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CHXII03:ELECTROCHEMISTRY

330365 Assertion :
The cell constant of a conductivity cell depends upon the nature of the material of the electrodes.
Reason :
The electrodes of the cell are coated with platinum black to avoid polarization effects.

1 If both the assertion and reason are true and reason is a true explanation of the assertion

2 If both the assertion and reason are true but the reason is not the correct explanation of assertion

3 If the assertion is true but reason is false

4 If assertion is false but reason is true.

CHXII03:ELECTROCHEMISTRY

330366 A conductivity cell shows resistance of $600 ohm$ . If conductivity of $0.01 M KCl$ is $0.0015 Ω^{- 1} {cm}^{- 1}$ , what is cell constant?

1

0.60 {cm}^{- 1}

2

0.45 {cm}^{- 1}

3

0.90 {cm}^{- 1}

4

0.75 {cm}^{- 1}

Explanation:

$R = 600 Ω, k_{KCl} = 0.0015 Ω^{-} {cm}^{- 1}$
Cell constnat $= k_{KCl} \times R_{solution}$
$= 0.0015 Ω^{- 1} {cm}^{- 1} \times 600 Ω = 0.90 {cm}^{- 1}$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330367 Assertion :
The observed conductance depends upon the nature of the electrolyte and the concentration of the solution
Reason :
The cell constant of a cell depends upon the nature of the material of the electrodes.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

CHXII03:ELECTROCHEMISTRY

330368 What is the resistance of $0.01 M KCl$ solution if its conductivity is $200 {ohm}^{- 1} {cm}^{- 1}$ and cell constant is $1 {cm}^{- 1}$ ?

1

1 \times 10^{- 3} ohm

2

5 \times 10^{- 3} ohm

3

4 \times 10^{- 3} ohm

4

2 \times 10^{- 3} ohm

Explanation:

$k = 200 oh m^{- 1} c m^{- 1}$ , cell constant
$R_{Solution} = \frac{Cell constant}{k_{KCl}}$
$= \frac{1 c m^{- 1}}{200 oh m^{- 1} c m^{- 1}} = 5 \times 10^{- 3} ohm$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330369 The equivalent conductivity of a solution containing 2.54 grams of ${CuSO}_{4}$ per litre is $91.0 Ω^{- 1} {cm}^{2} {eq}^{- 1}$ . Its conductivity would

1

2.9 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

2

1.8 \times 10^{- 2} Ω^{- 1} {cm}^{- 1}

3

2.4 \times 10^{- 4} Ω^{- 1} {cm}^{- 1}

4

3.6 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

Explanation:

$k = Λ_{eq} \times C$
$= (91 Ω^{- 1} c m^{2} e q^{- 1}) (\frac{2.54}{(159 / 2) \times 1000} e q \cdot c m^{- 3})$
$= 2.9 \times 10^{- 3} Ω^{- 1} c m^{- 1}$

CHXII03:ELECTROCHEMISTRY

330365 Assertion :
The cell constant of a conductivity cell depends upon the nature of the material of the electrodes.
Reason :
The electrodes of the cell are coated with platinum black to avoid polarization effects.

1 If both the assertion and reason are true and reason is a true explanation of the assertion

2 If both the assertion and reason are true but the reason is not the correct explanation of assertion

3 If the assertion is true but reason is false

4 If assertion is false but reason is true.

CHXII03:ELECTROCHEMISTRY

330366 A conductivity cell shows resistance of $600 ohm$ . If conductivity of $0.01 M KCl$ is $0.0015 Ω^{- 1} {cm}^{- 1}$ , what is cell constant?

1

0.60 {cm}^{- 1}

2

0.45 {cm}^{- 1}

3

0.90 {cm}^{- 1}

4

0.75 {cm}^{- 1}

Explanation:

$R = 600 Ω, k_{KCl} = 0.0015 Ω^{-} {cm}^{- 1}$
Cell constnat $= k_{KCl} \times R_{solution}$
$= 0.0015 Ω^{- 1} {cm}^{- 1} \times 600 Ω = 0.90 {cm}^{- 1}$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330367 Assertion :
The observed conductance depends upon the nature of the electrolyte and the concentration of the solution
Reason :
The cell constant of a cell depends upon the nature of the material of the electrodes.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

CHXII03:ELECTROCHEMISTRY

330368 What is the resistance of $0.01 M KCl$ solution if its conductivity is $200 {ohm}^{- 1} {cm}^{- 1}$ and cell constant is $1 {cm}^{- 1}$ ?

