320900
The gold number of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are 0.04 , \(0.002,10\) and 25 respectively. Protective power of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are in order
1 A \(>\) B \(>\) C \(>\) D
2 B \(>\) A \(>\) C \(>\) D
3 D \(>\) C \(>\) B \(>\) A
4 C \(>\) A \(>\) B \(>\) D
Explanation:
\({\rm{Protective}}\,\,{\rm{power}}\,\,{\rm{\alpha }}\,\frac{{\rm{1}}}{{{\rm{ Gold}}\,{\rm{ number }}}}{\rm{.}}\) Hence, the correct order of protective power is \(\mathrm{B}>\mathrm{A}>\mathrm{C}>\mathrm{D}\).
CHXII05:SURFACE CHEMISTRY
320901
Statement A : Lyophilic colloids are also called protective colloids. Statement B : The protecting power of lyophilic colloids is expensed in terms of gold number.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Due to more solvation, lyophilic colloids behaves as a protective colloid for lyophobic colloid. Higher is the gold number less is the repetitive power. So, the option (3) is correct.
CHXII05:SURFACE CHEMISTRY
320902
Gold numbers of some colloids are : Gelatin : \(0.005-0.01\), Gum Arabic : \(0.15-0.25\); Oleate \(: 0.04-1.0\); Starch : \(15-25\). Which among these is a better protective colloid?
1 Gelatin
2 Starch
3 Gum Arabic
4 Oleate
Explanation:
Lower the gold number, more will be the protective power of colloid.
JEE - 2016
CHXII05:SURFACE CHEMISTRY
320903
From the given following sol how many can coagulate silica acid sol? \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}, \mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), , Starch, Clay, \({\mathrm{\mathrm{As}_{2} \mathrm{~S}_{3}, \mathrm{CdS}}}\), Basic dye.
1 5
2 1
3 2
4 4
Explanation:
Salicilic acid is negatively charged sol. Hence the sol with positive charge can coagulate silicic acid, i.e., \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}}}\), \({\mathrm{\mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), basic dye.
CHXII05:SURFACE CHEMISTRY
320904
Hardy-Schulze rule explains the effect of electrolytes on the coagulation of colloidal solution. According to this rule, coagulation power of cations follow the order
According to this law, the coagulating effect of an ion increases with the increase in valency of the ion. The precipitating power of \(\mathrm{Al}^{+3}, \mathrm{Ba}^{+2}\) and \(\mathrm{Na}^{+}\)ions is in order \(\mathrm{Al}^{+3}>\mathrm{Ba}^{+2}>\mathrm{Na}^{+}\).
320900
The gold number of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are 0.04 , \(0.002,10\) and 25 respectively. Protective power of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are in order
1 A \(>\) B \(>\) C \(>\) D
2 B \(>\) A \(>\) C \(>\) D
3 D \(>\) C \(>\) B \(>\) A
4 C \(>\) A \(>\) B \(>\) D
Explanation:
\({\rm{Protective}}\,\,{\rm{power}}\,\,{\rm{\alpha }}\,\frac{{\rm{1}}}{{{\rm{ Gold}}\,{\rm{ number }}}}{\rm{.}}\) Hence, the correct order of protective power is \(\mathrm{B}>\mathrm{A}>\mathrm{C}>\mathrm{D}\).
CHXII05:SURFACE CHEMISTRY
320901
Statement A : Lyophilic colloids are also called protective colloids. Statement B : The protecting power of lyophilic colloids is expensed in terms of gold number.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Due to more solvation, lyophilic colloids behaves as a protective colloid for lyophobic colloid. Higher is the gold number less is the repetitive power. So, the option (3) is correct.
CHXII05:SURFACE CHEMISTRY
320902
Gold numbers of some colloids are : Gelatin : \(0.005-0.01\), Gum Arabic : \(0.15-0.25\); Oleate \(: 0.04-1.0\); Starch : \(15-25\). Which among these is a better protective colloid?
1 Gelatin
2 Starch
3 Gum Arabic
4 Oleate
Explanation:
Lower the gold number, more will be the protective power of colloid.
JEE - 2016
CHXII05:SURFACE CHEMISTRY
320903
From the given following sol how many can coagulate silica acid sol? \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}, \mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), , Starch, Clay, \({\mathrm{\mathrm{As}_{2} \mathrm{~S}_{3}, \mathrm{CdS}}}\), Basic dye.
