QBManager

CHXII02:SOLUTIONS

319372 The mole fraction of helium in a saturated sodium at $20^{\circ} C$ is $1 .2 \times 1 0^{- 6}$ . The pressure of helium above the solution is, (Given Henry’s constant at $20^{\circ} C = 144 .97 k b a r$ ).

1 0.174 bar

2 1.95 bar

3 1.74 bar

4 1 bar

Explanation:

Given, $x_{H e} = 1 .2 \times 1 0^{- 6}$
$K_{H} = 144 .97 k b a r$
$= 144 .97 \times 1 0^{3} b a r$
According to Henry's law,
$p = K_{H} . x_{H e}$
$= 144 .97 \times 1 0^{3} \times 1 .2 \times 1 0^{- 6}$
$= 174 \times 1 0^{- 3} b a r$
$= 0 .174 b a r$

CHXII02:SOLUTIONS

319373 What is Henry's law constant if solubility of a gas in water at $298 K$ and 1 bar pressure is $7 \times 10^{- 4} {molL}^{- 1}$ ?

1

2.0 \times 10^{- 5} mol L^{- 1} {bar}^{- 1}

2

7.0 \times 10^{- 4} {molL}^{- 1} {bar}^{- 1}

3

3.5 \times 10^{- 3} {molL}^{- 1} {bar}^{- 1}

4

3.1 \times 10^{- 5} {molL}^{- 1} {bar}^{- 1}

Explanation:

$P = 1 bar, S = 7 \times 10^{- 4} mol L^{- 1}$
$K_{H} = \frac{S}{P} = \frac{7 \times 10^{- 4} mol L^{- 1}}{1 bar}$
$= 7 \times 10^{- 4} mol L^{- 1} ba r^{- 1}$

MHTCET - 2021

CHXII02:SOLUTIONS

319374 The relation between solubility of a gas in liquid at constant temperature and external pressure is stated by which law?

1 Raoult’s law

2 van’t Hoff-Boyle’s law

3 van’t Hoff-charles’ law

4 Henry’s law

Explanation:

The relationship between solubility of a gas in liquid at constant temperature and external pressure is given by Henry’s law. $X \propto$ Partial pressure of the gas, p
$p = K_{H} x$
Here, $K_{H} =$ Henry’s law constant
More the value of $K_{H}$ , lower is the solubility of gas.

MHTCET - 2016

CHXII02:SOLUTIONS

319375 Variation of $K_{H}$ (Henry’s law constant) with temperature T is shown by following graphs I - IV.
Correct representation is
supporting img

1 IV

2 III

3 I

4 II

Explanation:

Partial pressure, $p = K_{H} X$
If temperature is lowered, solubility of gases increases at a given pressure. Thus, $K_{H}$ increases with increase in temperature. It is due to this reason that aquatic species are more comfortable in cold water rather than in warm water.

CHXII02:SOLUTIONS

319372 The mole fraction of helium in a saturated sodium at $20^{\circ} C$ is $1 .2 \times 1 0^{- 6}$ . The pressure of helium above the solution is, (Given Henry’s constant at $20^{\circ} C = 144 .97 k b a r$ ).

1 0.174 bar

2 1.95 bar

3 1.74 bar

4 1 bar

Explanation:

Given, $x_{H e} = 1 .2 \times 1 0^{- 6}$
$K_{H} = 144 .97 k b a r$
$= 144 .97 \times 1 0^{3} b a r$
According to Henry's law,
$p = K_{H} . x_{H e}$
$= 144 .97 \times 1 0^{3} \times 1 .2 \times 1 0^{- 6}$
$= 174 \times 1 0^{- 3} b a r$
$= 0 .174 b a r$

CHXII02:SOLUTIONS

319373 What is Henry's law constant if solubility of a gas in water at $298 K$ and 1 bar pressure is $7 \times 10^{- 4} {molL}^{- 1}$ ?

1

2.0 \times 10^{- 5} mol L^{- 1} {bar}^{- 1}

2

7.0 \times 10^{- 4} {molL}^{- 1} {bar}^{- 1}

3

3.5 \times 10^{- 3} {molL}^{- 1} {bar}^{- 1}

4

3.1 \times 10^{- 5} {molL}^{- 1} {bar}^{- 1}

Explanation:

$P = 1 bar, S = 7 \times 10^{- 4} mol L^{- 1}$
$K_{H} = \frac{S}{P} = \frac{7 \times 10^{- 4} mol L^{- 1}}{1 bar}$
$= 7 \times 10^{- 4} mol L^{- 1} ba r^{- 1}$

MHTCET - 2021

CHXII02:SOLUTIONS

319374 The relation between solubility of a gas in liquid at constant temperature and external pressure is stated by which law?

1 Raoult’s law

2 van’t Hoff-Boyle’s law

3 van’t Hoff-charles’ law

4 Henry’s law

Explanation:

The relationship between solubility of a gas in liquid at constant temperature and external pressure is given by Henry’s law. $X \propto$ Partial pressure of the gas, p
$p = K_{H} x$
Here, $K_{H} =$ Henry’s law constant
More the value of $K_{H}$ , lower is the solubility of gas.

MHTCET - 2016

CHXII02:SOLUTIONS

319375 Variation of $K_{H}$ (Henry’s law constant) with temperature T is shown by following graphs I - IV.
Correct representation is
supporting img

1 IV

2 III

3 I

4 II

Explanation:

Partial pressure, $p = K_{H} X$
If temperature is lowered, solubility of gases increases at a given pressure. Thus, $K_{H}$ increases with increase in temperature. It is due to this reason that aquatic species are more comfortable in cold water rather than in warm water.