1

1 \times 10^{- 3} ohm

2

5 \times 10^{- 3} ohm

3

4 \times 10^{- 3} ohm

4

2 \times 10^{- 3} ohm

Explanation:

$k = 200 oh m^{- 1} c m^{- 1}$ , cell constant
$R_{Solution} = \frac{Cell constant}{k_{KCl}}$
$= \frac{1 c m^{- 1}}{200 oh m^{- 1} c m^{- 1}} = 5 \times 10^{- 3} ohm$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330369 The equivalent conductivity of a solution containing 2.54 grams of ${CuSO}_{4}$ per litre is $91.0 Ω^{- 1} {cm}^{2} {eq}^{- 1}$ . Its conductivity would

1

2.9 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

2

1.8 \times 10^{- 2} Ω^{- 1} {cm}^{- 1}

3

2.4 \times 10^{- 4} Ω^{- 1} {cm}^{- 1}

4

3.6 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

Explanation:

$k = Λ_{eq} \times C$
$= (91 Ω^{- 1} c m^{2} e q^{- 1}) (\frac{2.54}{(159 / 2) \times 1000} e q \cdot c m^{- 3})$
$= 2.9 \times 10^{- 3} Ω^{- 1} c m^{- 1}$

CHXII03:ELECTROCHEMISTRY

330365 Assertion :
The cell constant of a conductivity cell depends upon the nature of the material of the electrodes.
Reason :
The electrodes of the cell are coated with platinum black to avoid polarization effects.

1 If both the assertion and reason are true and reason is a true explanation of the assertion

2 If both the assertion and reason are true but the reason is not the correct explanation of assertion

3 If the assertion is true but reason is false

4 If assertion is false but reason is true.

CHXII03:ELECTROCHEMISTRY

330366 A conductivity cell shows resistance of $600 ohm$ . If conductivity of $0.01 M KCl$ is $0.0015 Ω^{- 1} {cm}^{- 1}$ , what is cell constant?

1

0.60 {cm}^{- 1}

2

0.45 {cm}^{- 1}

3

0.90 {cm}^{- 1}

4

0.75 {cm}^{- 1}

Explanation:

$R = 600 Ω, k_{KCl} = 0.0015 Ω^{-} {cm}^{- 1}$
Cell constnat $= k_{KCl} \times R_{solution}$
$= 0.0015 Ω^{- 1} {cm}^{- 1} \times 600 Ω = 0.90 {cm}^{- 1}$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330367 Assertion :
The observed conductance depends upon the nature of the electrolyte and the concentration of the solution
Reason :
The cell constant of a cell depends upon the nature of the material of the electrodes.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

CHXII03:ELECTROCHEMISTRY

330368 What is the resistance of $0.01 M KCl$ solution if its conductivity is $200 {ohm}^{- 1} {cm}^{- 1}$ and cell constant is $1 {cm}^{- 1}$ ?

1

1 \times 10^{- 3} ohm

2

5 \times 10^{- 3} ohm

3

4 \times 10^{- 3} ohm

4

2 \times 10^{- 3} ohm

Explanation:

$k = 200 oh m^{- 1} c m^{- 1}$ , cell constant
$R_{Solution} = \frac{Cell constant}{k_{KCl}}$
$= \frac{1 c m^{- 1}}{200 oh m^{- 1} c m^{- 1}} = 5 \times 10^{- 3} ohm$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330369 The equivalent conductivity of a solution containing 2.54 grams of ${CuSO}_{4}$ per litre is $91.0 Ω^{- 1} {cm}^{2} {eq}^{- 1}$ . Its conductivity would

1

2.9 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

2

1.8 \times 10^{- 2} Ω^{- 1} {cm}^{- 1}

3

2.4 \times 10^{- 4} Ω^{- 1} {cm}^{- 1}

4

3.6 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

Explanation:

$k = Λ_{eq} \times C$
$= (91 Ω^{- 1} c m^{2} e q^{- 1}) (\frac{2.54}{(159 / 2) \times 1000} e q \cdot c m^{- 3})$
$= 2.9 \times 10^{- 3} Ω^{- 1} c m^{- 1}$

CHXII03:ELECTROCHEMISTRY

330365 Assertion :
The cell constant of a conductivity cell depends upon the nature of the material of the electrodes.
Reason :
The electrodes of the cell are coated with platinum black to avoid polarization effects.

1 If both the assertion and reason are true and reason is a true explanation of the assertion

2 If both the assertion and reason are true but the reason is not the correct explanation of assertion

3 If the assertion is true but reason is false

4 If assertion is false but reason is true.

CHXII03:ELECTROCHEMISTRY

330366 A conductivity cell shows resistance of $600 ohm$ . If conductivity of $0.01 M KCl$ is $0.0015 Ω^{- 1} {cm}^{- 1}$ , what is cell constant?

