320893 \(10^{-4} \mathrm{~g}\) of gelation is required to be added to \(100 \mathrm{~cm}^{3}\) of a standard gold solution to just prevent its precipitation by addition of \(1 \mathrm{~cm}^{3}\) of \(10 \%\) \(\mathrm{NaCl}\) solution to it. Hence the gold number of gelation in \(\mathrm{mg}\) is
320893 \(10^{-4} \mathrm{~g}\) of gelation is required to be added to \(100 \mathrm{~cm}^{3}\) of a standard gold solution to just prevent its precipitation by addition of \(1 \mathrm{~cm}^{3}\) of \(10 \%\) \(\mathrm{NaCl}\) solution to it. Hence the gold number of gelation in \(\mathrm{mg}\) is
320893 \(10^{-4} \mathrm{~g}\) of gelation is required to be added to \(100 \mathrm{~cm}^{3}\) of a standard gold solution to just prevent its precipitation by addition of \(1 \mathrm{~cm}^{3}\) of \(10 \%\) \(\mathrm{NaCl}\) solution to it. Hence the gold number of gelation in \(\mathrm{mg}\) is
320893 \(10^{-4} \mathrm{~g}\) of gelation is required to be added to \(100 \mathrm{~cm}^{3}\) of a standard gold solution to just prevent its precipitation by addition of \(1 \mathrm{~cm}^{3}\) of \(10 \%\) \(\mathrm{NaCl}\) solution to it. Hence the gold number of gelation in \(\mathrm{mg}\) is