CHXII02:SOLUTIONS

319372 The mole fraction of helium in a saturated sodium at $20^{\circ} C$ is $1 .2 \times 1 0^{- 6}$ . The pressure of helium above the solution is, (Given Henry’s constant at $20^{\circ} C = 144 .97 k b a r$ ).

1 0.174 bar

2 1.95 bar

3 1.74 bar

4 1 bar

Explanation:

Given, $x_{H e} = 1 .2 \times 1 0^{- 6}$
$K_{H} = 144 .97 k b a r$
$= 144 .97 \times 1 0^{3} b a r$
According to Henry's law,
$p = K_{H} . x_{H e}$
$= 144 .97 \times 1 0^{3} \times 1 .2 \times 1 0^{- 6}$
$= 174 \times 1 0^{- 3} b a r$
$= 0 .174 b a r$

CHXII02:SOLUTIONS

319373 What is Henry's law constant if solubility of a gas in water at $298 K$ and 1 bar pressure is $7 \times 10^{- 4} {molL}^{- 1}$ ?

1

2.0 \times 10^{- 5} mol L^{- 1} {bar}^{- 1}

2

7.0 \times 10^{- 4} {molL}^{- 1} {bar}^{- 1}

3

3.5 \times 10^{- 3} {molL}^{- 1} {bar}^{- 1}

4

3.1 \times 10^{- 5} {molL}^{- 1} {bar}^{- 1}

Explanation:

$P = 1 bar, S = 7 \times 10^{- 4} mol L^{- 1}$
$K_{H} = \frac{S}{P} = \frac{7 \times 10^{- 4} mol L^{- 1}}{1 bar}$
$= 7 \times 10^{- 4} mol L^{- 1} ba r^{- 1}$

MHTCET - 2021

CHXII02:SOLUTIONS

319374 The relation between solubility of a gas in liquid at constant temperature and external pressure is stated by which law?

1 Raoult’s law

2 van’t Hoff-Boyle’s law

3 van’t Hoff-charles’ law

4 Henry’s law

Explanation:

The relationship between solubility of a gas in liquid at constant temperature and external pressure is given by Henry’s law. $X \propto$ Partial pressure of the gas, p
$p = K_{H} x$
Here, $K_{H} =$ Henry’s law constant
More the value of $K_{H}$ , lower is the solubility of gas.

MHTCET - 2016

CHXII02:SOLUTIONS

319375 Variation of $K_{H}$ (Henry’s law constant) with temperature T is shown by following graphs I - IV.
Correct representation is
supporting img

1 IV

2 III

3 I

4 II

Explanation:

Partial pressure, $p = K_{H} X$
If temperature is lowered, solubility of gases increases at a given pressure. Thus, $K_{H}$ increases with increase in temperature. It is due to this reason that aquatic species are more comfortable in cold water rather than in warm water.

CHXII02:SOLUTIONS

319372 The mole fraction of helium in a saturated sodium at $20^{\circ} C$ is $1 .2 \times 1 0^{- 6}$ . The pressure of helium above the solution is, (Given Henry’s constant at $20^{\circ} C = 144 .97 k b a r$ ).

1 0.174 bar

2 1.95 bar

3 1.74 bar

4 1 bar

Explanation:

Given, $x_{H e} = 1 .2 \times 1 0^{- 6}$
$K_{H} = 144 .97 k b a r$
$= 144 .97 \times 1 0^{3} b a r$
According to Henry's law,
$p = K_{H} . x_{H e}$
$= 144 .97 \times 1 0^{3} \times 1 .2 \times 1 0^{- 6}$
$= 174 \times 1 0^{- 3} b a r$
$= 0 .174 b a r$

CHXII02:SOLUTIONS

319373 What is Henry's law constant if solubility of a gas in water at $298 K$ and 1 bar pressure is $7 \times 10^{- 4} {molL}^{- 1}$ ?

1

2.0 \times 10^{- 5} mol L^{- 1} {bar}^{- 1}

2

7.0 \times 10^{- 4} {molL}^{- 1} {bar}^{- 1}

3

3.5 \times 10^{- 3} {molL}^{- 1} {bar}^{- 1}

4

3.1 \times 10^{- 5} {molL}^{- 1} {bar}^{- 1}

Explanation:

$P = 1 bar, S = 7 \times 10^{- 4} mol L^{- 1}$
$K_{H} = \frac{S}{P} = \frac{7 \times 10^{- 4} mol L^{- 1}}{1 bar}$
$= 7 \times 10^{- 4} mol L^{- 1} ba r^{- 1}$

MHTCET - 2021

CHXII02:SOLUTIONS

319374 The relation between solubility of a gas in liquid at constant temperature and external pressure is stated by which law?

1 Raoult’s law

2 van’t Hoff-Boyle’s law

3 van’t Hoff-charles’ law

4 Henry’s law

Explanation:

The relationship between solubility of a gas in liquid at constant temperature and external pressure is given by Henry’s law. $X \propto$ Partial pressure of the gas, p
$p = K_{H} x$
Here, $K_{H} =$ Henry’s law constant
More the value of $K_{H}$ , lower is the solubility of gas.

MHTCET - 2016

CHXII02:SOLUTIONS

319375 Variation of $K_{H}$ (Henry’s law constant) with temperature T is shown by following graphs I - IV.
Correct representation is
supporting img

1 IV

2 III

3 I

4 II

Explanation:

Partial pressure, $p = K_{H} X$
If temperature is lowered, solubility of gases increases at a given pressure. Thus, $K_{H}$ increases with increase in temperature. It is due to this reason that aquatic species are more comfortable in cold water rather than in warm water.