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CHXI11:THE P-BLOCK ELEMENTS

317011 Bromine water reacts with ${SO}_{2}$ to form

1

HBr

and

S

2

H_{2} O

and

HBr

3

S

and

H_{2} O

4

H_{2} {SO}_{4}

and

HBr

Explanation:

When bromine water reacts with ${SO}_{2}$ , it oxidises ${SO}_{2}$ to sulphuric acid and itself gets reduced to $HBr$ .
supporting img

CHXI11:THE P-BLOCK ELEMENTS

317012 On passing ${SO}_{2}$ gas through cupric chloride solution

1 The solution becomes colourless only

2 The solution becomes colourless first and later a white ppt. of

{Cu}_{2} {Cl}_{2}

is formed.

3 No visible change takes place.

4 A white ppt. is not obtained.

Explanation:

${CuCl}_{2} + 2 H_{2} O + {SO}_{2}$
${Cu}_{2} {Cl}_{2} + 2 HCl + H_{2}$

CHXI11:THE P-BLOCK ELEMENTS

317013 How many of the following statements are CORRECT?
i. ${SO}_{2}$ is produced by the action of hydrochloric acid on ${Na}_{2} {SO}_{3}$ .
ii. ${SO}_{2}$ is ${sp}^{2}$ hybridized.
iii. ${SO}_{2}$ has two $p π - p π$ bonds.
iv. ${SO}_{2}$ and ${CS}_{2}$ are isostructural.

1 1

2 2

3 3

4 4

Explanation:

Statements (i) and (ii) are correct. ${SO}_{2}$ has two $π$ bonds; one is $p π - p π$ and the other is $d π - p π$ . ${SO}_{2}$ and ${CS}_{2}$ are not isostructural. ${SO}_{2}$ is bent while ${CS}_{2}$ is linear.

CHXI11:THE P-BLOCK ELEMENTS

317014 Which of the following reaction cannot change ${SO}_{2} \to {SO}_{4}^{2 -} ?$

1

{SO}_{2} + {MnO}_{4}^{-} \overset{H^{+}}{\to}

2

{SO}_{2} + {Cr}_{2} O_{7}^{2 -} \overset{H^{+}}{\to}

3

{SO}_{2} + {Fe}^{3 +} \overset{H^{+}}{\to}

4

{SO}_{2} + Ba (OH)_{2} \to

Explanation:

$2 {MnO}_{4}^{-} + 5 {SO}_{2} + 2 H_{2} O ⟶$
$2 M n^{2 +} + 5 {S O}_{4}^{2 -} + 4 H^{+}$
$C r_{2} O_{7}^{2 -} + 3 S O_{2} + 2 H^{+} \to$
$2 C r^{3 +} + 3 {S O}_{4}^{2 -} + H_{2} O$
$2 F e^{3 +} + S O_{2} + 2 H_{2} O \to$
$2 F e^{2 +} + 4 H^{+} + {S O}_{4}^{2 -}$
$S O_{2} + Ba {(OH)}_{2} \to BaS O_{3} + H_{2} O$
So, $Ba ({OH}_{2})$ cannot oxidise ${SO}_{2}$ to ${SO}_{4}^{- 2}$

CHXI11:THE P-BLOCK ELEMENTS

317011 Bromine water reacts with ${SO}_{2}$ to form

1

HBr

and

S

2

H_{2} O

and

HBr

3

S

and

H_{2} O

4

H_{2} {SO}_{4}

and

HBr

Explanation:

When bromine water reacts with ${SO}_{2}$ , it oxidises ${SO}_{2}$ to sulphuric acid and itself gets reduced to $HBr$ .
supporting img

CHXI11:THE P-BLOCK ELEMENTS

317012 On passing ${SO}_{2}$ gas through cupric chloride solution

1 The solution becomes colourless only

2 The solution becomes colourless first and later a white ppt. of

{Cu}_{2} {Cl}_{2}

is formed.

