
2 As entropy increases, the free energy of formation increases.
3 Entropy drops as a result of the consumption of oxygen.
4 At low temperature, the free energy of formation becomes less dependent on the enthalpy of formation.
Explanation:
As formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) from \(\mathrm{\mathrm{Fe}}\) and \(\mathrm{\mathrm{O}_{2}}\) occurs with a -ve \(\mathrm{\Delta S}\) value so according to the Gibbs-Helmholtz equation: \(\mathrm{\Delta G=\Delta H-T \Delta S}\)
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321194
In Ellingham diagrams of \(\mathrm{\Delta_{f} G}\) oxide formation Vs T, which of the following graphs has negative slope?
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321191
Although thermodynamically feasible, in practice, magnesium metal is not used for the reduction of alumina in the metallurgy of aluminium. Why?
1 \(\mathrm{\mathrm{Mg}}\) can reduce Alumina below point \(\mathrm{\mathrm{A}}\) at temperature lower than at \(\mathrm{\mathrm{A}}\)
2 The process is uneconomical
3 Though thermodynamically feasible practically not possible
4 Both (1) and (2)
Explanation:
Temperature below the point of intersection of \(\mathrm{\mathrm{Al}_{2} \mathrm{O}_{3}}\) and \(\mathrm{\mathrm{MgO}}\) curves, magnesium can reduce alumina. But the process will be uneconomical.
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321192
Ellingham diagram represents:
1 Change of \(\mathrm{\Delta G}\) with temperature.
2 Change of \(\mathrm{\Delta H}\) with temperature.
3 Change of \(\mathrm{\Delta G}\) with pressure.
4 Change of \(\mathrm{(\Delta G-T \Delta S)}\) with temperature.
Explanation:
Conceptual Questions
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321193
Which of the following best explains why the free energy of formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) becomes less negative as the temperature increases?
1 The free energy of formation is independent of the absolute temperature.
2 As entropy increases, the free energy of formation increases.
3 Entropy drops as a result of the consumption of oxygen.
4 At low temperature, the free energy of formation becomes less dependent on the enthalpy of formation.
Explanation:
As formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) from \(\mathrm{\mathrm{Fe}}\) and \(\mathrm{\mathrm{O}_{2}}\) occurs with a -ve \(\mathrm{\Delta S}\) value so according to the Gibbs-Helmholtz equation: \(\mathrm{\Delta G=\Delta H-T \Delta S}\)
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321194
In Ellingham diagrams of \(\mathrm{\Delta_{f} G}\) oxide formation Vs T, which of the following graphs has negative slope?
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321191
Although thermodynamically feasible, in practice, magnesium metal is not used for the reduction of alumina in the metallurgy of aluminium. Why?
1 \(\mathrm{\mathrm{Mg}}\) can reduce Alumina below point \(\mathrm{\mathrm{A}}\) at temperature lower than at \(\mathrm{\mathrm{A}}\)
2 The process is uneconomical
3 Though thermodynamically feasible practically not possible
4 Both (1) and (2)
Explanation:
Temperature below the point of intersection of \(\mathrm{\mathrm{Al}_{2} \mathrm{O}_{3}}\) and \(\mathrm{\mathrm{MgO}}\) curves, magnesium can reduce alumina. But the process will be uneconomical.
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321192
Ellingham diagram represents:
1 Change of \(\mathrm{\Delta G}\) with temperature.
2 Change of \(\mathrm{\Delta H}\) with temperature.
3 Change of \(\mathrm{\Delta G}\) with pressure.
4 Change of \(\mathrm{(\Delta G-T \Delta S)}\) with temperature.
Explanation:
Conceptual Questions
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321193
Which of the following best explains why the free energy of formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) becomes less negative as the temperature increases?
1 The free energy of formation is independent of the absolute temperature.
2 As entropy increases, the free energy of formation increases.
3 Entropy drops as a result of the consumption of oxygen.
4 At low temperature, the free energy of formation becomes less dependent on the enthalpy of formation.
Explanation:
As formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) from \(\mathrm{\mathrm{Fe}}\) and \(\mathrm{\mathrm{O}_{2}}\) occurs with a -ve \(\mathrm{\Delta S}\) value so according to the Gibbs-Helmholtz equation: \(\mathrm{\Delta G=\Delta H-T \Delta S}\)
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321194
In Ellingham diagrams of \(\mathrm{\Delta_{f} G}\) oxide formation Vs T, which of the following graphs has negative slope?
