Adsorption
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CHXII05:SURFACE CHEMISTRY

320831 Select the correct option for the following graph:
supporting img

1 \({{\rm{T}}_{\rm{1}}}{\rm{ > }}{{\rm{T}}_{\rm{2}}}{\rm{ > }}{{\rm{T}}_{\rm{3}}}\)
2 \({{\rm{T}}_{\rm{1}}}{\rm{ = }}{{\rm{T}}_{\rm{2}}}{\rm{ = }}{{\rm{T}}_{\rm{3}}}\)
3 \({{\rm{T}}_{\rm{1}}}{\rm{ < }}{{\rm{T}}_{\rm{2}}}{\rm{ < }}{{\rm{T}}_{\rm{3}}}\)
4 \({{\rm{T}}_{\rm{1}}}{\rm{ < }}{{\rm{T}}_{\rm{2}}}{\rm{ > }}{{\rm{T}}_{\rm{3}}}\)
CHXII05:SURFACE CHEMISTRY

320832 Graph between \({\rm{log}}\frac{{\rm{x}}}{{\rm{m}}}\) and \(\log \mathrm{P}\) is a straight line inclined at an angle of \(45^{\circ}\). When pressure is \(0.5 \mathrm{~atm}\) and \(\ln \mathrm{k}=0.693\), the amount of solute adsorbed per gram of adsorbent will be :

1 2.5
2 1
3 1.5
4 0.25
CHXII05:SURFACE CHEMISTRY

320833 Statement A :
According to Freundlich adsorption isotherm, \(\dfrac{\mathrm{x}}{\mathrm{m}}=\mathrm{k} \cdot \mathrm{p}^{0}\) at high pressure.
Statement B :
The isotherm shows variation of the amount of gas adsorbed by the adsorbent with temperature.

1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
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CHXII05:SURFACE CHEMISTRY

320831 Select the correct option for the following graph:
supporting img

1 \({{\rm{T}}_{\rm{1}}}{\rm{ > }}{{\rm{T}}_{\rm{2}}}{\rm{ > }}{{\rm{T}}_{\rm{3}}}\)
2 \({{\rm{T}}_{\rm{1}}}{\rm{ = }}{{\rm{T}}_{\rm{2}}}{\rm{ = }}{{\rm{T}}_{\rm{3}}}\)
3 \({{\rm{T}}_{\rm{1}}}{\rm{ < }}{{\rm{T}}_{\rm{2}}}{\rm{ < }}{{\rm{T}}_{\rm{3}}}\)
4 \({{\rm{T}}_{\rm{1}}}{\rm{ < }}{{\rm{T}}_{\rm{2}}}{\rm{ > }}{{\rm{T}}_{\rm{3}}}\)
CHXII05:SURFACE CHEMISTRY

320832 Graph between \({\rm{log}}\frac{{\rm{x}}}{{\rm{m}}}\) and \(\log \mathrm{P}\) is a straight line inclined at an angle of \(45^{\circ}\). When pressure is \(0.5 \mathrm{~atm}\) and \(\ln \mathrm{k}=0.693\), the amount of solute adsorbed per gram of adsorbent will be :

1 2.5
2 1
3 1.5
4 0.25
CHXII05:SURFACE CHEMISTRY

320833 Statement A :
According to Freundlich adsorption isotherm, \(\dfrac{\mathrm{x}}{\mathrm{m}}=\mathrm{k} \cdot \mathrm{p}^{0}\) at high pressure.
Statement B :
The isotherm shows variation of the amount of gas adsorbed by the adsorbent with temperature.

1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
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CHXII05:SURFACE CHEMISTRY

320831 Select the correct option for the following graph:
supporting img

1 \({{\rm{T}}_{\rm{1}}}{\rm{ > }}{{\rm{T}}_{\rm{2}}}{\rm{ > }}{{\rm{T}}_{\rm{3}}}\)
2 \({{\rm{T}}_{\rm{1}}}{\rm{ = }}{{\rm{T}}_{\rm{2}}}{\rm{ = }}{{\rm{T}}_{\rm{3}}}\)
3 \({{\rm{T}}_{\rm{1}}}{\rm{ < }}{{\rm{T}}_{\rm{2}}}{\rm{ < }}{{\rm{T}}_{\rm{3}}}\)
4 \({{\rm{T}}_{\rm{1}}}{\rm{ < }}{{\rm{T}}_{\rm{2}}}{\rm{ > }}{{\rm{T}}_{\rm{3}}}\)
CHXII05:SURFACE CHEMISTRY

320832 Graph between \({\rm{log}}\frac{{\rm{x}}}{{\rm{m}}}\) and \(\log \mathrm{P}\) is a straight line inclined at an angle of \(45^{\circ}\). When pressure is \(0.5 \mathrm{~atm}\) and \(\ln \mathrm{k}=0.693\), the amount of solute adsorbed per gram of adsorbent will be :

1 2.5
2 1
3 1.5
4 0.25
CHXII05:SURFACE CHEMISTRY

320833 Statement A :
According to Freundlich adsorption isotherm, \(\dfrac{\mathrm{x}}{\mathrm{m}}=\mathrm{k} \cdot \mathrm{p}^{0}\) at high pressure.
Statement B :
The isotherm shows variation of the amount of gas adsorbed by the adsorbent with temperature.

1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
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