1

0.60 {cm}^{- 1}

2

0.45 {cm}^{- 1}

3

0.90 {cm}^{- 1}

4

0.75 {cm}^{- 1}

Explanation:

$R = 600 Ω, k_{KCl} = 0.0015 Ω^{-} {cm}^{- 1}$
Cell constnat $= k_{KCl} \times R_{solution}$
$= 0.0015 Ω^{- 1} {cm}^{- 1} \times 600 Ω = 0.90 {cm}^{- 1}$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330367 Assertion :
The observed conductance depends upon the nature of the electrolyte and the concentration of the solution
Reason :
The cell constant of a cell depends upon the nature of the material of the electrodes.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

CHXII03:ELECTROCHEMISTRY

330368 What is the resistance of $0.01 M KCl$ solution if its conductivity is $200 {ohm}^{- 1} {cm}^{- 1}$ and cell constant is $1 {cm}^{- 1}$ ?

1

1 \times 10^{- 3} ohm

2

5 \times 10^{- 3} ohm

3

4 \times 10^{- 3} ohm

4

2 \times 10^{- 3} ohm

Explanation:

$k = 200 oh m^{- 1} c m^{- 1}$ , cell constant
$R_{Solution} = \frac{Cell constant}{k_{KCl}}$
$= \frac{1 c m^{- 1}}{200 oh m^{- 1} c m^{- 1}} = 5 \times 10^{- 3} ohm$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330369 The equivalent conductivity of a solution containing 2.54 grams of ${CuSO}_{4}$ per litre is $91.0 Ω^{- 1} {cm}^{2} {eq}^{- 1}$ . Its conductivity would

1

2.9 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

2

1.8 \times 10^{- 2} Ω^{- 1} {cm}^{- 1}

3

2.4 \times 10^{- 4} Ω^{- 1} {cm}^{- 1}

4

3.6 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

Explanation:

$k = Λ_{eq} \times C$
$= (91 Ω^{- 1} c m^{2} e q^{- 1}) (\frac{2.54}{(159 / 2) \times 1000} e q \cdot c m^{- 3})$
$= 2.9 \times 10^{- 3} Ω^{- 1} c m^{- 1}$

CHXII03:ELECTROCHEMISTRY

330365 Assertion :
The cell constant of a conductivity cell depends upon the nature of the material of the electrodes.
Reason :
The electrodes of the cell are coated with platinum black to avoid polarization effects.

1 If both the assertion and reason are true and reason is a true explanation of the assertion

2 If both the assertion and reason are true but the reason is not the correct explanation of assertion

3 If the assertion is true but reason is false

4 If assertion is false but reason is true.

CHXII03:ELECTROCHEMISTRY

330366 A conductivity cell shows resistance of $600 ohm$ . If conductivity of $0.01 M KCl$ is $0.0015 Ω^{- 1} {cm}^{- 1}$ , what is cell constant?

1

0.60 {cm}^{- 1}

2

0.45 {cm}^{- 1}

3

0.90 {cm}^{- 1}

4

0.75 {cm}^{- 1}

Explanation:

$R = 600 Ω, k_{KCl} = 0.0015 Ω^{-} {cm}^{- 1}$
Cell constnat $= k_{KCl} \times R_{solution}$
$= 0.0015 Ω^{- 1} {cm}^{- 1} \times 600 Ω = 0.90 {cm}^{- 1}$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330367 Assertion :
The observed conductance depends upon the nature of the electrolyte and the concentration of the solution
Reason :
The cell constant of a cell depends upon the nature of the material of the electrodes.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

CHXII03:ELECTROCHEMISTRY

330368 What is the resistance of $0.01 M KCl$ solution if its conductivity is $200 {ohm}^{- 1} {cm}^{- 1}$ and cell constant is $1 {cm}^{- 1}$ ?

1

1 \times 10^{- 3} ohm

2

5 \times 10^{- 3} ohm

3

4 \times 10^{- 3} ohm

4

2 \times 10^{- 3} ohm

Explanation:

$k = 200 oh m^{- 1} c m^{- 1}$ , cell constant
$R_{Solution} = \frac{Cell constant}{k_{KCl}}$
$= \frac{1 c m^{- 1}}{200 oh m^{- 1} c m^{- 1}} = 5 \times 10^{- 3} ohm$

MHTCET - 2021

CHXII03:ELECTROCHEMISTRY

330369 The equivalent conductivity of a solution containing 2.54 grams of ${CuSO}_{4}$ per litre is $91.0 Ω^{- 1} {cm}^{2} {eq}^{- 1}$ . Its conductivity would

1

2.9 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

2

1.8 \times 10^{- 2} Ω^{- 1} {cm}^{- 1}

3

2.4 \times 10^{- 4} Ω^{- 1} {cm}^{- 1}

4

3.6 \times 10^{- 3} Ω^{- 1} {cm}^{- 1}

Explanation:

$k = Λ_{eq} \times C$
$= (91 Ω^{- 1} c m^{2} e q^{- 1}) (\frac{2.54}{(159 / 2) \times 1000} e q \cdot c m^{- 3})$
$= 2.9 \times 10^{- 3} Ω^{- 1} c m^{- 1}$