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CHXII02:SOLUTIONS

319249 Which statement is incorrect about osmotic pressure $(π)$ , volume(V) & temperature(T)?

1

π α \frac{1}{V}

, if T is constant.

2

π α T

, if V is constant.

3

π α V

, if T is constant.

4

π V

, is constant, if T is constant

Explanation:

$π V = n S T$

CHXII02:SOLUTIONS

319250 Equal volumes of $M / 20$ urea solution and $M / 20$ glucose solution are mixed. The mixture will have osmotic pressure

1 equal to either of the solution

2 less than either of the solution

3 higher than either of the solution

4 zero

Explanation:

Molarity of resulting solution,
$M_{R} = \frac{\frac{M}{20} \times V + \frac{M}{20} \times V}{2 V} = \frac{M}{20}$
As urea, glucose and the mixture have same molarities the mixture O.P. is equal to either of solution.

CHXII02:SOLUTIONS

319251 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
If red blood cells were removed from the body and placed in pure water, pressure inside the cells increases.
Statement B :
The concentration of salt content in the cell increases.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

CHXII02:SOLUTIONS

319252 A solution is made by dissolving $20 g$ of a substance in $500 ml$ of water. Its osmotic pressure was found to be $600 mm$ of $Hg$ at $15^{\circ} C$ . The molecular weight of the
substance is

1

1198 g {mol}^{- 1}

2

500 g {mol}^{- 1}

3

599 g {mol}^{- 1}

4

1000 g {mol}^{- 1}

Explanation:

$π = CRT$ (or)
$M = \frac{W_{B} RT}{π V}$
$= \frac{20 \times 0.0821 \times 288 \times 1000}{(600 / 760) \times 500} = 1198 g {mol}^{- 1}$

CHXII02:SOLUTIONS

319249 Which statement is incorrect about osmotic pressure $(π)$ , volume(V) & temperature(T)?

1

π α \frac{1}{V}

, if T is constant.

2

π α T

, if V is constant.

3

π α V

, if T is constant.

4

π V

, is constant, if T is constant

Explanation:

$π V = n S T$

CHXII02:SOLUTIONS

319250 Equal volumes of $M / 20$ urea solution and $M / 20$ glucose solution are mixed. The mixture will have osmotic pressure

1 equal to either of the solution

2 less than either of the solution

3 higher than either of the solution

4 zero

Explanation:

Molarity of resulting solution,
$M_{R} = \frac{\frac{M}{20} \times V + \frac{M}{20} \times V}{2 V} = \frac{M}{20}$
As urea, glucose and the mixture have same molarities the mixture O.P. is equal to either of solution.

CHXII02:SOLUTIONS

319251 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
If red blood cells were removed from the body and placed in pure water, pressure inside the cells increases.
Statement B :
The concentration of salt content in the cell increases.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

CHXII02:SOLUTIONS

319252 A solution is made by dissolving $20 g$ of a substance in $500 ml$ of water. Its osmotic pressure was found to be $600 mm$ of $Hg$ at $15^{\circ} C$ . The molecular weight of the
substance is

1

1198 g {mol}^{- 1}

2

500 g {mol}^{- 1}

3

599 g {mol}^{- 1}

4

1000 g {mol}^{- 1}

Explanation:

$π = CRT$ (or)
$M = \frac{W_{B} RT}{π V}$
$= \frac{20 \times 0.0821 \times 288 \times 1000}{(600 / 760) \times 500} = 1198 g {mol}^{- 1}$

CHXII02:SOLUTIONS

319249 Which statement is incorrect about osmotic pressure $(π)$ , volume(V) & temperature(T)?

1

π α \frac{1}{V}

, if T is constant.

2

π α T

, if V is constant.

3

π α V

, if T is constant.

4

π V

, is constant, if T is constant

Explanation:

$π V = n S T$

CHXII02:SOLUTIONS

319250 Equal volumes of $M / 20$ urea solution and $M / 20$ glucose solution are mixed. The mixture will have osmotic pressure

1 equal to either of the solution

2 less than either of the solution

3 higher than either of the solution

4 zero

Explanation:

Molarity of resulting solution,
$M_{R} = \frac{\frac{M}{20} \times V + \frac{M}{20} \times V}{2 V} = \frac{M}{20}$
As urea, glucose and the mixture have same molarities the mixture O.P. is equal to either of solution.

CHXII02:SOLUTIONS

319251 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
If red blood cells were removed from the body and placed in pure water, pressure inside the cells increases.
Statement B :
The concentration of salt content in the cell increases.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

CHXII02:SOLUTIONS

319252 A solution is made by dissolving $20 g$ of a substance in $500 ml$ of water. Its osmotic pressure was found to be $600 mm$ of $Hg$ at $15^{\circ} C$ . The molecular weight of the
substance is

1

1198 g {mol}^{- 1}

2

500 g {mol}^{- 1}

3

599 g {mol}^{- 1}

4

1000 g {mol}^{- 1}

Explanation:

$π = CRT$ (or)
$M = \frac{W_{B} RT}{π V}$
$= \frac{20 \times 0.0821 \times 288 \times 1000}{(600 / 760) \times 500} = 1198 g {mol}^{- 1}$

CHXII02:SOLUTIONS

319249 Which statement is incorrect about osmotic pressure $(π)$ , volume(V) & temperature(T)?

1

π α \frac{1}{V}

, if T is constant.

2

π α T

, if V is constant.

3

π α V

, if T is constant.

4

π V

, is constant, if T is constant

Explanation:

$π V = n S T$

CHXII02:SOLUTIONS

319250 Equal volumes of $M / 20$ urea solution and $M / 20$ glucose solution are mixed. The mixture will have osmotic pressure

1 equal to either of the solution

2 less than either of the solution

3 higher than either of the solution

4 zero

Explanation:

Molarity of resulting solution,
$M_{R} = \frac{\frac{M}{20} \times V + \frac{M}{20} \times V}{2 V} = \frac{M}{20}$
As urea, glucose and the mixture have same molarities the mixture O.P. is equal to either of solution.

CHXII02:SOLUTIONS

319251 Read the Statement - A and Statement - B carefully to mark the correct options given below:
Statement A :
If red blood cells were removed from the body and placed in pure water, pressure inside the cells increases.
Statement B :
The concentration of salt content in the cell increases.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

CHXII02:SOLUTIONS

319252 A solution is made by dissolving $20 g$ of a substance in $500 ml$ of water. Its osmotic pressure was found to be $600 mm$ of $Hg$ at $15^{\circ} C$ . The molecular weight of the
substance is

1

1198 g {mol}^{- 1}

2

500 g {mol}^{- 1}

3

599 g {mol}^{- 1}

4

1000 g {mol}^{- 1}

Explanation:

$π = CRT$ (or)
$M = \frac{W_{B} RT}{π V}$
$= \frac{20 \times 0.0821 \times 288 \times 1000}{(600 / 760) \times 500} = 1198 g {mol}^{- 1}$