3 No visible change takes place.

4 A white ppt. is not obtained.

Explanation:

${CuCl}_{2} + 2 H_{2} O + {SO}_{2}$
${Cu}_{2} {Cl}_{2} + 2 HCl + H_{2}$

CHXI11:THE P-BLOCK ELEMENTS

317013 How many of the following statements are CORRECT?
i. ${SO}_{2}$ is produced by the action of hydrochloric acid on ${Na}_{2} {SO}_{3}$ .
ii. ${SO}_{2}$ is ${sp}^{2}$ hybridized.
iii. ${SO}_{2}$ has two $p π - p π$ bonds.
iv. ${SO}_{2}$ and ${CS}_{2}$ are isostructural.

1 1

2 2

3 3

4 4

Explanation:

Statements (i) and (ii) are correct. ${SO}_{2}$ has two $π$ bonds; one is $p π - p π$ and the other is $d π - p π$ . ${SO}_{2}$ and ${CS}_{2}$ are not isostructural. ${SO}_{2}$ is bent while ${CS}_{2}$ is linear.

CHXI11:THE P-BLOCK ELEMENTS

317014 Which of the following reaction cannot change ${SO}_{2} \to {SO}_{4}^{2 -} ?$

1

{SO}_{2} + {MnO}_{4}^{-} \overset{H^{+}}{\to}

2

{SO}_{2} + {Cr}_{2} O_{7}^{2 -} \overset{H^{+}}{\to}

3

{SO}_{2} + {Fe}^{3 +} \overset{H^{+}}{\to}

4

{SO}_{2} + Ba (OH)_{2} \to

Explanation:

$2 {MnO}_{4}^{-} + 5 {SO}_{2} + 2 H_{2} O ⟶$
$2 M n^{2 +} + 5 {S O}_{4}^{2 -} + 4 H^{+}$
$C r_{2} O_{7}^{2 -} + 3 S O_{2} + 2 H^{+} \to$
$2 C r^{3 +} + 3 {S O}_{4}^{2 -} + H_{2} O$
$2 F e^{3 +} + S O_{2} + 2 H_{2} O \to$
$2 F e^{2 +} + 4 H^{+} + {S O}_{4}^{2 -}$
$S O_{2} + Ba {(OH)}_{2} \to BaS O_{3} + H_{2} O$
So, $Ba ({OH}_{2})$ cannot oxidise ${SO}_{2}$ to ${SO}_{4}^{- 2}$

CHXI11:THE P-BLOCK ELEMENTS

317011 Bromine water reacts with ${SO}_{2}$ to form

1

HBr

and

S

2

H_{2} O

and

HBr

3

S

and

H_{2} O

4

H_{2} {SO}_{4}

and

HBr

Explanation:

When bromine water reacts with ${SO}_{2}$ , it oxidises ${SO}_{2}$ to sulphuric acid and itself gets reduced to $HBr$ .
supporting img

CHXI11:THE P-BLOCK ELEMENTS

317012 On passing ${SO}_{2}$ gas through cupric chloride solution

1 The solution becomes colourless only

2 The solution becomes colourless first and later a white ppt. of

{Cu}_{2} {Cl}_{2}

is formed.

3 No visible change takes place.

4 A white ppt. is not obtained.

Explanation:

${CuCl}_{2} + 2 H_{2} O + {SO}_{2}$
${Cu}_{2} {Cl}_{2} + 2 HCl + H_{2}$

CHXI11:THE P-BLOCK ELEMENTS

317013 How many of the following statements are CORRECT?
i. ${SO}_{2}$ is produced by the action of hydrochloric acid on ${Na}_{2} {SO}_{3}$ .
ii. ${SO}_{2}$ is ${sp}^{2}$ hybridized.
iii. ${SO}_{2}$ has two $p π - p π$ bonds.
iv. ${SO}_{2}$ and ${CS}_{2}$ are isostructural.

1 1

2 2

3 3

4 4

Explanation:

Statements (i) and (ii) are correct. ${SO}_{2}$ has two $π$ bonds; one is $p π - p π$ and the other is $d π - p π$ . ${SO}_{2}$ and ${CS}_{2}$ are not isostructural. ${SO}_{2}$ is bent while ${CS}_{2}$ is linear.