1 5
2 1
3 2
4 4
Explanation:
Salicilic acid is negatively charged sol. Hence the sol with positive charge can coagulate silicic acid, i.e., \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}}}\), \({\mathrm{\mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), basic dye.
CHXII05:SURFACE CHEMISTRY
320904
Hardy-Schulze rule explains the effect of electrolytes on the coagulation of colloidal solution. According to this rule, coagulation power of cations follow the order
According to this law, the coagulating effect of an ion increases with the increase in valency of the ion. The precipitating power of \(\mathrm{Al}^{+3}, \mathrm{Ba}^{+2}\) and \(\mathrm{Na}^{+}\)ions is in order \(\mathrm{Al}^{+3}>\mathrm{Ba}^{+2}>\mathrm{Na}^{+}\).
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXII05:SURFACE CHEMISTRY
320900
The gold number of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are 0.04 , \(0.002,10\) and 25 respectively. Protective power of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are in order
1 A \(>\) B \(>\) C \(>\) D
2 B \(>\) A \(>\) C \(>\) D
3 D \(>\) C \(>\) B \(>\) A
4 C \(>\) A \(>\) B \(>\) D
Explanation:
\({\rm{Protective}}\,\,{\rm{power}}\,\,{\rm{\alpha }}\,\frac{{\rm{1}}}{{{\rm{ Gold}}\,{\rm{ number }}}}{\rm{.}}\) Hence, the correct order of protective power is \(\mathrm{B}>\mathrm{A}>\mathrm{C}>\mathrm{D}\).
CHXII05:SURFACE CHEMISTRY
320901
Statement A : Lyophilic colloids are also called protective colloids. Statement B : The protecting power of lyophilic colloids is expensed in terms of gold number.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Due to more solvation, lyophilic colloids behaves as a protective colloid for lyophobic colloid. Higher is the gold number less is the repetitive power. So, the option (3) is correct.
CHXII05:SURFACE CHEMISTRY
320902
Gold numbers of some colloids are : Gelatin : \(0.005-0.01\), Gum Arabic : \(0.15-0.25\); Oleate \(: 0.04-1.0\); Starch : \(15-25\). Which among these is a better protective colloid?
1 Gelatin
2 Starch
3 Gum Arabic
4 Oleate
Explanation:
Lower the gold number, more will be the protective power of colloid.
JEE - 2016
CHXII05:SURFACE CHEMISTRY
320903
From the given following sol how many can coagulate silica acid sol? \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}, \mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), , Starch, Clay, \({\mathrm{\mathrm{As}_{2} \mathrm{~S}_{3}, \mathrm{CdS}}}\), Basic dye.
1 5
2 1
3 2
4 4
Explanation:
Salicilic acid is negatively charged sol. Hence the sol with positive charge can coagulate silicic acid, i.e., \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}}}\), \({\mathrm{\mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), basic dye.
CHXII05:SURFACE CHEMISTRY
320904
Hardy-Schulze rule explains the effect of electrolytes on the coagulation of colloidal solution. According to this rule, coagulation power of cations follow the order
According to this law, the coagulating effect of an ion increases with the increase in valency of the ion. The precipitating power of \(\mathrm{Al}^{+3}, \mathrm{Ba}^{+2}\) and \(\mathrm{Na}^{+}\)ions is in order \(\mathrm{Al}^{+3}>\mathrm{Ba}^{+2}>\mathrm{Na}^{+}\).
320900
The gold number of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are 0.04 , \(0.002,10\) and 25 respectively. Protective power of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are in order
1 A \(>\) B \(>\) C \(>\) D
2 B \(>\) A \(>\) C \(>\) D
3 D \(>\) C \(>\) B \(>\) A
4 C \(>\) A \(>\) B \(>\) D
Explanation:
\({\rm{Protective}}\,\,{\rm{power}}\,\,{\rm{\alpha }}\,\frac{{\rm{1}}}{{{\rm{ Gold}}\,{\rm{ number }}}}{\rm{.}}\) Hence, the correct order of protective power is \(\mathrm{B}>\mathrm{A}>\mathrm{C}>\mathrm{D}\).
CHXII05:SURFACE CHEMISTRY
320901
Statement A : Lyophilic colloids are also called protective colloids. Statement B : The protecting power of lyophilic colloids is expensed in terms of gold number.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Due to more solvation, lyophilic colloids behaves as a protective colloid for lyophobic colloid. Higher is the gold number less is the repetitive power. So, the option (3) is correct.
