Molecularity and Mechanism of a Reaction
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CHXII04:CHEMICAL KINETICS

320535 Nitric oxide (NO) reacts with oxygen to produce nitrogen dioxide
\({\text{2N}}{{\text{O}}_{{\text{(g)}}}}{\text{  +  }}{{\text{O}}_{\text{2}}}{\text{(g)}}\xrightarrow{{\text{K}}}{\text{2N}}{{\text{O}}_{{\text{2(g)}}}}\)
If the mechanism of reaction is
\({\text{NO  +  }}{{\text{O}}_{\text{2}}}\mathop  \rightleftharpoons \limits_{\text{K}} {{\text{N}}_{\text{3}}}{\text{( fast )}}{\mkern 1mu} {\text{N}}{{\text{O}}_{\text{3}}}{\text{  +  NO}}\xrightarrow{{{{\text{K}}_{\text{1}}}}}\)
\({\text{N}}{{\text{O}}_{\text{2}}}{\text{  +  N}}{{\text{O}}_{\text{2}}}{\text{(slow)}}\)
then rate law is

1 Rate \(=K^{\prime}[N O]\left[O_{2}\right]\)
2 Rate \(=K^{\prime}[\mathrm{NO}]\left[\mathrm{O}_{2}\right]^{2}\)
3 Rate \(=K^{\prime}[N O]^{2}\left[\mathrm{O}_{2}\right]\)
4 Rate \(=K^{\prime}[N O]^{3}\left[\mathrm{O}_{2}\right]\)
CHXII04:CHEMICAL KINETICS

320536 The plot of \({{\rm{t}}_{{\rm{1/2}}}}\,\,{\rm{v/s}}\,{{\rm{[R]}}_{\rm{0}}}\) for a reaction is a straight-line parallel to \(x\)-axis. The unit for the rate constant of this reaction is

1 \(\mathrm{molL}^{-1} \mathrm{~s}\)
2 \(\mathrm{molL}^{-1} \mathrm{~s}^{-1}\)
3 \(\mathrm{Lmol}^{-1} \mathrm{~s}^{-1}\)
4 \(\mathrm{s}^{-1}\)
CHXII04:CHEMICAL KINETICS

320537 The reaction, \({\rm{X + 2Y + Z}} \to {\rm{N}}\) occurs by the following mechanism

(i) \(X + Y \rightleftharpoons M\) very rapid equilibrium)

(ii) \({\rm{M + Z}} \to {\rm{O}}\) (slow) (iii) \({\rm{O + Y}} \to {\rm{N}}\) (very fast)

What is the rate law for this reaction?

1 \({\rm{Rate = k[Z]}}\)
2 \({\rm{Rate = k[X][Y}}{{\rm{]}}^{\rm{2}}}{\rm{[Z]}}\)
3 \({\rm{Rate = k[\;N]}}\)
4 \({\rm{Rate = k[X][Y][Z]}}\)
CHXII04:CHEMICAL KINETICS

320538 The reaction, \(X_{2}+Y_{2} \rightarrow 2 X Y\) occurs by the following mechanism

(i) \(X_{2} \rightleftharpoons 2 X\) (fast)

(ii) \(X+Y_{2} \rightarrow X Y+X\) (slow)

(iii) \(X+Y \rightarrow X Y\) (fast)
What is the order of the reaction?

1 2
2 0
3 -1
4 1.5
CHXII04:CHEMICAL KINETICS

320535 Nitric oxide (NO) reacts with oxygen to produce nitrogen dioxide
\({\text{2N}}{{\text{O}}_{{\text{(g)}}}}{\text{  +  }}{{\text{O}}_{\text{2}}}{\text{(g)}}\xrightarrow{{\text{K}}}{\text{2N}}{{\text{O}}_{{\text{2(g)}}}}\)
If the mechanism of reaction is
\({\text{NO  +  }}{{\text{O}}_{\text{2}}}\mathop  \rightleftharpoons \limits_{\text{K}} {{\text{N}}_{\text{3}}}{\text{( fast )}}{\mkern 1mu} {\text{N}}{{\text{O}}_{\text{3}}}{\text{  +  NO}}\xrightarrow{{{{\text{K}}_{\text{1}}}}}\)
\({\text{N}}{{\text{O}}_{\text{2}}}{\text{  +  N}}{{\text{O}}_{\text{2}}}{\text{(slow)}}\)
then rate law is

