320818
The slope of the straight line graph between \({\text{log}}\frac{{\text{x}}}{{\text{m}}}\,\,{\text{and}}\,\,{\text{logP}}\) for the adsorption of a gas on solid is
1 \(\mathrm{k}\)
2 \(\log \mathrm{k}\)
3 \({\rm{n}}\)
4 \(\frac{{\rm{1}}}{{\rm{n}}}\)
Explanation:
\({\text{log(x/m) = (1/n)logP + logk y = mX + C}}\)
CHXII05:SURFACE CHEMISTRY
320819
According to Freundlich adsorption isotherm, at high pressure, the value of\(\frac{{\text{x}}}{{\text{m}}}\) is
1 Directly proportional to pressure
2 Inversely proportional to pressure
3 Directly proportional to square of pressure
4 Independent of pressure
Explanation:
\(\frac{{\rm{x}}}{{\rm{m}}}\) doesn't depend on pressure.
CHXII05:SURFACE CHEMISTRY
320820
Which of the following graphs would yield a straight line?
According to Freundlich adsorption isotherm, \(\log (\mathrm{x} / \mathrm{m})=(1 / \mathrm{n}) \log \mathrm{P}+\log \mathrm{k}\) \({\rm{y = mx + C}}\) Plot of \(\log (\mathrm{x} / \mathrm{m})\) vs \(\log\) P gives a straight line with positive slope i.e., \({\rm{1 / n}}\)
CHXII05:SURFACE CHEMISTRY
320821
The plot of \(\frac{{\rm{x}}}{{\rm{m}}}\) Vs temperature at constant pressure is called
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CHXII05:SURFACE CHEMISTRY
320818
The slope of the straight line graph between \({\text{log}}\frac{{\text{x}}}{{\text{m}}}\,\,{\text{and}}\,\,{\text{logP}}\) for the adsorption of a gas on solid is
1 \(\mathrm{k}\)
2 \(\log \mathrm{k}\)
3 \({\rm{n}}\)
4 \(\frac{{\rm{1}}}{{\rm{n}}}\)
Explanation:
\({\text{log(x/m) = (1/n)logP + logk y = mX + C}}\)
CHXII05:SURFACE CHEMISTRY
320819
According to Freundlich adsorption isotherm, at high pressure, the value of\(\frac{{\text{x}}}{{\text{m}}}\) is
1 Directly proportional to pressure
2 Inversely proportional to pressure
3 Directly proportional to square of pressure
4 Independent of pressure
Explanation:
\(\frac{{\rm{x}}}{{\rm{m}}}\) doesn't depend on pressure.
CHXII05:SURFACE CHEMISTRY
320820
Which of the following graphs would yield a straight line?
According to Freundlich adsorption isotherm, \(\log (\mathrm{x} / \mathrm{m})=(1 / \mathrm{n}) \log \mathrm{P}+\log \mathrm{k}\) \({\rm{y = mx + C}}\) Plot of \(\log (\mathrm{x} / \mathrm{m})\) vs \(\log\) P gives a straight line with positive slope i.e., \({\rm{1 / n}}\)
CHXII05:SURFACE CHEMISTRY
320821
The plot of \(\frac{{\rm{x}}}{{\rm{m}}}\) Vs temperature at constant pressure is called
320818
The slope of the straight line graph between \({\text{log}}\frac{{\text{x}}}{{\text{m}}}\,\,{\text{and}}\,\,{\text{logP}}\) for the adsorption of a gas on solid is
1 \(\mathrm{k}\)
2 \(\log \mathrm{k}\)
3 \({\rm{n}}\)
4 \(\frac{{\rm{1}}}{{\rm{n}}}\)
Explanation:
\({\text{log(x/m) = (1/n)logP + logk y = mX + C}}\)
CHXII05:SURFACE CHEMISTRY
320819
According to Freundlich adsorption isotherm, at high pressure, the value of\(\frac{{\text{x}}}{{\text{m}}}\) is
1 Directly proportional to pressure
2 Inversely proportional to pressure
3 Directly proportional to square of pressure
4 Independent of pressure
Explanation:
\(\frac{{\rm{x}}}{{\rm{m}}}\) doesn't depend on pressure.
CHXII05:SURFACE CHEMISTRY
320820
Which of the following graphs would yield a straight line?
According to Freundlich adsorption isotherm, \(\log (\mathrm{x} / \mathrm{m})=(1 / \mathrm{n}) \log \mathrm{P}+\log \mathrm{k}\) \({\rm{y = mx + C}}\) Plot of \(\log (\mathrm{x} / \mathrm{m})\) vs \(\log\) P gives a straight line with positive slope i.e., \({\rm{1 / n}}\)
CHXII05:SURFACE CHEMISTRY
320821
The plot of \(\frac{{\rm{x}}}{{\rm{m}}}\) Vs temperature at constant pressure is called
320818
The slope of the straight line graph between \({\text{log}}\frac{{\text{x}}}{{\text{m}}}\,\,{\text{and}}\,\,{\text{logP}}\) for the adsorption of a gas on solid is
1 \(\mathrm{k}\)
2 \(\log \mathrm{k}\)
3 \({\rm{n}}\)
4 \(\frac{{\rm{1}}}{{\rm{n}}}\)
Explanation:
\({\text{log(x/m) = (1/n)logP + logk y = mX + C}}\)
CHXII05:SURFACE CHEMISTRY
320819
According to Freundlich adsorption isotherm, at high pressure, the value of\(\frac{{\text{x}}}{{\text{m}}}\) is
1 Directly proportional to pressure
2 Inversely proportional to pressure
3 Directly proportional to square of pressure
4 Independent of pressure
Explanation:
\(\frac{{\rm{x}}}{{\rm{m}}}\) doesn't depend on pressure.
CHXII05:SURFACE CHEMISTRY
320820
Which of the following graphs would yield a straight line?
According to Freundlich adsorption isotherm, \(\log (\mathrm{x} / \mathrm{m})=(1 / \mathrm{n}) \log \mathrm{P}+\log \mathrm{k}\) \({\rm{y = mx + C}}\) Plot of \(\log (\mathrm{x} / \mathrm{m})\) vs \(\log\) P gives a straight line with positive slope i.e., \({\rm{1 / n}}\)
CHXII05:SURFACE CHEMISTRY
320821
The plot of \(\frac{{\rm{x}}}{{\rm{m}}}\) Vs temperature at constant pressure is called