CHXII05:SURFACE CHEMISTRY
320902
Gold numbers of some colloids are : Gelatin : \(0.005-0.01\), Gum Arabic : \(0.15-0.25\); Oleate \(: 0.04-1.0\); Starch : \(15-25\). Which among these is a better protective colloid?
1 Gelatin
2 Starch
3 Gum Arabic
4 Oleate
Explanation:
Lower the gold number, more will be the protective power of colloid.
JEE - 2016
CHXII05:SURFACE CHEMISTRY
320903
From the given following sol how many can coagulate silica acid sol? \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}, \mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), , Starch, Clay, \({\mathrm{\mathrm{As}_{2} \mathrm{~S}_{3}, \mathrm{CdS}}}\), Basic dye.
1 5
2 1
3 2
4 4
Explanation:
Salicilic acid is negatively charged sol. Hence the sol with positive charge can coagulate silicic acid, i.e., \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}}}\), \({\mathrm{\mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), basic dye.
CHXII05:SURFACE CHEMISTRY
320904
Hardy-Schulze rule explains the effect of electrolytes on the coagulation of colloidal solution. According to this rule, coagulation power of cations follow the order
According to this law, the coagulating effect of an ion increases with the increase in valency of the ion. The precipitating power of \(\mathrm{Al}^{+3}, \mathrm{Ba}^{+2}\) and \(\mathrm{Na}^{+}\)ions is in order \(\mathrm{Al}^{+3}>\mathrm{Ba}^{+2}>\mathrm{Na}^{+}\).
320900
The gold number of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are 0.04 , \(0.002,10\) and 25 respectively. Protective power of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and \(\mathrm{D}\) are in order
1 A \(>\) B \(>\) C \(>\) D
2 B \(>\) A \(>\) C \(>\) D
3 D \(>\) C \(>\) B \(>\) A
4 C \(>\) A \(>\) B \(>\) D
Explanation:
\({\rm{Protective}}\,\,{\rm{power}}\,\,{\rm{\alpha }}\,\frac{{\rm{1}}}{{{\rm{ Gold}}\,{\rm{ number }}}}{\rm{.}}\) Hence, the correct order of protective power is \(\mathrm{B}>\mathrm{A}>\mathrm{C}>\mathrm{D}\).
CHXII05:SURFACE CHEMISTRY
320901
Statement A : Lyophilic colloids are also called protective colloids. Statement B : The protecting power of lyophilic colloids is expensed in terms of gold number.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Due to more solvation, lyophilic colloids behaves as a protective colloid for lyophobic colloid. Higher is the gold number less is the repetitive power. So, the option (3) is correct.
CHXII05:SURFACE CHEMISTRY
320902
Gold numbers of some colloids are : Gelatin : \(0.005-0.01\), Gum Arabic : \(0.15-0.25\); Oleate \(: 0.04-1.0\); Starch : \(15-25\). Which among these is a better protective colloid?
1 Gelatin
2 Starch
3 Gum Arabic
4 Oleate
Explanation:
Lower the gold number, more will be the protective power of colloid.
JEE - 2016
CHXII05:SURFACE CHEMISTRY
320903
From the given following sol how many can coagulate silica acid sol? \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}, \mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), , Starch, Clay, \({\mathrm{\mathrm{As}_{2} \mathrm{~S}_{3}, \mathrm{CdS}}}\), Basic dye.
1 5
2 1
3 2
4 4
Explanation:
Salicilic acid is negatively charged sol. Hence the sol with positive charge can coagulate silicic acid, i.e., \({\mathrm{\mathrm{Fe}(\mathrm{OH})_{3}}}\), \({\mathrm{\mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{Al}(\mathrm{OH})_{3}}}\), basic dye.
CHXII05:SURFACE CHEMISTRY
320904
Hardy-Schulze rule explains the effect of electrolytes on the coagulation of colloidal solution. According to this rule, coagulation power of cations follow the order
According to this law, the coagulating effect of an ion increases with the increase in valency of the ion. The precipitating power of \(\mathrm{Al}^{+3}, \mathrm{Ba}^{+2}\) and \(\mathrm{Na}^{+}\)ions is in order \(\mathrm{Al}^{+3}>\mathrm{Ba}^{+2}>\mathrm{Na}^{+}\).