318241
Read the Statement - A and Statement - B carefully to mark the correct options given below Statement A : Nitration of benzene involves the following step
Statement B : Use of Lewis base promotes the electrophilic substitution of benzene.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Lewis acid promotes the electrophilic substitution of benzene not Lewis base. So, the correct option is (1).
JEE Main - 2024
CHXI13:HYDROCARBONS
318242
Acylation of benzene to produce aliphatic aromatic ketone is known as
1 Benzoin condensation
2 Hydroformylation
3 Clemmensen reduction
4 Friedel-Craft's reaction
Explanation:
This reaction is known as Friedel craft's reaction.
CHXI13:HYDROCARBONS
318243
Assertion : Benzene reacts with iodine monochloride in presence of anhyd. \(\mathrm{AlCl}_{3}\) to form iodobenzene. Reason : Iodine monochloride reacts with anhyd \(\mathrm{AlCl}_{3}\) to produce \(\mathrm{I}^{+}\)which attacks the benzene ring.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Benzene reacts with iodine monochloride in presence of anhyd. \(\mathrm{AlCl}_{3}\) to form iodobenzene. It is an electrophilic substitution reaction. Iodine monochloride reacts with anhyd. \(\mathrm{AlCl}_{3}\) to produce \(\mathrm{I}^{+}\)which acts as electrophile and attacks the benzene ring. Anhyd. \(\mathrm{AlCl}_{3}\) acts as a catalyst. \(\begin{aligned}& \mathrm{AlCl}_{3}+\mathrm{ICl} \rightarrow \mathrm{I}^{+}+\mathrm{AlCl}_{4}^{-} \\& \mathrm{C}_{6} \mathrm{H}_{6}+\mathrm{I}^{+} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{I}+\mathrm{H}^{+} \\& \mathrm{H}^{+}+\mathrm{AlCl}_{4}^{\Theta} \rightarrow \mathrm{AlCl}_{3}+\mathrm{HCl}\end{aligned}\) So, option (1) is correct.
CHXI13:HYDROCARBONS
318244
During monoalkylation of benzene with \(\mathrm{CH}_{3} \mathrm{Cl}\) in presence of anhydrous \(\mathrm{AlCl}_{3}\), an excess of \(\mathrm{C}_{6} \mathrm{H}_{6}\) must be used because this will
1 increase the chance for collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\)
2 decrease collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3}\)
3 both (1) and (2)
4 decrease the chance for collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI13:HYDROCARBONS
318241
Read the Statement - A and Statement - B carefully to mark the correct options given below Statement A : Nitration of benzene involves the following step
Statement B : Use of Lewis base promotes the electrophilic substitution of benzene.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Lewis acid promotes the electrophilic substitution of benzene not Lewis base. So, the correct option is (1).
JEE Main - 2024
CHXI13:HYDROCARBONS
318242
Acylation of benzene to produce aliphatic aromatic ketone is known as
1 Benzoin condensation
2 Hydroformylation
3 Clemmensen reduction
4 Friedel-Craft's reaction
Explanation:
This reaction is known as Friedel craft's reaction.
CHXI13:HYDROCARBONS
318243
Assertion : Benzene reacts with iodine monochloride in presence of anhyd. \(\mathrm{AlCl}_{3}\) to form iodobenzene. Reason : Iodine monochloride reacts with anhyd \(\mathrm{AlCl}_{3}\) to produce \(\mathrm{I}^{+}\)which attacks the benzene ring.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Benzene reacts with iodine monochloride in presence of anhyd. \(\mathrm{AlCl}_{3}\) to form iodobenzene. It is an electrophilic substitution reaction. Iodine monochloride reacts with anhyd. \(\mathrm{AlCl}_{3}\) to produce \(\mathrm{I}^{+}\)which acts as electrophile and attacks the benzene ring. Anhyd. \(\mathrm{AlCl}_{3}\) acts as a catalyst. \(\begin{aligned}& \mathrm{AlCl}_{3}+\mathrm{ICl} \rightarrow \mathrm{I}^{+}+\mathrm{AlCl}_{4}^{-} \\& \mathrm{C}_{6} \mathrm{H}_{6}+\mathrm{I}^{+} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{I}+\mathrm{H}^{+} \\& \mathrm{H}^{+}+\mathrm{AlCl}_{4}^{\Theta} \rightarrow \mathrm{AlCl}_{3}+\mathrm{HCl}\end{aligned}\) So, option (1) is correct.
CHXI13:HYDROCARBONS
318244
During monoalkylation of benzene with \(\mathrm{CH}_{3} \mathrm{Cl}\) in presence of anhydrous \(\mathrm{AlCl}_{3}\), an excess of \(\mathrm{C}_{6} \mathrm{H}_{6}\) must be used because this will
1 increase the chance for collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\)
2 decrease collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3}\)
3 both (1) and (2)
4 decrease the chance for collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\)
318241
Read the Statement - A and Statement - B carefully to mark the correct options given below Statement A : Nitration of benzene involves the following step
Statement B : Use of Lewis base promotes the electrophilic substitution of benzene.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Lewis acid promotes the electrophilic substitution of benzene not Lewis base. So, the correct option is (1).