1 Rate \(=K^{\prime}[N O]\left[O_{2}\right]\)
2 Rate \(=K^{\prime}[\mathrm{NO}]\left[\mathrm{O}_{2}\right]^{2}\)
3 Rate \(=K^{\prime}[N O]^{2}\left[\mathrm{O}_{2}\right]\)
4 Rate \(=K^{\prime}[N O]^{3}\left[\mathrm{O}_{2}\right]\)
CHXII04:CHEMICAL KINETICS

320536 The plot of \({{\rm{t}}_{{\rm{1/2}}}}\,\,{\rm{v/s}}\,{{\rm{[R]}}_{\rm{0}}}\) for a reaction is a straight-line parallel to \(x\)-axis. The unit for the rate constant of this reaction is

1 \(\mathrm{molL}^{-1} \mathrm{~s}\)
2 \(\mathrm{molL}^{-1} \mathrm{~s}^{-1}\)
3 \(\mathrm{Lmol}^{-1} \mathrm{~s}^{-1}\)
4 \(\mathrm{s}^{-1}\)
CHXII04:CHEMICAL KINETICS

320537 The reaction, \({\rm{X + 2Y + Z}} \to {\rm{N}}\) occurs by the following mechanism

(i) \(X + Y \rightleftharpoons M\) very rapid equilibrium)

(ii) \({\rm{M + Z}} \to {\rm{O}}\) (slow) (iii) \({\rm{O + Y}} \to {\rm{N}}\) (very fast)

What is the rate law for this reaction?

1 \({\rm{Rate = k[Z]}}\)
2 \({\rm{Rate = k[X][Y}}{{\rm{]}}^{\rm{2}}}{\rm{[Z]}}\)
3 \({\rm{Rate = k[\;N]}}\)
4 \({\rm{Rate = k[X][Y][Z]}}\)
CHXII04:CHEMICAL KINETICS

320538 The reaction, \(X_{2}+Y_{2} \rightarrow 2 X Y\) occurs by the following mechanism

(i) \(X_{2} \rightleftharpoons 2 X\) (fast)

(ii) \(X+Y_{2} \rightarrow X Y+X\) (slow)

(iii) \(X+Y \rightarrow X Y\) (fast)
What is the order of the reaction?

1 2
2 0
3 -1
4 1.5
CHXII04:CHEMICAL KINETICS

320535 Nitric oxide (NO) reacts with oxygen to produce nitrogen dioxide
\({\text{2N}}{{\text{O}}_{{\text{(g)}}}}{\text{  +  }}{{\text{O}}_{\text{2}}}{\text{(g)}}\xrightarrow{{\text{K}}}{\text{2N}}{{\text{O}}_{{\text{2(g)}}}}\)
If the mechanism of reaction is
\({\text{NO  +  }}{{\text{O}}_{\text{2}}}\mathop  \rightleftharpoons \limits_{\text{K}} {{\text{N}}_{\text{3}}}{\text{( fast )}}{\mkern 1mu} {\text{N}}{{\text{O}}_{\text{3}}}{\text{  +  NO}}\xrightarrow{{{{\text{K}}_{\text{1}}}}}\)
\({\text{N}}{{\text{O}}_{\text{2}}}{\text{  +  N}}{{\text{O}}_{\text{2}}}{\text{(slow)}}\)
then rate law is

1 Rate \(=K^{\prime}[N O]\left[O_{2}\right]\)
2 Rate \(=K^{\prime}[\mathrm{NO}]\left[\mathrm{O}_{2}\right]^{2}\)
3 Rate \(=K^{\prime}[N O]^{2}\left[\mathrm{O}_{2}\right]\)
4 Rate \(=K^{\prime}[N O]^{3}\left[\mathrm{O}_{2}\right]\)
CHXII04:CHEMICAL KINETICS

320536 The plot of \({{\rm{t}}_{{\rm{1/2}}}}\,\,{\rm{v/s}}\,{{\rm{[R]}}_{\rm{0}}}\) for a reaction is a straight-line parallel to \(x\)-axis. The unit for the rate constant of this reaction is

1 \(\mathrm{molL}^{-1} \mathrm{~s}\)
2 \(\mathrm{molL}^{-1} \mathrm{~s}^{-1}\)
3 \(\mathrm{Lmol}^{-1} \mathrm{~s}^{-1}\)
4 \(\mathrm{s}^{-1}\)
CHXII04:CHEMICAL KINETICS

320537 The reaction, \({\rm{X + 2Y + Z}} \to {\rm{N}}\) occurs by the following mechanism

(i) \(X + Y \rightleftharpoons M\) very rapid equilibrium)

(ii) \({\rm{M + Z}} \to {\rm{O}}\) (slow) (iii) \({\rm{O + Y}} \to {\rm{N}}\) (very fast)

What is the rate law for this reaction?