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CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321191
Although thermodynamically feasible, in practice, magnesium metal is not used for the reduction of alumina in the metallurgy of aluminium. Why?
1 \(\mathrm{\mathrm{Mg}}\) can reduce Alumina below point \(\mathrm{\mathrm{A}}\) at temperature lower than at \(\mathrm{\mathrm{A}}\)
2 The process is uneconomical
3 Though thermodynamically feasible practically not possible
4 Both (1) and (2)
Explanation:
Temperature below the point of intersection of \(\mathrm{\mathrm{Al}_{2} \mathrm{O}_{3}}\) and \(\mathrm{\mathrm{MgO}}\) curves, magnesium can reduce alumina. But the process will be uneconomical.
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321192
Ellingham diagram represents:
1 Change of \(\mathrm{\Delta G}\) with temperature.
2 Change of \(\mathrm{\Delta H}\) with temperature.
3 Change of \(\mathrm{\Delta G}\) with pressure.
4 Change of \(\mathrm{(\Delta G-T \Delta S)}\) with temperature.
Explanation:
Conceptual Questions
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321193
Which of the following best explains why the free energy of formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) becomes less negative as the temperature increases?
1 The free energy of formation is independent of the absolute temperature.
2 As entropy increases, the free energy of formation increases.
3 Entropy drops as a result of the consumption of oxygen.
4 At low temperature, the free energy of formation becomes less dependent on the enthalpy of formation.
Explanation:
As formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) from \(\mathrm{\mathrm{Fe}}\) and \(\mathrm{\mathrm{O}_{2}}\) occurs with a -ve \(\mathrm{\Delta S}\) value so according to the Gibbs-Helmholtz equation: \(\mathrm{\Delta G=\Delta H-T \Delta S}\)
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321194
In Ellingham diagrams of \(\mathrm{\Delta_{f} G}\) oxide formation Vs T, which of the following graphs has negative slope?
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321191
Although thermodynamically feasible, in practice, magnesium metal is not used for the reduction of alumina in the metallurgy of aluminium. Why?
1 \(\mathrm{\mathrm{Mg}}\) can reduce Alumina below point \(\mathrm{\mathrm{A}}\) at temperature lower than at \(\mathrm{\mathrm{A}}\)
2 The process is uneconomical
3 Though thermodynamically feasible practically not possible
4 Both (1) and (2)
Explanation:
Temperature below the point of intersection of \(\mathrm{\mathrm{Al}_{2} \mathrm{O}_{3}}\) and \(\mathrm{\mathrm{MgO}}\) curves, magnesium can reduce alumina. But the process will be uneconomical.
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321192
Ellingham diagram represents:
1 Change of \(\mathrm{\Delta G}\) with temperature.
2 Change of \(\mathrm{\Delta H}\) with temperature.
3 Change of \(\mathrm{\Delta G}\) with pressure.
4 Change of \(\mathrm{(\Delta G-T \Delta S)}\) with temperature.
Explanation:
Conceptual Questions
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321193
Which of the following best explains why the free energy of formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) becomes less negative as the temperature increases?
1 The free energy of formation is independent of the absolute temperature.
2 As entropy increases, the free energy of formation increases.
3 Entropy drops as a result of the consumption of oxygen.
4 At low temperature, the free energy of formation becomes less dependent on the enthalpy of formation.
Explanation:
As formation of \(\mathrm{\mathrm{Fe}_{2} \mathrm{O}_{3}}\) from \(\mathrm{\mathrm{Fe}}\) and \(\mathrm{\mathrm{O}_{2}}\) occurs with a -ve \(\mathrm{\Delta S}\) value so according to the Gibbs-Helmholtz equation: \(\mathrm{\Delta G=\Delta H-T \Delta S}\)
CHXII06:GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS
321194
In Ellingham diagrams of \(\mathrm{\Delta_{f} G}\) oxide formation Vs T, which of the following graphs has negative slope?