JEE Main - 2024
CHXI13:HYDROCARBONS
318242
Acylation of benzene to produce aliphatic aromatic ketone is known as
1 Benzoin condensation
2 Hydroformylation
3 Clemmensen reduction
4 Friedel-Craft's reaction
Explanation:
This reaction is known as Friedel craft's reaction.
CHXI13:HYDROCARBONS
318243
Assertion : Benzene reacts with iodine monochloride in presence of anhyd. \(\mathrm{AlCl}_{3}\) to form iodobenzene. Reason : Iodine monochloride reacts with anhyd \(\mathrm{AlCl}_{3}\) to produce \(\mathrm{I}^{+}\)which attacks the benzene ring.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Benzene reacts with iodine monochloride in presence of anhyd. \(\mathrm{AlCl}_{3}\) to form iodobenzene. It is an electrophilic substitution reaction. Iodine monochloride reacts with anhyd. \(\mathrm{AlCl}_{3}\) to produce \(\mathrm{I}^{+}\)which acts as electrophile and attacks the benzene ring. Anhyd. \(\mathrm{AlCl}_{3}\) acts as a catalyst. \(\begin{aligned}& \mathrm{AlCl}_{3}+\mathrm{ICl} \rightarrow \mathrm{I}^{+}+\mathrm{AlCl}_{4}^{-} \\& \mathrm{C}_{6} \mathrm{H}_{6}+\mathrm{I}^{+} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{I}+\mathrm{H}^{+} \\& \mathrm{H}^{+}+\mathrm{AlCl}_{4}^{\Theta} \rightarrow \mathrm{AlCl}_{3}+\mathrm{HCl}\end{aligned}\) So, option (1) is correct.
CHXI13:HYDROCARBONS
318244
During monoalkylation of benzene with \(\mathrm{CH}_{3} \mathrm{Cl}\) in presence of anhydrous \(\mathrm{AlCl}_{3}\), an excess of \(\mathrm{C}_{6} \mathrm{H}_{6}\) must be used because this will
1 increase the chance for collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\)
2 decrease collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3}\)
3 both (1) and (2)
4 decrease the chance for collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\)
318241
Read the Statement - A and Statement - B carefully to mark the correct options given below Statement A : Nitration of benzene involves the following step
Statement B : Use of Lewis base promotes the electrophilic substitution of benzene.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Lewis acid promotes the electrophilic substitution of benzene not Lewis base. So, the correct option is (1).
JEE Main - 2024
CHXI13:HYDROCARBONS
318242
Acylation of benzene to produce aliphatic aromatic ketone is known as
1 Benzoin condensation
2 Hydroformylation
3 Clemmensen reduction
4 Friedel-Craft's reaction
Explanation:
This reaction is known as Friedel craft's reaction.
CHXI13:HYDROCARBONS
318243
Assertion : Benzene reacts with iodine monochloride in presence of anhyd. \(\mathrm{AlCl}_{3}\) to form iodobenzene. Reason : Iodine monochloride reacts with anhyd \(\mathrm{AlCl}_{3}\) to produce \(\mathrm{I}^{+}\)which attacks the benzene ring.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Benzene reacts with iodine monochloride in presence of anhyd. \(\mathrm{AlCl}_{3}\) to form iodobenzene. It is an electrophilic substitution reaction. Iodine monochloride reacts with anhyd. \(\mathrm{AlCl}_{3}\) to produce \(\mathrm{I}^{+}\)which acts as electrophile and attacks the benzene ring. Anhyd. \(\mathrm{AlCl}_{3}\) acts as a catalyst. \(\begin{aligned}& \mathrm{AlCl}_{3}+\mathrm{ICl} \rightarrow \mathrm{I}^{+}+\mathrm{AlCl}_{4}^{-} \\& \mathrm{C}_{6} \mathrm{H}_{6}+\mathrm{I}^{+} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{I}+\mathrm{H}^{+} \\& \mathrm{H}^{+}+\mathrm{AlCl}_{4}^{\Theta} \rightarrow \mathrm{AlCl}_{3}+\mathrm{HCl}\end{aligned}\) So, option (1) is correct.
CHXI13:HYDROCARBONS
318244
During monoalkylation of benzene with \(\mathrm{CH}_{3} \mathrm{Cl}\) in presence of anhydrous \(\mathrm{AlCl}_{3}\), an excess of \(\mathrm{C}_{6} \mathrm{H}_{6}\) must be used because this will
1 increase the chance for collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\)
2 decrease collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3}\)
3 both (1) and (2)
4 decrease the chance for collision between \(\mathrm{CH}_{3}^{+}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\)