CHXI11:THE P-BLOCK ELEMENTS

317014 Which of the following reaction cannot change ${SO}_{2} \to {SO}_{4}^{2 -} ?$

1

{SO}_{2} + {MnO}_{4}^{-} \overset{H^{+}}{\to}

2

{SO}_{2} + {Cr}_{2} O_{7}^{2 -} \overset{H^{+}}{\to}

3

{SO}_{2} + {Fe}^{3 +} \overset{H^{+}}{\to}

4

{SO}_{2} + Ba (OH)_{2} \to

Explanation:

$2 {MnO}_{4}^{-} + 5 {SO}_{2} + 2 H_{2} O ⟶$
$2 M n^{2 +} + 5 {S O}_{4}^{2 -} + 4 H^{+}$
$C r_{2} O_{7}^{2 -} + 3 S O_{2} + 2 H^{+} \to$
$2 C r^{3 +} + 3 {S O}_{4}^{2 -} + H_{2} O$
$2 F e^{3 +} + S O_{2} + 2 H_{2} O \to$
$2 F e^{2 +} + 4 H^{+} + {S O}_{4}^{2 -}$
$S O_{2} + Ba {(OH)}_{2} \to BaS O_{3} + H_{2} O$
So, $Ba ({OH}_{2})$ cannot oxidise ${SO}_{2}$ to ${SO}_{4}^{- 2}$

CHXI11:THE P-BLOCK ELEMENTS

317011 Bromine water reacts with ${SO}_{2}$ to form

1

HBr

and

S

2

H_{2} O

and

HBr

3

S

and

H_{2} O

4

H_{2} {SO}_{4}

and

HBr

Explanation:

When bromine water reacts with ${SO}_{2}$ , it oxidises ${SO}_{2}$ to sulphuric acid and itself gets reduced to $HBr$ .
supporting img

CHXI11:THE P-BLOCK ELEMENTS

317012 On passing ${SO}_{2}$ gas through cupric chloride solution

1 The solution becomes colourless only

2 The solution becomes colourless first and later a white ppt. of

{Cu}_{2} {Cl}_{2}

is formed.

3 No visible change takes place.

4 A white ppt. is not obtained.

Explanation:

${CuCl}_{2} + 2 H_{2} O + {SO}_{2}$
${Cu}_{2} {Cl}_{2} + 2 HCl + H_{2}$

CHXI11:THE P-BLOCK ELEMENTS

317013 How many of the following statements are CORRECT?
i. ${SO}_{2}$ is produced by the action of hydrochloric acid on ${Na}_{2} {SO}_{3}$ .
ii. ${SO}_{2}$ is ${sp}^{2}$ hybridized.
iii. ${SO}_{2}$ has two $p π - p π$ bonds.
iv. ${SO}_{2}$ and ${CS}_{2}$ are isostructural.

1 1

2 2

3 3

4 4

Explanation:

Statements (i) and (ii) are correct. ${SO}_{2}$ has two $π$ bonds; one is $p π - p π$ and the other is $d π - p π$ . ${SO}_{2}$ and ${CS}_{2}$ are not isostructural. ${SO}_{2}$ is bent while ${CS}_{2}$ is linear.

CHXI11:THE P-BLOCK ELEMENTS

317014 Which of the following reaction cannot change ${SO}_{2} \to {SO}_{4}^{2 -} ?$

1

{SO}_{2} + {MnO}_{4}^{-} \overset{H^{+}}{\to}

2

{SO}_{2} + {Cr}_{2} O_{7}^{2 -} \overset{H^{+}}{\to}

3

{SO}_{2} + {Fe}^{3 +} \overset{H^{+}}{\to}

4

{SO}_{2} + Ba (OH)_{2} \to

Explanation:

$2 {MnO}_{4}^{-} + 5 {SO}_{2} + 2 H_{2} O ⟶$
$2 M n^{2 +} + 5 {S O}_{4}^{2 -} + 4 H^{+}$
$C r_{2} O_{7}^{2 -} + 3 S O_{2} + 2 H^{+} \to$
$2 C r^{3 +} + 3 {S O}_{4}^{2 -} + H_{2} O$
$2 F e^{3 +} + S O_{2} + 2 H_{2} O \to$
$2 F e^{2 +} + 4 H^{+} + {S O}_{4}^{2 -}$
$S O_{2} + Ba {(OH)}_{2} \to BaS O_{3} + H_{2} O$
So, $Ba ({OH}_{2})$ cannot oxidise ${SO}_{2}$ to ${SO}_{4}^{- 2}$

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