NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI13:HYDROCARBONS
318025
Propene when treated with cold conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) forms a compound which on heating with water gives
1 propan-2-ol
2 butan-1-ol
3 ethanol
4 propan-1-ol
Explanation:
Propene when treated with cold \({\text{conc}}{\text{. }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\) forms a compound, isopropyl-hydrogen sulphate on heating with water gives propan-2ol.
CHXI13:HYDROCARBONS
318027
Addition of \(\mathrm{HI}\) on double bond of propene yields isopropyl iodide as the major product, because addition proceeds through
1 A more stable carbocation
2 A more stable carbanion
3 A more stable free radical
4 A more stable carbene
Explanation:
CHXI13:HYDROCARBONS
318028
The major product obtained in the following reaction is
1 4-Iodo -4-methylhexane
2 4-Iodo-3-methylhexane
3 3-Iodo-3-methylhexane
4 3- Iodo -4-methylhexane
Explanation:
Peroxide has effect only on \(\mathrm{HBr}\) not on \(\mathrm{HCl}\), HI. It is Markovnikov addition of HI.
MHTCET - 2021
CHXI13:HYDROCARBONS
318029
\(\alpha - \) butylene when subjected to hydroboration oxidation reaction, yeilds
1 iso-butyl alcohol
2 sec-butyl alcohol
3 n-butyl alcohol
4 tert-butyl alcohol
Explanation:
\(\alpha \) butyelene When subjected to hydrocarbotion oxidation reaction,yeilds n- butyl alcohol .The reaction is as follows:
318025
Propene when treated with cold conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) forms a compound which on heating with water gives
1 propan-2-ol
2 butan-1-ol
3 ethanol
4 propan-1-ol
Explanation:
Propene when treated with cold \({\text{conc}}{\text{. }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\) forms a compound, isopropyl-hydrogen sulphate on heating with water gives propan-2ol.
CHXI13:HYDROCARBONS
318027
Addition of \(\mathrm{HI}\) on double bond of propene yields isopropyl iodide as the major product, because addition proceeds through
1 A more stable carbocation
2 A more stable carbanion
3 A more stable free radical
4 A more stable carbene
Explanation:
CHXI13:HYDROCARBONS
318028
The major product obtained in the following reaction is
1 4-Iodo -4-methylhexane
2 4-Iodo-3-methylhexane
3 3-Iodo-3-methylhexane
4 3- Iodo -4-methylhexane
Explanation:
Peroxide has effect only on \(\mathrm{HBr}\) not on \(\mathrm{HCl}\), HI. It is Markovnikov addition of HI.
MHTCET - 2021
CHXI13:HYDROCARBONS
318029
\(\alpha - \) butylene when subjected to hydroboration oxidation reaction, yeilds
1 iso-butyl alcohol
2 sec-butyl alcohol
3 n-butyl alcohol
4 tert-butyl alcohol
Explanation:
\(\alpha \) butyelene When subjected to hydrocarbotion oxidation reaction,yeilds n- butyl alcohol .The reaction is as follows:
318025
Propene when treated with cold conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) forms a compound which on heating with water gives
1 propan-2-ol
2 butan-1-ol
3 ethanol
4 propan-1-ol
Explanation:
Propene when treated with cold \({\text{conc}}{\text{. }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\) forms a compound, isopropyl-hydrogen sulphate on heating with water gives propan-2ol.
CHXI13:HYDROCARBONS
318027
Addition of \(\mathrm{HI}\) on double bond of propene yields isopropyl iodide as the major product, because addition proceeds through
1 A more stable carbocation
2 A more stable carbanion
3 A more stable free radical
4 A more stable carbene
Explanation:
CHXI13:HYDROCARBONS
318028
The major product obtained in the following reaction is
1 4-Iodo -4-methylhexane
2 4-Iodo-3-methylhexane
3 3-Iodo-3-methylhexane
4 3- Iodo -4-methylhexane
Explanation:
Peroxide has effect only on \(\mathrm{HBr}\) not on \(\mathrm{HCl}\), HI. It is Markovnikov addition of HI.
MHTCET - 2021
CHXI13:HYDROCARBONS
318029
\(\alpha - \) butylene when subjected to hydroboration oxidation reaction, yeilds
1 iso-butyl alcohol
2 sec-butyl alcohol
3 n-butyl alcohol
4 tert-butyl alcohol
Explanation:
\(\alpha \) butyelene When subjected to hydrocarbotion oxidation reaction,yeilds n- butyl alcohol .The reaction is as follows:
318025
Propene when treated with cold conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) forms a compound which on heating with water gives
1 propan-2-ol
2 butan-1-ol
3 ethanol
4 propan-1-ol
Explanation:
Propene when treated with cold \({\text{conc}}{\text{. }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\) forms a compound, isopropyl-hydrogen sulphate on heating with water gives propan-2ol.
CHXI13:HYDROCARBONS
318027
Addition of \(\mathrm{HI}\) on double bond of propene yields isopropyl iodide as the major product, because addition proceeds through
1 A more stable carbocation
2 A more stable carbanion
3 A more stable free radical
4 A more stable carbene
Explanation:
CHXI13:HYDROCARBONS
318028
The major product obtained in the following reaction is
1 4-Iodo -4-methylhexane
2 4-Iodo-3-methylhexane
3 3-Iodo-3-methylhexane
4 3- Iodo -4-methylhexane
Explanation:
Peroxide has effect only on \(\mathrm{HBr}\) not on \(\mathrm{HCl}\), HI. It is Markovnikov addition of HI.
MHTCET - 2021
CHXI13:HYDROCARBONS
318029
\(\alpha - \) butylene when subjected to hydroboration oxidation reaction, yeilds
1 iso-butyl alcohol
2 sec-butyl alcohol
3 n-butyl alcohol
4 tert-butyl alcohol
Explanation:
\(\alpha \) butyelene When subjected to hydrocarbotion oxidation reaction,yeilds n- butyl alcohol .The reaction is as follows:
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