319488 If two substances \({\rm{A}}\,{\rm{and}}\,{\rm{B}}\,{\rm{have }}\,{{\rm{p}}_{\rm{A}}}{\rm{: }}\,{{\rm{p}}_{\rm{B}}}{\rm{ = 1}}:{\rm{2}}\) and have mole fraction in solution \(1: 2\) then mole fraction of \({\rm{A}}\) in vapours is

319489 A solution of A and B with 30% moles of A in solution is in equilibrium with its vapour which contains 60% moles of A. What will be the ratio of the vapour pressure of pure A to that of pure B? (Assume ideal nature)

319490 In which case Raoult's law is not applicable?

319491 At \(80^{\circ} \mathrm{C}\), the vapour pressure of pure liquid ' A ' is 520 mm Hg and that of pure liquid ' B ' is 1000 mm Hg . If a mixture solution of ' A ' and ' B ' boils at \(80^{\circ} \mathrm{C}\) and 1 atm pressure, the amount ' A ' in the mixture is
\((1\,{\rm{atm}} = 760\,\,{\rm{mm}}\,{\rm{Hg}})\)

319492 The determination of correct molecular weight from Raoult’s law is applicable to

319488 If two substances \({\rm{A}}\,{\rm{and}}\,{\rm{B}}\,{\rm{have }}\,{{\rm{p}}_{\rm{A}}}{\rm{: }}\,{{\rm{p}}_{\rm{B}}}{\rm{ = 1}}:{\rm{2}}\) and have mole fraction in solution \(1: 2\) then mole fraction of \({\rm{A}}\) in vapours is

319489 A solution of A and B with 30% moles of A in solution is in equilibrium with its vapour which contains 60% moles of A. What will be the ratio of the vapour pressure of pure A to that of pure B? (Assume ideal nature)

319490 In which case Raoult's law is not applicable?

319491 At \(80^{\circ} \mathrm{C}\), the vapour pressure of pure liquid ' A ' is 520 mm Hg and that of pure liquid ' B ' is 1000 mm Hg . If a mixture solution of ' A ' and ' B ' boils at \(80^{\circ} \mathrm{C}\) and 1 atm pressure, the amount ' A ' in the mixture is
\((1\,{\rm{atm}} = 760\,\,{\rm{mm}}\,{\rm{Hg}})\)

319492 The determination of correct molecular weight from Raoult’s law is applicable to

319488 If two substances \({\rm{A}}\,{\rm{and}}\,{\rm{B}}\,{\rm{have }}\,{{\rm{p}}_{\rm{A}}}{\rm{: }}\,{{\rm{p}}_{\rm{B}}}{\rm{ = 1}}:{\rm{2}}\) and have mole fraction in solution \(1: 2\) then mole fraction of \({\rm{A}}\) in vapours is

319489 A solution of A and B with 30% moles of A in solution is in equilibrium with its vapour which contains 60% moles of A. What will be the ratio of the vapour pressure of pure A to that of pure B? (Assume ideal nature)

319490 In which case Raoult's law is not applicable?

319491 At \(80^{\circ} \mathrm{C}\), the vapour pressure of pure liquid ' A ' is 520 mm Hg and that of pure liquid ' B ' is 1000 mm Hg . If a mixture solution of ' A ' and ' B ' boils at \(80^{\circ} \mathrm{C}\) and 1 atm pressure, the amount ' A ' in the mixture is
\((1\,{\rm{atm}} = 760\,\,{\rm{mm}}\,{\rm{Hg}})\)

319492 The determination of correct molecular weight from Raoult’s law is applicable to

319488 If two substances \({\rm{A}}\,{\rm{and}}\,{\rm{B}}\,{\rm{have }}\,{{\rm{p}}_{\rm{A}}}{\rm{: }}\,{{\rm{p}}_{\rm{B}}}{\rm{ = 1}}:{\rm{2}}\) and have mole fraction in solution \(1: 2\) then mole fraction of \({\rm{A}}\) in vapours is

319489 A solution of A and B with 30% moles of A in solution is in equilibrium with its vapour which contains 60% moles of A. What will be the ratio of the vapour pressure of pure A to that of pure B? (Assume ideal nature)

319490 In which case Raoult's law is not applicable?

319491 At \(80^{\circ} \mathrm{C}\), the vapour pressure of pure liquid ' A ' is 520 mm Hg and that of pure liquid ' B ' is 1000 mm Hg . If a mixture solution of ' A ' and ' B ' boils at \(80^{\circ} \mathrm{C}\) and 1 atm pressure, the amount ' A ' in the mixture is
\((1\,{\rm{atm}} = 760\,\,{\rm{mm}}\,{\rm{Hg}})\)

319492 The determination of correct molecular weight from Raoult’s law is applicable to

319488 If two substances \({\rm{A}}\,{\rm{and}}\,{\rm{B}}\,{\rm{have }}\,{{\rm{p}}_{\rm{A}}}{\rm{: }}\,{{\rm{p}}_{\rm{B}}}{\rm{ = 1}}:{\rm{2}}\) and have mole fraction in solution \(1: 2\) then mole fraction of \({\rm{A}}\) in vapours is

319489 A solution of A and B with 30% moles of A in solution is in equilibrium with its vapour which contains 60% moles of A. What will be the ratio of the vapour pressure of pure A to that of pure B? (Assume ideal nature)

319490 In which case Raoult's law is not applicable?

319491 At \(80^{\circ} \mathrm{C}\), the vapour pressure of pure liquid ' A ' is 520 mm Hg and that of pure liquid ' B ' is 1000 mm Hg . If a mixture solution of ' A ' and ' B ' boils at \(80^{\circ} \mathrm{C}\) and 1 atm pressure, the amount ' A ' in the mixture is
\((1\,{\rm{atm}} = 760\,\,{\rm{mm}}\,{\rm{Hg}})\)

319492 The determination of correct molecular weight from Raoult’s law is applicable to