1 \({\rm{Rate = k[Z]}}\)
2 \({\rm{Rate = k[X][Y}}{{\rm{]}}^{\rm{2}}}{\rm{[Z]}}\)
3 \({\rm{Rate = k[\;N]}}\)
4 \({\rm{Rate = k[X][Y][Z]}}\)
CHXII04:CHEMICAL KINETICS

320538 The reaction, \(X_{2}+Y_{2} \rightarrow 2 X Y\) occurs by the following mechanism

(i) \(X_{2} \rightleftharpoons 2 X\) (fast)

(ii) \(X+Y_{2} \rightarrow X Y+X\) (slow)

(iii) \(X+Y \rightarrow X Y\) (fast)
What is the order of the reaction?

1 2
2 0
3 -1
4 1.5
CHXII04:CHEMICAL KINETICS

320535 Nitric oxide (NO) reacts with oxygen to produce nitrogen dioxide
\({\text{2N}}{{\text{O}}_{{\text{(g)}}}}{\text{  +  }}{{\text{O}}_{\text{2}}}{\text{(g)}}\xrightarrow{{\text{K}}}{\text{2N}}{{\text{O}}_{{\text{2(g)}}}}\)
If the mechanism of reaction is
\({\text{NO  +  }}{{\text{O}}_{\text{2}}}\mathop  \rightleftharpoons \limits_{\text{K}} {{\text{N}}_{\text{3}}}{\text{( fast )}}{\mkern 1mu} {\text{N}}{{\text{O}}_{\text{3}}}{\text{  +  NO}}\xrightarrow{{{{\text{K}}_{\text{1}}}}}\)
\({\text{N}}{{\text{O}}_{\text{2}}}{\text{  +  N}}{{\text{O}}_{\text{2}}}{\text{(slow)}}\)
then rate law is

1 Rate \(=K^{\prime}[N O]\left[O_{2}\right]\)
2 Rate \(=K^{\prime}[\mathrm{NO}]\left[\mathrm{O}_{2}\right]^{2}\)
3 Rate \(=K^{\prime}[N O]^{2}\left[\mathrm{O}_{2}\right]\)
4 Rate \(=K^{\prime}[N O]^{3}\left[\mathrm{O}_{2}\right]\)
CHXII04:CHEMICAL KINETICS

320536 The plot of \({{\rm{t}}_{{\rm{1/2}}}}\,\,{\rm{v/s}}\,{{\rm{[R]}}_{\rm{0}}}\) for a reaction is a straight-line parallel to \(x\)-axis. The unit for the rate constant of this reaction is

1 \(\mathrm{molL}^{-1} \mathrm{~s}\)
2 \(\mathrm{molL}^{-1} \mathrm{~s}^{-1}\)
3 \(\mathrm{Lmol}^{-1} \mathrm{~s}^{-1}\)
4 \(\mathrm{s}^{-1}\)
CHXII04:CHEMICAL KINETICS

320537 The reaction, \({\rm{X + 2Y + Z}} \to {\rm{N}}\) occurs by the following mechanism

(i) \(X + Y \rightleftharpoons M\) very rapid equilibrium)

(ii) \({\rm{M + Z}} \to {\rm{O}}\) (slow) (iii) \({\rm{O + Y}} \to {\rm{N}}\) (very fast)

What is the rate law for this reaction?

1 \({\rm{Rate = k[Z]}}\)
2 \({\rm{Rate = k[X][Y}}{{\rm{]}}^{\rm{2}}}{\rm{[Z]}}\)
3 \({\rm{Rate = k[\;N]}}\)
4 \({\rm{Rate = k[X][Y][Z]}}\)
CHXII04:CHEMICAL KINETICS

320538 The reaction, \(X_{2}+Y_{2} \rightarrow 2 X Y\) occurs by the following mechanism

(i) \(X_{2} \rightleftharpoons 2 X\) (fast)

(ii) \(X+Y_{2} \rightarrow X Y+X\) (slow)

(iii) \(X+Y \rightarrow X Y\) (fast)
What is the order of the reaction?

1 2
2 0
3 -1
4 1.5