Relative Lowering of Vapour Pressure
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CHXII02:SOLUTIONS

319339 At a given temperature,
I. Vapour pressure of a solution containing non- volatile solute is proportional to mole fraction of solvent
II. Lowering of vapour pressure of solution containing non volatile solute is proportional to mole fraction of solute
III. Relative lowering of vapour pressure is equal to mole fraction of solute. The correct combination is

1 I
2 I, II
3 I, II, III
4 II, III
CHXII02:SOLUTIONS

319340 A 12 g of nonvolatile solute dissolved in 108 g of water produces the relative lowering vapour pressure 0.1. The molecular mass of the solute is

1 20
2 40
3 60
4 80
CHXII02:SOLUTIONS

319341 What is vapour pressure of solution containing 0.1 mole solute dissolved in \(1.8 \times 10^{-2} \mathrm{~kg} \mathrm{H}_{2} \mathrm{O}\) ? \(\left( {{\text{P}}_1^0 = 24\;{\text{mm Hg}}} \right)\)

1 \(12.40 {\text{mm Hg}}\)
2 \(18.12 {\text{mm Hg}}\)
3 \(15.72 {\text{mm Hg}}\)
4 \(21.84{\text{mm Hg}}\)
MHTCET - 2021
CHXII02:SOLUTIONS

319342 The vapour pressure curves of the same solute in the same solvent are shown. The curves are parallel to each other and do not intersect. The concentrations of solutions are in order of
supporting img

1 \({\rm{I < II < III}}\)
2 \(\mathrm{I}=\mathrm{II}=\mathrm{III}\)
3 \({\rm{I > }}\,{\rm{II > III}}\)
4 \({\rm{I > III > II}}\)
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CHXII02:SOLUTIONS

319339 At a given temperature,
I. Vapour pressure of a solution containing non- volatile solute is proportional to mole fraction of solvent
II. Lowering of vapour pressure of solution containing non volatile solute is proportional to mole fraction of solute
III. Relative lowering of vapour pressure is equal to mole fraction of solute. The correct combination is

1 I
2 I, II
3 I, II, III
4 II, III
CHXII02:SOLUTIONS

319340 A 12 g of nonvolatile solute dissolved in 108 g of water produces the relative lowering vapour pressure 0.1. The molecular mass of the solute is

1 20
2 40
3 60
4 80
CHXII02:SOLUTIONS

319341 What is vapour pressure of solution containing 0.1 mole solute dissolved in \(1.8 \times 10^{-2} \mathrm{~kg} \mathrm{H}_{2} \mathrm{O}\) ? \(\left( {{\text{P}}_1^0 = 24\;{\text{mm Hg}}} \right)\)

1 \(12.40 {\text{mm Hg}}\)
2 \(18.12 {\text{mm Hg}}\)
3 \(15.72 {\text{mm Hg}}\)
4 \(21.84{\text{mm Hg}}\)
MHTCET - 2021
CHXII02:SOLUTIONS

319342 The vapour pressure curves of the same solute in the same solvent are shown. The curves are parallel to each other and do not intersect. The concentrations of solutions are in order of
supporting img

1 \({\rm{I < II < III}}\)
2 \(\mathrm{I}=\mathrm{II}=\mathrm{III}\)
3 \({\rm{I > }}\,{\rm{II > III}}\)
4 \({\rm{I > III > II}}\)
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CHXII02:SOLUTIONS

319339 At a given temperature,
I. Vapour pressure of a solution containing non- volatile solute is proportional to mole fraction of solvent
II. Lowering of vapour pressure of solution containing non volatile solute is proportional to mole fraction of solute
III. Relative lowering of vapour pressure is equal to mole fraction of solute. The correct combination is

1 I
2 I, II
3 I, II, III
4 II, III
CHXII02:SOLUTIONS

319340 A 12 g of nonvolatile solute dissolved in 108 g of water produces the relative lowering vapour pressure 0.1. The molecular mass of the solute is

1 20
2 40
3 60
4 80
CHXII02:SOLUTIONS

319341 What is vapour pressure of solution containing 0.1 mole solute dissolved in \(1.8 \times 10^{-2} \mathrm{~kg} \mathrm{H}_{2} \mathrm{O}\) ? \(\left( {{\text{P}}_1^0 = 24\;{\text{mm Hg}}} \right)\)

1 \(12.40 {\text{mm Hg}}\)
2 \(18.12 {\text{mm Hg}}\)
3 \(15.72 {\text{mm Hg}}\)
4 \(21.84{\text{mm Hg}}\)
MHTCET - 2021
CHXII02:SOLUTIONS

319342 The vapour pressure curves of the same solute in the same solvent are shown. The curves are parallel to each other and do not intersect. The concentrations of solutions are in order of
supporting img

1 \({\rm{I < II < III}}\)
2 \(\mathrm{I}=\mathrm{II}=\mathrm{III}\)
3 \({\rm{I > }}\,{\rm{II > III}}\)
4 \({\rm{I > III > II}}\)
For More Updates join with Us
CHXII02:SOLUTIONS

319339 At a given temperature,
I. Vapour pressure of a solution containing non- volatile solute is proportional to mole fraction of solvent
II. Lowering of vapour pressure of solution containing non volatile solute is proportional to mole fraction of solute
III. Relative lowering of vapour pressure is equal to mole fraction of solute. The correct combination is

1 I
2 I, II
3 I, II, III
4 II, III
CHXII02:SOLUTIONS

319340 A 12 g of nonvolatile solute dissolved in 108 g of water produces the relative lowering vapour pressure 0.1. The molecular mass of the solute is

1 20
2 40
3 60
4 80
CHXII02:SOLUTIONS

319341 What is vapour pressure of solution containing 0.1 mole solute dissolved in \(1.8 \times 10^{-2} \mathrm{~kg} \mathrm{H}_{2} \mathrm{O}\) ? \(\left( {{\text{P}}_1^0 = 24\;{\text{mm Hg}}} \right)\)

1 \(12.40 {\text{mm Hg}}\)
2 \(18.12 {\text{mm Hg}}\)
3 \(15.72 {\text{mm Hg}}\)
4 \(21.84{\text{mm Hg}}\)
MHTCET - 2021
CHXII02:SOLUTIONS

319342 The vapour pressure curves of the same solute in the same solvent are shown. The curves are parallel to each other and do not intersect. The concentrations of solutions are in order of
supporting img

1 \({\rm{I < II < III}}\)
2 \(\mathrm{I}=\mathrm{II}=\mathrm{III}\)
3 \({\rm{I > }}\,{\rm{II > III}}\)
4 \({\rm{I > III > II}}\)