Explanation:

Since, the alkene on oxidation gives only acetic acid, therefore, the alkene must be symmetrical containing two carbon-atoms on either side of the double bond, i.e. 2-butene.

Explanation:

\({\text{C}}{{\text{H}}_{\text{3}}}{\text{CH = CHC}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\xrightarrow[{{\text{MnO}}_{\text{4}}^\Theta }]{{{\text{ warm conc}}{\text{. }}}}\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{CO}}{{\text{O}}^\Theta }}\limits_{{\text{Acetate}}} \)
\({\text{ + }}\mathop {{\text{ C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{CO}}{{\text{O}}^\Theta }}\limits_{{\text{Butanoate}}} \)

Explanation:

Explanation:

The terminal \(\mathrm{CH}_{2}\) group \(\left(=\mathrm{CH}_{2}\right)\) is completely oxidised to \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\); a monosubstituted atom of a double bond is converted to aldehyde which is further oxidised to carboxylic acid, and the disubstituted atom of a double bond is oxidised to ketone.

Explanation:

Since, the alkene on oxidation gives only acetic acid, therefore, the alkene must be symmetrical containing two carbon-atoms on either side of the double bond, i.e. 2-butene.

Explanation:

\({\text{C}}{{\text{H}}_{\text{3}}}{\text{CH = CHC}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\xrightarrow[{{\text{MnO}}_{\text{4}}^\Theta }]{{{\text{ warm conc}}{\text{. }}}}\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{CO}}{{\text{O}}^\Theta }}\limits_{{\text{Acetate}}} \)
\({\text{ + }}\mathop {{\text{ C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{CO}}{{\text{O}}^\Theta }}\limits_{{\text{Butanoate}}} \)

Explanation:

Explanation:

The terminal \(\mathrm{CH}_{2}\) group \(\left(=\mathrm{CH}_{2}\right)\) is completely oxidised to \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\); a monosubstituted atom of a double bond is converted to aldehyde which is further oxidised to carboxylic acid, and the disubstituted atom of a double bond is oxidised to ketone.

Explanation:

Since, the alkene on oxidation gives only acetic acid, therefore, the alkene must be symmetrical containing two carbon-atoms on either side of the double bond, i.e. 2-butene.

Explanation:

\({\text{C}}{{\text{H}}_{\text{3}}}{\text{CH = CHC}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\xrightarrow[{{\text{MnO}}_{\text{4}}^\Theta }]{{{\text{ warm conc}}{\text{. }}}}\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{CO}}{{\text{O}}^\Theta }}\limits_{{\text{Acetate}}} \)
\({\text{ + }}\mathop {{\text{ C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{CO}}{{\text{O}}^\Theta }}\limits_{{\text{Butanoate}}} \)

Explanation:

Explanation:

The terminal \(\mathrm{CH}_{2}\) group \(\left(=\mathrm{CH}_{2}\right)\) is completely oxidised to \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\); a monosubstituted atom of a double bond is converted to aldehyde which is further oxidised to carboxylic acid, and the disubstituted atom of a double bond is oxidised to ketone.

Explanation:

Since, the alkene on oxidation gives only acetic acid, therefore, the alkene must be symmetrical containing two carbon-atoms on either side of the double bond, i.e. 2-butene.

Explanation:

\({\text{C}}{{\text{H}}_{\text{3}}}{\text{CH = CHC}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\xrightarrow[{{\text{MnO}}_{\text{4}}^\Theta }]{{{\text{ warm conc}}{\text{. }}}}\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{CO}}{{\text{O}}^\Theta }}\limits_{{\text{Acetate}}} \)
\({\text{ + }}\mathop {{\text{ C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{CO}}{{\text{O}}^\Theta }}\limits_{{\text{Butanoate}}} \)

Explanation:

Explanation:

The terminal \(\mathrm{CH}_{2}\) group \(\left(=\mathrm{CH}_{2}\right)\) is completely oxidised to \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\); a monosubstituted atom of a double bond is converted to aldehyde which is further oxidised to carboxylic acid, and the disubstituted atom of a double bond is oxidised to ketone.